-3/7+(3–3/4)–(-2,25–10/7)
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\(-2,25-\dfrac{10}{7}\)
\(=\dfrac{-9}{4}-\dfrac{10}{7}\)
\(=\dfrac{-63}{28}-\dfrac{40}{28}\)
\(=\dfrac{-103}{28}\)
My favourite hobby is reading; therefore I have collected various types of books. I started reading fairy tales when I was four years old. At the first time, I was interesting in colorful pictures with meaningful contents. When reading a story with a happy ending, I felt very happy. Reading books brings me a lot of benefit. Firstly, it makes me relaxed and calmed. After a hard-working day, I can relieve stress by reading a funny story. I also learn new vocabulary items. Then I can further improve my English. Moreover, it can give me an unlimited imagination, so I can write books in the future. I can learn the different cultures and customs of other countries in the world too. I read books at least one hour every day. I wish I could read different kinds of books because it might be very challenging.
Bước 1: Bật máy casio
Bước 2: nhập số 1,5
Bước 3: nhấn alpha
Bước 4: nhấn \(\sqrt{ }\)
Bước 5: nhập chu kỳ vào trong dấu ngoặc
Bước 6: nhấn = khi đó ta được
1,5(68) = \(\dfrac{1553}{990}\)
Hello. I am Lilith, a teacher at Oxford University. People say I am the best at this school, and I hope you all support me!
Giải:
Thời gian ô tô xuất phát trước xe khách là: 10 giờ - 7 giờ = 3 giờ
Khi xe khách xuất phát ô tô cách xe khách là: 30 x 3 = 90 (km/h)
Hai xe gặp nhau sau: 90 : (60 - 30) = 3 (giờ)
Lúc gặp nhau cách A là: 60 x 3 = 180 (km)
Lúc gặp nhau cách B là: 230 - 180 = 50 (km)
Kết luận: Hai xe gặp nhau sau 3 giờ
Vị trí gặp nhau cách A là 180 km, cách B là 50 km
10 Who did she go to visit in the hospital?
11 What is his favorite hobby?
\(\dfrac{-3}{7}+\left(3-\dfrac{3}{4}\right)-\left(-2,25-\dfrac{10}{7}\right)\)
\(=\dfrac{-3}{7}+\left(3-\dfrac{3}{4}\right)-\left(-\dfrac{9}{4}-\dfrac{10}{7}\right)\)
\(=\dfrac{-3}{7}+\left(\dfrac{12}{4}-\dfrac{3}{4}\right)-\left(-\dfrac{63}{28}-\dfrac{40}{28}\right)\)
\(=\dfrac{-3}{7}+\dfrac{9}{4}-\left(\dfrac{-103}{28}\right)\)
\(=\dfrac{-12}{28}+\dfrac{63}{28}-\left(\dfrac{-103}{28}\right)\)
\(=\dfrac{51}{28}-\left(\dfrac{-103}{28}\right)\)
\(=\dfrac{51}{28}+\dfrac{103}{28}\)
\(=\dfrac{154}{28}\)
\(=\dfrac{11}{2}\)
\(-\dfrac{3}{7}+\left(3-\dfrac{3}{4}\right)-\left(-2,25-\dfrac{10}{7}\right)\)
\(=-\dfrac{3}{7}+3-\dfrac{3}{4}+2,25+\dfrac{10}{7}\)
\(=\left(-\dfrac{3}{7}+\dfrac{10}{7}\right)+\left(3-\dfrac{3}{4}+2,25\right)\)
\(=\left(-\dfrac{3}{7}+\dfrac{10}{7}\right)+\left(\dfrac{12}{4}-\dfrac{3}{4}+\dfrac{9}{4}\right)\)
\(=1+\dfrac{18}{4}\)
\(=\dfrac{22}{4}\)