121212/161616 - (151515/323232 - x ) = 2
x/2 + x/ 6 + x/12 + x/20 + x/30 + x/42 + x/56 + x/72 + x/90 = 9/5
giải giúp mik với mai mik phải nộp bài rồi xong trình bày bài rồi mik kick cho
Thank You
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\(43.27+93.43+57.61+59.57\)
\(=\left(43.27+93.43\right)+\left(57.61+59.57\right)\)
\(=43\left(27+93\right)+57\left(61+59\right)\)
\(=43.120+57.120\)
\(=120\left(43+57\right)\)
\(=120.100\)
\(=12000\)
Học tốt
43.27+93.43+57.61+59.57=43(27+93)+57(61+59)=43.120+57.120=120(43+57)=120.100=12000
Chúc bạn học tốt
1.plays volleyball Ex2.
2.gets up 1.No, she doesn't
3.watches 2.Does she get......
4.( bạn ghi nhầm thành 5) 3.Does she go....
5.washes No, she doesn't. She goes to the park every Sunday
6.does
Bạn nhớ kiểm tra lại nhé
1.Zoe.....................every Friday plays volleyball
2.She...........................at eleven o'clock every Sunday gets up
3.She..........................Tv every Friday watches
5.He....................................his dad's car every Saturday washes
6.He...................................his homework every Sunday does
2 Look at exercise 1. Write questions and answers.
1.Does Zoe play volleyball Everyday?
No , she doesn't
2..............she...................at seven o'clock every Saturday? Does / go to the park
No , she doesn't
3...............to the cinema every Sunday? Does she go
No, she doesn't.
Bài làm:
Ta có: \(A=\frac{5}{4}\div\frac{a}{a+1}=\frac{5}{4}.\frac{a+1}{a}=\frac{5a+5}{4a}\)
\(\Rightarrow4A=\frac{20a+20}{4a}=5+\frac{5}{a}\)
Để 4A là số nguyên
=> \(\frac{5}{a}\inℤ\Rightarrow5⋮a\Rightarrow a\inƯ\left(5\right)=\left\{\pm1;\pm5\right\}\)
Thử lại để A là số nguyên thì \(a\in\left\{-5;-1\right\}\)
a) Ta có\(\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+...+\frac{2}{110}=\frac{2}{2.3}+\frac{2}{3.4}+\frac{2}{4.5}+...+\frac{2}{10.11}\)
\(=2\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{10.11}\right)=2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{10}-\frac{1}{11}\right)\)
\(=2\left(\frac{1}{2}-\frac{1}{11}\right)=1-\frac{2}{11}=\frac{9}{11}\)
b) Ta có \(1-\frac{1}{2}-\frac{1}{4}-\frac{1}{8}-...-\frac{1}{2048}=1-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{2048}\right)\)(1)
Đặt S = \(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{1024}+\frac{1}{2048}\)
=> \(2S=1+\frac{1}{2}+\frac{1}{4}+...+\frac{1}{1024}\)
Lấy 2S trừ S ta có :
2S - S \(=\left(1+\frac{1}{2}+\frac{1}{4}+...+\frac{1}{1024}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{1024}+\frac{1}{2048}\right)\)
\(S=1-\frac{1}{2048}\)
Khi đó (1) <=> \(1-\left(1-\frac{1}{2048}\right)=1-1+\frac{1}{2048}=\frac{1}{2048}\)
\(a,\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+\frac{2}{30}+....+\frac{2}{90}+\frac{2}{110}\)
