xin loi minh ko biet nha bnxin loi minh ko biet nha bn

xin loi minh ko biet nha bn

xin loi minh ko biet nha bn

xin lỗi mình ko bik

xin lỗi minh ko bik

xin lỗi mik kobik

ax(x-y)+y^3(x+y)

=a.(-1)(-1+1)+1^3(-1+1)

=(-a).0+1.0

=0

Khó quá

Kho vay ban

Vâng, có ai giúp được k ạ =(((

b)x^3 - 6x^2 +11x-6=0

<=>x^3 - x^2 - 5x^2 +5x + 6x - 6=0

<=>x^2(x - 1) - 5x(x - 1) +6(x - 1)=0

<=>(x-1).(x^2 - 5x + 6)=0

<=>(x - 1).(x^2 - 2x - 3x + 6)=0

<=>(x - 1).[(x(x-2)-3(x-2)]=0

<=>(x-1)(x-2)(x-3)=0

<=>x-1=0hoac x-2=0 hoac x-3=0

<=>x=1hoac x=2 hoac x=3

bạn mua cái máy tính vinacal xog giải nghiệm ra hết thui

4+2x(2x+4)=-x

4+4x^2+8x=-x

4x^2+8x+x+4=0

4x^2+9x+4=0

Ban tu phan h ra nua la xong nhe.

Chuyen thanh phuong trinh h nhe ban.

x^2-x-2=0

x^2-2x+x-2=0

x(x-2)+(x-2)=0

(x+1)(x-2)=0

\(\Rightarrow\hept{\begin{cases}x+1=0\\x-2=0\end{cases}\Rightarrow\hept{\begin{cases}x=-1\\x=2\end{cases}}}\)

(4-x)(2-x)=2(4-x)

8-4x-2x+x^2=8-2x

8-8-4x-2x+2x+x^2=0

-4x+x^2=0

x(-4+x)=0

\(\Rightarrow\hept{\begin{cases}x=0\\-4+x=0\end{cases}\Rightarrow\hept{\begin{cases}x=0\\x=4\end{cases}}}\)

(4 - x)(2 - x) = 2.(4 - x)

2 - x = 2.(4 - x) : (4 - x)

2 - x = 2

x = 2 - 2 

x = 0

x^3-x=x^2+x

x^3-x^2-x-x=0

x^3-x^2-2x=0

x^3-2x^2+x^2-2x=0

x^2(x-2)+x(x-2)=0

(x-2)(x^2+x)=0

x(x-2)(x+1)=0

Th1 : x=0

Th2 : x-2=0=>x=2

Th3 : x+1=0=>x=-1