tổng số hạt trong nguyên tử nguyên tố X là 13 Tìm số proton
giúp mh làm câu này đi ...
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
- Qua C dựng đường thẳng song song với AB cắt AQ tại E.
- \(\Delta ABQ\) và \(\Delta ECQ\) có:
\(\left\{{}\begin{matrix}\widehat{ABQ}=\widehat{ECQ}\\BQ=CQ\\\widehat{AQB}=\widehat{EQC}\end{matrix}\right.\)
\(\Rightarrow\Delta ABQ=\Delta ECQ\left(g-c-g\right)\)
\(\Rightarrow AB=CE;QA=QE\Rightarrow\)Q là trung điểm AE.
- \(\Delta ADE\) có: P là trung điểm AD, Q là trung điểm AE.
\(\Rightarrow\)PQ là đường trung bình của \(\Delta ADE\).
\(\Rightarrow PQ=\dfrac{DE}{2}\).
- Mà theo BĐT tam giác ta có: \(DE\le CD+CE\)
\(\Rightarrow PQ=\dfrac{CD+CE}{2}=\dfrac{AB+CD}{2}\)
\(\Rightarrowđpcm\)
- Dấu "=" xảy ra khi D,C,E thẳng hàng \(\Leftrightarrow\)AB//CD \(\Leftrightarrow\)ABCD là hình thang.
Lời giải:
$M=(2ab+b)^2-(b-2a)^2=(2ab+b-b+2a)(2ab+b+b-2a)$
$=(2ab+2a)(2ab+2b-2a)$
$=4a(b+1)(ab+b-a)$
$N=(3a+2)^2+2(2+3a)(1-2b)+(2b-1)^2$
$=(3a+2)^2-2(3a+2)(2b-1)+(2b-1)^2$
$=[(3a+2)-(2b-1)]^2=(3a+2-2b+1)^2=(3a-2b+3)^2$
Lời giải:
a.
$2x(8x-3)+4x(4x-1)=3$
$\Leftrightarrow 16x^2-6x+16x^2-4x=3$
$\Leftrightarrow 32x^2-10x-3=0$
$\Leftrightarrow (2x-1)(16x+3)=0$
$\Leftrightarrow 2x-1=0$ hoặc $16x+3=0$
$\Leftrightarrow x=\frac{1}{2}$ hoặc $x=\frac{-3}{16}$
b.
$x(10x+3)-2x(5x-7)=6$
$\Leftrightarrow 10x^2+3x-(10x^2-14x)=6$
$\Leftrightarrow 17x=6$
$\Leftrightarrow x=\frac{6}{17}$
\(=\left[\left(x-1\right).\left(x^2+x+1\right)\right].\left[\left(x+1\right)\left(x^2-x+1\right)\right]=\)
\(=\left(x^3-1\right)\left(x^3+1\right)=x^6-1=\left(-3\right)^6-1=728\)
watch
listened
dóe - have
gets
didn't do
watched
visited
is
went
has
Does - take
1. The sun/ rise/ East.
……………The Sun rises in the East……………………………………………………………………………
2. He/ be/ old/ enough/ go/ school.
………………He is old enough to go to school…………………………………………………………………………
3. It/ be/ cold/ go out.
……………………It is too cold to go out……………………………………………………………………
4. She/ be/ nice girl/ long hair.
……………………She is a nice girl with long hair……………………………………………………………………
5. He/ be/ friendly/ kind/ everyone.
…………………He is friendly and kind to everyone………………………………………………………………………
6. His hair/ short/ black.
…………………His hair is short and back………………………………………………………………………
7. What/ your teacher/ like?
…………What is your teacher like?………………………………………………………………………………
8. He/ be/ not/ sociable/ as/ his brother.
…………He is not as sociable as his brother………………………………………………………………………………
9. We/ enjoy/ tell/ jokes.
……………………We enjoy telling jokes……………………………………………………………………
10.He/ be/ hard-working student.
…………………………He is a hard-working student………………………………………………………………
Ta có: \(\left\{{}\begin{matrix}2p_X+n_X=13\\p_X\le n_X\le1,5p_X\end{matrix}\right.\)
=> \(\dfrac{26}{7}\le p_X\le\dfrac{13}{3}\)
=> pX = 4