Bỏ ngoặc trong phép tính sau rồi tính:
a,( 13 - 47 ) - ( 13 + 59 -81 ) + ( 35 - 13 )
b, ( 345 - 61 + 84) - ( - 61 + 116 + 345)
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(102 + 112 + 122) : (132 + 142)
= (100 + 121 + 144) :( 169 + 196)
= 365: 365
= 1
a) Suy ra : \(x\in BCNN\left(14,21\right)\)
14 = 2.7
21 = 3.7
=> BCNN (14,21)=7.2.3=42
Vậy x = 42
b) 200-(2x+6)=4^3
=>200-2x-6=64
=>194-2x=64
=>2x=194-64=130
=>x=65
a) x ⋮ 14 và x ⋮ 21
Mà x ≠ 0 và x là số nhỏ nhất nên:
\(x\in BCNN\left(14,21\right)\)
Ta có:
\(14=2\cdot7\)
\(21=3\cdot7\)
\(\Rightarrow x=BCNN\left(14,21\right)=7\cdot2\cdot3=42\)
b) \(200-\left(2x+6\right)=4^3\)
\(\Rightarrow2x+6=200-4^3\)
\(\Rightarrow2x+6=200-64\)
\(\Rightarrow2x+6=136\)
\(\Rightarrow2x=136-6\)
\(\Rightarrow2x=130\)
\(\Rightarrow x=130:2\)
\(\Rightarrow x=65\)
2^3 * 5+3^19:3^17-2022^0
= 8*5+3^19:3^17-1
=8*5+3^2-1
=8*5+9-1
=40+9-1
=48
Số số hạng của A:
(100 - 2) : 2 + 1 = 50 (số)
A = 2 - 4 + 6 - 8 + ... + 98 - 100
= (2 - 4) + (6 - 8) + ... + (98 - 100)
= -2 . 50 : 2
= -50
a) x - 1/2 = 3/5
x = 3/5 + 1/2
x = 11/10
b) x - 1/2 = -2/3
x = -2/3 + 1/2
x = -1/6
c) 2/5 - x = 0,25
x = 2/5 - 0,25
x = 2/5 - 1/4
x = 3/20
\(d,-\dfrac{3}{26}.\left(-\dfrac{15}{19}\right)+\dfrac{2}{19}.\left(-\dfrac{3}{26}\right)\\=-\dfrac{3}{26}.\left(-\dfrac{15}{19}+\dfrac{2}{19}\right)\\ =-\dfrac{13}{19}.\left(-\dfrac{3}{26}\right)\\ =\dfrac{3}{38}. \)
d) \(\dfrac{-3}{26}\times\left(\dfrac{-15}{19}\right)+\dfrac{2}{19}\times\dfrac{-3}{26}\)
\(=\dfrac{-3}{26}\times\left[\left(\dfrac{-15}{19}\right)+\dfrac{2}{19}\right]\)
\(=\dfrac{-3}{26}\times\dfrac{-13}{19}\)
\(=\dfrac{3}{38}\)
Câu 9
a) 2/15 + (-3/5)
= 2/15 - 3/5
= 2/15 - 9/15
= -7/15
b) -5/7 + 3/7 . (-2/9)
= -5/7 - 2/21
= -15/21 - 2/21
= -17/21
c) 5/16 - (7/15 - 3/16) + 17/30
= 5/16 - 7/15 + 3/16 + 17/30
= (5/16 + 3/16) + (17/30 - 14/30)
= 1/2 + 1/10
= 5/10 + 1/10
= 6/10
= 3/5
\(a,\dfrac{2}{15}+\left(-\dfrac{3}{5}\right)\\ =\dfrac{2}{15}-\dfrac{3}{5}\\ =\dfrac{2}{15}-\dfrac{9}{15}\\ =-\dfrac{7}{15}\\ b,-\dfrac{5}{7}+\dfrac{3}{7}\times\left(-\dfrac{2}{9}\right)\\ =-\dfrac{5}{7}-\dfrac{2}{21}\\ =-\dfrac{15}{21}-\dfrac{2}{21}\\ =-\dfrac{17}{21}\\ c,\dfrac{5}{16}-\left(\dfrac{7}{15}-\dfrac{3}{16}\right)+\dfrac{17}{30}\\ =\dfrac{5}{16}-\dfrac{7}{15}+\dfrac{3}{16}+\dfrac{17}{30}\\ =\left(\dfrac{5}{16}+\dfrac{3}{16}\right)-\left(\dfrac{17}{15}+\dfrac{17}{30}\right)\\ =\dfrac{1}{2}-\dfrac{17}{10}\\ =\dfrac{5}{10}-\dfrac{17}{10}\\ =-\dfrac{6}{5}.\)
Lời giải:
a. $=13-47-13-59+81+35-13$
$=(13-13-13)-(47+59)+(81+35)$
$=-13-106+116=-13+(116-106)=-13+10=-3$
b.
$=345-61+84+61-116-345$
$=(345-345)+(-61+61)-(116-84)$
$=0+0-32=-32$
a, $(13-47)-(13+59-81)+(35-13)$
$=13-47-13-59+81+35-13$
$=(13-13)+(-47-13)+(-59+81)+35$
$=-60+22+35$
$=-38+35$
$=-3$
$---$
b, $(345-61+84)-(-61+116+345)$
$=345-61+84+61-116-345$
$=(345-345)+(-61+61)+(84-116)$
$=-32$