8/9-1/72-1/56-1/42-...-1/6-1/2
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Tìm Min à bạn?
\(Q=\left|x-2\right|+\left|x-5\right|+\left|x+1\right|\)
\(=\left|x-2\right|+\left|5-x\right|+\left|x+1\right|\)
\(=\left(\left|x-2\right|+\left|x-5\right|\right)+\left|x+1\right|\)
\(=\left(\left|2-x+5-x\right|\right)+\left|x+1\right|\)
\(=\left|3\right|+\left|x+1\right|=\left|3+x+1\right|=\left|x+4\right|\)
Mà \(\left|x+4\right|\ge0\forall x\Rightarrow MinQ=0\)
Dấu '' = '' xảy ra khi \(x+4=0\Leftrightarrow x=-4\)
\(P=\left|x+1\right|+\left|x+2\right|+\left|x+3\right|\)
\(=\left(\left|x+1+x+2\right|\right)+\left|x+3\right|\)
\(=\left(\left|2x+3\right|+\left|x+3\right|\right)\)
\(=\left|2x+3+x+3\right|\)
\(=\left|3x+6\right|\ge0\)
Dấu '' = '' xảy ra khi \(3x+6=0\Rightarrow3x=-6\Rightarrow x=-2\)
Đặt đại 1 cái tên kk
\(N=\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{100.103}\)
\(\Rightarrow3N=3\left(\frac{1}{1.4}+\frac{1}{4.7}+...+\frac{1}{100.103}\right)\)
\(\Rightarrow3N=\frac{3}{1.4}+\frac{3}{4.7}+...+\frac{3}{100.103}\)
\(\Rightarrow3N=\frac{1}{1}-\frac{1}{4}+...+\frac{1}{100}-\frac{1}{103}\)
\(\Rightarrow3N=\frac{1}{1}-\frac{1}{103}\)
\(\Rightarrow N=\frac{102}{103}:3\)
\(\Rightarrow N=\frac{34}{103}\)
\(\frac{8}{9}-\frac{1}{72}-\frac{1}{56}-\frac{1}{42}-...-\frac{1}{6}-\frac{1}{2}\)
\(\Rightarrow\frac{8}{9}-\left(\frac{1}{72}+\frac{1}{56}+\frac{1}{42}+...+\frac{1}{6}+\frac{1}{2}\right)\)
\(\Rightarrow\frac{8}{9}-\left(\frac{1}{9.8}+\frac{1}{8.7}+\frac{1}{7.6}+...+\frac{1}{3.2}+\frac{1}{2.1}\right)\)
\(\Rightarrow\frac{8}{9}-\left(\frac{1}{9}-\frac{1}{8}+\frac{1}{8}-\frac{1}{7}+...+\frac{1}{2}-1\right)\)
\(\Rightarrow\frac{8}{9}-\left(1-\frac{1}{9}\right)\)
\(\Rightarrow0\)