D= 1/1x5 + 1/5x9 + 1/9x15 + ...+ 1/21×25
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3/(x - 7) = 27/135
3 × 135 = (x - 7) × 27
(x - 7) × 27 = 405
x - 7 = 405 : 27
x - 7 = 15
x = 15 + 7
x = 22
\(\dfrac{3}{x-7}=\dfrac{27}{135}\)
\(27\times\left(x-7\right)=3\times135\)
\(27\times x-189=405\)
\(27\times x=405+189\)
\(27\times x=594\)
\(x=594\div27\)
\(x=22\)
\(72\cdot\dfrac{1}{2}\cdot85-6:\dfrac{1}{6}\cdot20+18\cdot70\)
\(=\dfrac{2\cdot36\cdot85}{2}-6\cdot6\cdot20+1260\)
\(=3060-720+1260\)
\(=3600\)
a) \(\dfrac{5}{6}+\dfrac{3}{2}\cdot\dfrac{4}{5}\)
\(=\dfrac{5}{6}+\dfrac{3\cdot2\cdot2}{2\cdot5}\)
\(=\dfrac{5}{6}+\dfrac{6}{5}\)
\(=\dfrac{61}{30}\)
b) \(\dfrac{6}{7}:\dfrac{9}{14}-1\)
\(=\dfrac{6}{7}\cdot\dfrac{14}{9}-1\)
\(=\dfrac{2\cdot3\cdot7\cdot2}{7\cdot3\cdot3}-1\)
\(=\dfrac{4}{3}-1\)
\(=\dfrac{1}{3}\)
a) \(\dfrac{5}{6}+\dfrac{3}{2}.\dfrac{4}{5}=\dfrac{5}{6}+\dfrac{6}{5}=\dfrac{61}{30}\)
b) \(\dfrac{6}{7}:\dfrac{9}{14}-1=\dfrac{4}{3}-1=\dfrac{1}{3}\)
\(D=\dfrac{1}{1\cdot5}+\dfrac{1}{5\cdot9}+...+\dfrac{1}{21\cdot25}\)
\(4D=\dfrac{4}{1\cdot5}+\dfrac{4}{5\cdot9}+...+\dfrac{4}{21\cdot25}\)
\(4D=1-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{9}+...+\dfrac{1}{21}-\dfrac{1}{25}\)
\(4D=1-\dfrac{1}{25}=\dfrac{24}{25}\)
\(D=\dfrac{24}{25}\cdot\dfrac{1}{4}=\dfrac{4\cdot6}{25\cdot4}=\dfrac{6}{25}\)