chơi nhau à

có cc=)))

a. ta có \(3^{102}=3^{3\times34}=27^{34}>25^{34}=5^{2\times34}=5^6\text{ vậy }3^{102}>5^{68}\)

b. ta có \(C=1+2+..+2^{2017}\text{ nên }2C=2+2^2+...+2^{2018}\)

lấy hiệu ta có : \(C=\left(2+2^2+..+2^{2018}\right)-\left(1+2+..+2^{2017}\right)=2^{2018}-1< 2^{2018}\)

Vậy \(C< 2^{2018}\)

c. dễ thấy \(C>\frac{1}{2}=F\)

d. ta có \(5G=1+\frac{1}{5}+..+\frac{1}{5^{2016}}\Rightarrow4G=1-\frac{1}{5^{2017}}\)hay \(G=\frac{1}{4}-\frac{1}{4\times5^{2017}}< \frac{1}{4}=H\text{ hay }G< H\)

dài quá :>

\(2,5-\left(-\frac{16}{2021}\right)^0+\left(-\frac{1}{3}\right)^2\div\left(-3\right)\)

\(=2,5-1+\frac{1}{9}\div\left(-3\right)\)

\(=2,5-1+\frac{1}{27}\)

\(=1,5+\frac{1}{27}\)

\(=\frac{83}{54}\)

=2,5+1-1/9:(-3)

=2,5+1+1/27

=3,5+1/27

=191/54

\(x=\frac{7}{2};1\)

x = 7/2;1

~~~~~~~~~~~~~~~~HOK TOT~~~~~~~~~~~~~~~~

\(\left(\frac{1}{3}-\frac{1}{3}\right)+\left(\frac{3}{5}-\frac{3}{5}\right)+\left(\frac{7}{9}-\frac{7}{9}\right)+\left(\frac{9}{11}-\frac{9}{11}\right)+\left(\frac{11}{13}-\frac{11}{13}\right)+\frac{13}{15}\)

\(=0+\frac{13}{15}\)

\(=\frac{13}{15}\)

eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

\(\left(\frac{1}{2}\right)^{2n-1}=\frac{1}{8}\)

\(\left(\frac{1}{2}\right)^{2n-1}=\left(\frac{1}{2}\right)^3\)

\(\Rightarrow2n-1=3\)

\(2n=3+1\)

\(2n=4\)

\(\Rightarrow n=2\)

\(\left(\frac{1}{2}\right)^{2n-1}=\left(\frac{1}{2}\right)^3\)

2n-1=3

2n=4

n=2