Cứu vs 4 mũ 10 : 2 mũ 5
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125: (2\(x\) - 3\(x\)) = 55: 53
125: (-\(x\)) = 25
\(x\) = - 125 : 25
\(x\) = - 5
\(\left(3\cdot x-16\right)\cdot7^3=2\cdot7\)
\(\Rightarrow3\cdot x-16=\dfrac{2\cdot7}{7^3}\)
\(\Rightarrow3\cdot x-16=\dfrac{2}{7^2}\)
\(\Rightarrow3\cdot x-16=\dfrac{2}{49}\)
\(\Rightarrow3\cdot x=\dfrac{2}{49}+16\)
\(\Rightarrow3\cdot x=\dfrac{786}{49}\)
\(\Rightarrow x=\dfrac{786}{49}:3\)
\(\Rightarrow x=\dfrac{262}{49}\)
\(\left(3x-16\right)\cdot7^3=2\cdot7\)
\(\left(3x-16\right)\cdot343=14\)
\(1029x-5488=14\)
\(1029x=14+5488=5502\)
\(x=\dfrac{5502}{1029}=\dfrac{262}{49}\)
\(201^{60}=\left(201^4\right)^{15}=1944810000^{15}\)
\(398^{45}=\left(398^3\right)^{15}=63044792^{15}\)
Do \(1944810000>63044792\)
\(\Rightarrow1944810000^{15}>63044792^{15}\)
\(\Rightarrow201^{60}>398^{45}\)
Ta có:
\(201^{60}>200^{60};398^{45}< 400^{45}\)
\(200^{60}=\left(2.100\right)^{60}=2^{60}.100^{60}=2^{60}.\left(10^2\right)^{60}\)
\(=2^{60}.10^{120}=2^{60}.10^{30}.10^{90}\)
\(400^{45}=\left(2.100\right)^{45}=2^{45}.100^{45}=2^{45}.\left(10^2\right)^{45}\)
\(=2^{45}.10^{90}\)
Mà \(2^{60}.10^{30}.10^{90}>2^{45}.10^{90}\)
\(\Rightarrow200^{60}>400^{45}\)
\(\Rightarrow201^{60}>200^{60}>400^{45}>398^{45}\)
\(\Rightarrow201^{60}>398^{45}\)
\(2\left[\left(7-3^{2021}:3^{2020}\right):2^2+99\right]-100\)
\(=2\left[\left(7-3^{2021-2020}\right):4+99\right]-100\)
\(=2\left[\left(7-3\right):4+99\right]-100\)
\(=2\left(4:4+99\right)-100\)
\(=2\left(1+99\right)-100\)
\(=2\cdot100-100\)
\(=100\cdot\left(2-1\right)\)
\(=100\)
2mũ8
Nhầm 2mũ 5 mới đúng