- There are a desk, an armchair, two computers and a printer in my father's working room.

- My father has a desk, an armchair, two computers and a printer in his working room.

\(MSC:30\\ \dfrac{3}{5}=\dfrac{3\times6}{5\times6}=\dfrac{18}{30}\\ \dfrac{7}{6}=\dfrac{7\times5}{6\times5}=\dfrac{35}{30}\\ 18< 35\\ =>\dfrac{3}{5}< \dfrac{7}{6}\)

\(\dfrac{3}{5}< 1< \dfrac{7}{6}\)

my / living / next / room / room / is / to / the / but / far / bathroom / from / the.
=> Answer:
The living room is next to my room but far from the bathroom.
HOẶC
The living room is next to the bathroom but far from my room.

#hoctot
 

KO BIẾT

\(\left(x-3\right)\left(x^2-2\right)-2\left(x-3\right)=0\\ =>\left(x-3\right)\left(x^2-2-2\right)=0\\ =>\left(x-3\right)\left(x^2-4\right)=0\\ \Rightarrow\left[{}\begin{matrix}x-3=0\\x^2-4=0\end{matrix}\right.=>\left[{}\begin{matrix}x=3\\x^2=4\end{matrix}\right.\\ =>\left[{}\begin{matrix}x=3\\x=2\\x=-2\end{matrix}\right.\)

U = 1 . 2 + 1 . 3 + 2 . 2 + 2 . 3 + ... + 99 . 2 + 99 . 3

    = ( 1 . 2 + 2 . 2 + ... + 99 . 2 ) + ( 1 . 3 + 2 . 3 + ... + 99 . 3 )

    = 2( 1 + 2 + ... + 99 ) + 3( 1 + 2 + ... + 99 )

    = 5( 1 + 2 + ... + 99 ) 

Đặt A = 1 + 2 + ... + 99

Số số hạng của tổng A là ( 99 - 1 ) : 1 + 1 = 99 ( số hạng )

A = ( 99 + 1 ) . 99 : 2 = 4950

U = 5 . 4950 = 24750

Vậy U = 24750

\(2^2.85+40.2^2-2^3\)

\(=2^2.85+40.2^2-2^2.2\)

\(=2^2.\left(85+40-2\right)\)

\(=2^2.123\)

\(=492\)

\(2^{2}.85+40.2^{2}-2^{3}\)

\(=2^{2}.85+40.2^{2}-2^{2+1}\)

\(=2^{2}.85+40.2^{2}-2^{2}.2^{1}\)

\(=2^{2}.(85+40-2)\)

\(=4.123\)

\(=492\)

có nhé

Tùy ạ. Bởi vì nếu điểm tb  bạn dưới 6,5 thì chắc là sẽ ko đc hsg đâu. Còn nếu đtb > 6,5 thì chắc là đc .