\(=2.\left(\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+.....+\frac{1}{90}+\frac{1}{110}\right)\)
\(=2.\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+....+\frac{1}{9.10}+\frac{1}{10.11}\right)\)
\(=2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-....+\frac{1}{9}-\frac{1}{10}+\frac{1}{10}-\frac{1}{11}\right)\)
\(=2\left(\frac{1}{2}-\frac{1}{11}\right)\)
\(=1-\frac{2}{11}\)
\(=\frac{9}{11}\)
Last year my brother spent his holiday in Da Lat
Chúc bạn học tốt
Trả lời:
a,\(24,5\times4,8\)
\(=117,6\)
b,\(\frac{2}{5}\times\frac{1}{2}-\frac{2}{5}\times\frac{1}{3}-\frac{2}{5}\times\frac{1}{6}\)
\(=\frac{2}{5}\times\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)
\(=\frac{2}{5}\times0\)
\(=0\)
c,\(0,5\times\left(x-\frac{15}{2}\right)\div\frac{1}{2}=\frac{9}{2}\)
\(\Leftrightarrow\frac{1}{2}\times\left(x-\frac{15}{2}\right)=\frac{9}{4}\)
\(\Leftrightarrow x-\frac{15}{2}=\frac{9}{2}\)
\(\Leftrightarrow x=12\)
Vậy \(x=12\)
Trả lời:
a,\(17-2\times\left(x-9\right)=5\)
\(\Leftrightarrow2\times\left(x-9\right)=12\)
\(\Leftrightarrow x-9=6\)
\(\Leftrightarrow x=15\)
Vậy \(x=15\)
b,\(\frac{7}{3}-\frac{1}{3}\times x=1\)
\(\Leftrightarrow\frac{1}{3}\times x=\frac{4}{3}\)
\(\Leftrightarrow x=4\)
Vậy \(x=4\)
c,\(x+x\div0,25+x\div0,25+x\div0,25=0,45\)
\(\Leftrightarrow x+x\times4+x\times4+x\times4=0,45\)
\(\Leftrightarrow x\times\left(1+4+4+4\right)=0,45\)
\(\Leftrightarrow x\times13=0,45\)
\(\Leftrightarrow x=\frac{9}{260}\)
Vậy \(x=\frac{9}{260}\)
Trả lời:
a,\(105,6-x=29,04\)
\(\Leftrightarrow x=76,56\)
Vậy \(x=76,56\)
b,\(x\div7=4,5\times3\)
\(\Leftrightarrow x\div7=13,5\)
\(\Leftrightarrow x=\frac{27}{14}\)
Vậy \(x=\frac{27}{14}\)
c,\(x\times2,8+5,2\times x=48\)
\(\Leftrightarrow x\times\left(2,8+5,2\right)=48\)
\(\Leftrightarrow x\times8=48\)
\(\Leftrightarrow x=6\)
Vậy \(x=6\)
\(\frac{121212}{161616}-\left(\frac{151515}{323232}-x\right)=2\)
=> \(\frac{3}{4}-\left(\frac{15}{32}-x\right)=2\)
=> \(\frac{15}{32}-x=\frac{3}{4}-2\)
=> \(\frac{15}{32}-x=-\frac{5}{4}\)
=> \(x=\frac{15}{32}-\frac{-5}{4}=\frac{15}{32}+\frac{5}{4}=\frac{55}{32}\)
b) \(\frac{x}{2}+\frac{x}{6}+\frac{x}{12}+\frac{x}{20}+\frac{x}{30}+\frac{x}{42}+\frac{x}{56}+\frac{x}{72}+\frac{x}{90}=\frac{9}{5}\)
=> \(\frac{x}{1\cdot2}+\frac{x}{2\cdot3}+\frac{x}{3\cdot4}+\frac{x}{4\cdot5}+\frac{x}{5\cdot6}+\frac{x}{6\cdot7}+\frac{x}{7\cdot8}+\frac{x}{8\cdot9}+\frac{x}{9\cdot10}=\frac{9}{5}\)
=> \(\frac{x}{1}-\frac{x}{2}+\frac{x}{2}-\frac{x}{3}+...+\frac{x}{9}-\frac{x}{10}=\frac{9}{5}\)
=> \(\frac{x}{1}-\frac{x}{10}=\frac{9}{5}\)
=> \(\frac{10x-x}{10}=\frac{9}{5}\)
=> \(\frac{9x}{10}=\frac{9}{5}\)
=> \(\frac{9x}{10}=\frac{9\cdot2}{5\cdot2}=\frac{18}{10}\)
=> x = 2