Bài 1:
a, \(A=\frac{1}{4}:\left(10,3-9,8\right)-\frac{3}{4}\)
b, \(B=\frac{6}{7}+\frac{5}{8}:5-\frac{3}{16}.\left(-2\right)^2\)
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\(34\%:\frac{51}{16}-\frac{34}{9}:6,5-\left(0,4\right)^2\)
\(=\frac{34}{100}:\frac{51}{16}-\frac{34}{9}:\frac{65}{10}-0,16\)
\(=\frac{34\cdot16}{100\cdot51}-\frac{34\cdot10}{9\cdot65}-\frac{16}{100}\)
\(=\frac{2\cdot17\cdot4\cdot4}{4\cdot5\cdot5\cdot17\cdot3}-\frac{2\cdot17\cdot2\cdot5}{3\cdot3\cdot5\cdot13}-\frac{4}{25}\)
\(=\frac{8}{75}-\frac{34}{117}-\frac{4}{25}=\left(\frac{8}{75}-\frac{4}{25}\right)-\frac{34}{117}\)
\(=\left(\frac{8}{75}-\frac{12}{75}\right)-\frac{34}{117}=\frac{-4}{75}-\frac{34}{117}\)
\(34\%\div\frac{51}{16}-\frac{34}{9}\div\frac{6}{5}-\left(0,4\right)^2\)
\(=\frac{34}{100}\times\frac{16}{51}-\frac{34}{9}\times\frac{5}{6}-0,16\)
\(=\frac{17}{50}\times\frac{16}{51}-\frac{85}{27}-\frac{16}{100}\)
\(=\frac{8}{75}-\frac{85}{27}-\frac{4}{25}\)
\(=\frac{8}{75}-\frac{85}{27}-\frac{12}{75}\)
\(=\frac{-4}{75}-\frac{85}{27}\)
\(=\frac{-108}{2025}-\frac{6375}{2025}\)
\(=\frac{-6483}{2025}\)
b)\(\frac{2n+6}{n-2}=\frac{2n-4+10}{n-2}=2+\frac{10}{n-2}\)
\(\Rightarrow n-2\in U\left(10\right)=\left\{1;2;5;10\right\}\)
\(\Rightarrow n=\left\{3;4;7;12\right\}\)
ý a thì tớ ko biết ý b thì làm như sau
2[n-2]+4+6
2[n-2]+10
n-2/n-2
10/[n-2]
Ư[10]=[1,-1,2,-2,5,-5,10,-10]
vì n-2 thuộc Ư[10]=[3,1,4,0,7,-3,12,-8]
[3,1,4,0,7,-3,12,-8] đó là kết quả chúcbanjk học tốt
NHỚ NHA
Ta có: \(\frac{6n+3}{3n+6}=\frac{6n+12-9}{3n+6}=\frac{2\left(6n+3\right)-9}{3n+6}=2-\frac{9}{3n+6}\)
Để 6n+3 chia hết cho 3n+6. thì 9 chia hết cho 3n+6
=> 3n+6\(\in\)Ư(9)
=> 3n+6 \(\in\){1,3,9}
=> 3n = 3
=> n = 3:3
=> n = 1
(1x1/2)x(1x1/3)x(1x1/4)...(1x1/2007)
=1/2x1/3x1/4...1/2007
=1/(2x3x4...2007)
=???
\(\frac{3}{4}+\frac{1}{4}:x=\frac{1}{2}\)
\(\frac{1}{4}:x=\frac{1}{2}-\frac{3}{4}\)
\(\frac{1}{4}:x=-\frac{1}{4}\)
\(x=\frac{1}{4}:\left(-\frac{1}{4}\right)\)
\(x=-1\)
~Học tốt~
\(\frac{3}{4}+\frac{1}{4}:x=\frac{1}{2}\)
\(\frac{1}{4}:x=\frac{1}{2}-\frac{3}{4}\)
\(\frac{1}{4}:x=\frac{-1}{4}\)
\(x=\frac{1}{4}:\frac{-1}{4}\)
\(x=-1\)
Gọi phân số đó là \(\frac{a}{9}\)
Ta có :
\(\Rightarrow\frac{a+10}{27}=\frac{3a}{27}\)
\(\Rightarrow\)a + 10 = 3a
\(\Rightarrow\) 3a - a = 10
\(\Rightarrow\)2a = 10
\(\Rightarrow\)a = 5
Vậy phân số cần tìm là \(\frac{5}{9}\)
\(A=\frac{1}{4}:\left(10,3-9,8\right)-\frac{3}{4}\)
\(A=\frac{1}{4}:\left(0,5\right)-\frac{3}{4}\)
\(A=\frac{1}{4}:\frac{1}{2}-\frac{3}{4}\)
\(A=\frac{1}{4}\cdot2-\frac{3}{4}=\frac{1}{2}-\frac{3}{4}=\frac{2}{4}-\frac{3}{4}=\frac{-1}{4}\)
Bài 1:
a, \(A=\frac{1}{4}:0,5-\frac{3}{4}\)
\(=\frac{1}{2}-\frac{3}{4}\)
\(=\frac{-1}{4}\)
b, \(B=\frac{6}{7}+\frac{5}{8}:5-\frac{3}{16}.\left(-2\right)^2\)
\(=\frac{6}{7}+\frac{1}{8}-\frac{3}{4}\)
\(=\frac{6}{7}+\frac{-5}{8}\)
\(=\frac{13}{56}\)
Hk tốt