cho các số x y thỏa mãn x + y = 3 tính giá trị biểu thức a = x mũ 3 + x mũ 2 y - 3 x mũ 2 + x y + y mũ 2 - 4y - x + 3
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a, 3x(x-1)=3x^2+9
\(\Leftrightarrow\)3x(x-1)-3x^2=9
\(\Leftrightarrow\)3x^2-3x-3x^2=9
\(\Leftrightarrow\)-3x=9
\(\Leftrightarrow\)x=9:(-3) \(\Leftrightarrow\)x=-3
3x ( x - 1 ) = 3x2 + 9
<=> 3x2 - 3x - 3x2 - 9 = 0
<=> - 3x - 9 = 0
<=> x = - 3
2x ( 1 - x ) - 6 ( x - 1 ) = 0
<=> 2x ( 1 - x ) + 6 ( 1 - x ) = 0
<=> ( 2x + 6 ) ( 1 - x ) = 0
<=> 2x + 6 = 0 hoặc 1 - x = 0
<=> x = - 3 hoặc x = 1
( 2x - 3 )2 - ( x + 1 ) = 0
<=> 4x2 - 12x + 9 - x - 1 = 0
<=> 4x2 - 13x + 8 = 0
<=> ( 4x2 - 13x + 169/16 ) - 41/16 = 0
<=> 4 ( x2 - 13x/4 + 169/64 ) = 41/16
<=> ( x - 13/8 )2 = 41/64
<=>\(\orbr{\begin{cases}x-\frac{13}{8}=\frac{\sqrt{41}}{8}\\x-\frac{13}{8}=-\frac{\sqrt{41}}{8}\end{cases}}\) <=> \(\orbr{\begin{cases}x=\frac{13+\sqrt{41}}{8}\\x=\frac{13-\sqrt{41}}{8}\end{cases}}\)
a) 5x( x - 1 ) + ( x - 4 )( x + 4 )
= 5x2 - 5x + x2 - 16
= 6x2 - 5x - 16
b) ( x - 2y )2 + ( x3 + 3x2y + 3xy2 + y3 ) : ( x + y )
= x2 - 4xy + 4y2 + ( x + y )3 : ( x + y )
= x2 - 4xy + 4y2 + ( x + y )2
= x2 - 4xy + 4y2 + x2 + 2xy + y2
= 2x2 - 2xy + 5y2
\(\frac{x+1}{2014}+\frac{x+2}{2013}+\frac{x+3}{2012}+\frac{x+4}{2011}+\frac{x+2023}{2}=0\)
\(\left(\frac{x+1}{2014}+1\right)+\left(\frac{x+2}{2013}+1\right)+\left(\frac{x+3}{2012}+1\right)+\left(\frac{x+2011}{4}+1\right)+\left(\frac{x+2023}{2}-4\right)=0\)
\(\frac{x+2015}{2014}+\frac{x+2015}{2013}+\frac{x+2015}{2012}+\frac{x+2015}{2011}+\frac{x+2015}{2}=0\)
\(\left(x+2015\right)\left(\frac{1}{2014}+\frac{1}{2013}+\frac{1}{2012}+\frac{1}{2011}+\frac{1}{2}\right)=0\)
Vì \(\frac{1}{2014}+\frac{1}{2013}+\frac{1}{2012}+\frac{1}{2011}+\frac{1}{2}\ne0\)
nên \(x+2015=0\)
\(\Rightarrow x=-2015\)
Vậy \(x=-2015\).
x5 + 1 - x3 - x2
= ( x5 - x3 ) - ( x2 - 1 )
= x3 ( x2 - 1 ) - ( x2 - 1 )
= ( x3 - 1 ) ( x2 - 1 )
= ( x - 1 ) ( x2 + x + 1 ) ( x - 1 ) ( x + 1 )
= ( x - 1 )2 ( x2 + x + 1 ) ( x + 1 )
x^5+1-x^3-x^2
=(x^5-x^2)-(x^3-1)
=x^2(x^3-1)-(x^3-1)
=(x^2-1)(x^3-1)
=(x-1)(x+1)(x-1)(x^2+x+1)
=(x-1)^2(x+1)(x^2+x+1)
kĩ nhất rồi đấy =')
(16-4x).(x+3)-(x+1).(3-4x)=40
=>16x-4x^2+48-12x-3x-3+4x^2+4x=40
=>x=40-48+3
=>x=-5
(16-4x).(x+3)-(x+1).(3-4x)=40
=>16x-4x^2+48-12x-3x-3+4x^2+4x=40
=>5x=40-48+3
=>5x=-5
=>x=-1
câu x=-5 sai .-.
a)x(x-1)-x(x-3)=0
=>x^2-x-x^2+3x=0
=>-x+3x=0
=>x=0
b)2x^2+2x+1/2=0
=>2(x^2+x+1/4)=0
=>(x+1/2)^2=0
=>x+1/2=0
=>x=-1/2