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\(x.7+x.5-x-x.5=790\)
\(x.\left(7+5-1-5\right)=790\)
\(x.6=790\)
\(x=796:6\)
\(x=\frac{395}{3}\)
x X ( 7 + 5 - 1 - 5 ) = 790
x X 6 = 790
x = 790 : 6
Vì ko có máy tính nên mk ko ghi kết quả cho bạn d

Tim x:
x X 12 + x X 14 + x X 18 = \(\frac{21}{24}\)
x X (\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}\)) = \(\frac{21}{24}\)
x X (\(\frac{4}{8}+\frac{2}{8}+\frac{1}{8}\)) = \(\frac{21}{24}\)
x X \(\frac{9}{8}\)= \(\frac{21}{24}\)
x = \(\frac{21}{24}\): \(\frac{9}{8}\)
x = \(\frac{21}{24}\)X \(\frac{8}{9}\)
x = \(\frac{7}{9}\)
\(x\times\frac{1}{2}+x\times\frac{1}{4}+x\times\frac{1}{8}=\frac{21}{24}\)
\(\Rightarrow x\times\left[\frac{1}{2}+\frac{1}{4}+\frac{1}{8}\right]=\frac{21}{24}\)
\(\Rightarrow x\times\left[\frac{4+2+1}{8}\right]=\frac{21}{24}\)
\(\Rightarrow x\times\frac{7}{8}=\frac{21}{24}\)
\(\Rightarrow x\times\frac{7}{8}=\frac{7}{8}\)
\(\Rightarrow x=\frac{7}{8}:\frac{7}{8}=1\)

Theo đầu bài ta có:
\(\frac{x-7}{7}+\frac{x-7}{8}=\frac{15}{56}\)
\(\Rightarrow\left(x-7\right)\cdot\frac{1}{7}+\left(x-7\right)\cdot\frac{1}{8}=\frac{15}{56}\)
\(\Rightarrow\left(x-7\right)\cdot\left(\frac{1}{7}+\frac{1}{8}\right)=\frac{15}{56}\)
\(\Rightarrow\left(x-7\right)\cdot\frac{15}{56}=\frac{15}{56}\)
\(\Rightarrow x-7=1\)
\(\Rightarrow x=8\)

1-[x(1/5+1)-2/3]=x-75
1-6/5x+2/3=x-75
1+2/3+75=x+6/5x
230/3=11/5x
x=230/3:11/5=1150/33

\(X\cdot4+0,5\cdot X=55,35\)
\(X\cdot\left(4+0,5\right)=55,35\)
\(X\cdot4,5=55,35\)
\(X=55,35:4,5\)
\(X=12,3\)

\(\frac{1}{2}+x=\frac{6}{13}:\frac{15}{39}=\frac{6}{5}\)
=>\(x=\frac{6}{5}-\frac{1}{2}=\frac{7}{10}\)
6/13 : (1/2 + x) = 15/39 1/2 + x = 6/13 : 15/39 1/2 + x = 6/5 x = 6/5 - 1/2 x = 7/10

a, \(\frac{6+x}{33}=\frac{7}{11}\)
\(\Leftrightarrow\left(6+x\right).11=7.33\)
\(\Leftrightarrow66+11x=231\)
\(\Leftrightarrow11x=231-66\)
\(\Leftrightarrow x=\frac{165}{11}=15\)
Vậy x = 15.
b,\(\frac{12+x}{43-x}=\frac{2}{3}\)
\(\Leftrightarrow3.\left(12+x\right)=2\left(43-x\right)\)
\(\Leftrightarrow36+3x=86-2x\)
\(\Leftrightarrow3x+2x=-36+86\)
\(\Leftrightarrow5x=50\)
\(\Leftrightarrow x=10\)
Vây x = 10.

\(\frac{5}{9}+\frac{2}{5}\cdot x=\frac{8}{9}\)
\(\frac{2}{5}\cdot x=\frac{8}{9}-\frac{5}{9}\)
\(\frac{2}{5}\cdot x=\frac{1}{3}\)
\(x=\frac{1}{3}\div\frac{2}{5}\)
\(x=\frac{5}{6}\)
2,5*x+21,6=40,35
2,5*x=40,35-21,6
2,5*x=18,75
x=18,75/2,5
x=7,5
vậy...
\(2,5\times x+21,6=40,35\)
\(2,5\times x=40,35-21,6\)
\(2,5\times x=18,75\)
\(x=18,75:2,5\)
\(x=7,5\)