GIÚP MÌNH VỚI TÝ MÌNH NỘP R
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3,5 = \(\frac{6}{10}\)
Vậy ta có phép tính 2/3 x 6/10
Chỗ này dễ quá và quen thuộc, bạn tự giải đi nha!
Nhớ tích nhớ!
1. He works the most effectively in my company
-> No one in my company works as effectively as him.
2. We didn't go to the theatre. We had a lot of work to do
-> Because we had a lot of work to do, we didn't go to the theater.
3. You’ll hurt yourself if you aren’t careful.
-> Unless you are careful, you will hurt yourself.
4. Many people have visited the exhibition
-> The exhibition has been visited by many people.
5. John began playing the piano ten years ago
-> John hasn’t played the piano for 10 years.
6. The man can't find the stolen car
-> The stolen car can't be found.
7. They have invented a new kind of medicine
-> A new kind of medicine has been invented.
8. Man will solve the problem of pollution in the future
-> The problem of pollution will be solved in the future by man.
9. Your son paid less attention to his study, didn’t he?
-> Did your son pay less attention to his study.
10. Living in the city is more convenient than living in the country
-> Living in the country isn’t as convenient as living in the country.
A D B C a b 1 1 1 M N 1 1 c 2 2 2
a) Ta có \(\widehat{B_1}+\widehat{ABC}=180^o\)( 2 góc kề bù )
\(\Rightarrow70^o+\widehat{ABC}=180^o\)\(\Leftrightarrow\widehat{ABC}=110^o\)mà \(\widehat{C_1}=110^o\)
\(\Rightarrow\widehat{ABC}=\widehat{C_1}\)mà \(\widehat{ABC}\text{ và }\widehat{C_1}\)là 2 góc đồng vị
=> a // b
b) Vì \(\hept{\begin{cases}a//b\left(\text{ phần a}\right)\\c⊥b\end{cases}}\Rightarrow c⊥a\Rightarrow\widehat{A_1}=90^o\)
c) Ta có : \(\widehat{B_1}=\widehat{C_2}\)( 2 góc so le trong )\(\Rightarrow\widehat{C_2}=70^o\)
Lại có tia phân giác của \(\widehat{ABC}\)tạo ra \(\widehat{B_2}=\frac{\widehat{ABC}}{2}=\frac{110^o}{2}=55^o\)
Mà \(\widehat{N_2}\)là góc ngoài của ∆NBC \(\Rightarrow\widehat{N_2}=\widehat{B_2}+\widehat{C_2}=70^o+55^o=125^o\)
Lại có : \(\hept{\begin{cases}\widehat{N_1}+\widehat{N_2}=180^o\left(\text{2 góc kề bù }\right)\\\widehat{N_2}=\widehat{D_2}+\widehat{M_1}\left(\text{do }\widehat{N_2}\text{ là góc ngoài của }∆DMN\right)\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}\widehat{N_1}+125^o=180^o\\\widehat{M_1}=\widehat{N_2}-\widehat{D_2}\end{cases}}\)\(\Rightarrow\hept{\begin{cases}\widehat{N_1}=180^o-125^o\\\widehat{M_1}=125^o-90^o\end{cases}}\)\(\Rightarrow\hept{\begin{cases}\widehat{N_1}=55^o\\\widehat{M_1}=35^o\end{cases}}\)