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=9/4x2/3+16/9x4/3
=18/12+64/36
=54/36+64/36=118/36=59/18

a. 36 × 25 × 4 = 36 × 100 = 3600
b. 18 × 24 : 9 = ( 18 : 9) × 24 = 2 × 24 = 48
c. 215 × 86 + 215 × 14 = 215 × ( 86 + 14) = 215 × 100 = 21500

\(99\times36+36\)
\(=99\times36+36\times1\)
\(=36\left(99+1\right)\)
\(=36\times100\)
\(=3600\)


\(1235\text{×}6789\text{×}\left(630-315\text{×}2\right)\)
\(=1235\text{×}6789\text{×}\left(630-630\right)\)
\(=1235\text{×}6789\text{×}0=0\)
\(\left(100+67\right)\text{×}67+\left(200-38\right)\text{×}33\)
\(=167\text{×}67+167\text{×}33\)
\(=167\text{×}\left(67+33\right)\)
\(=167\text{×}100=16700\)
\(72+36\text{×}2+24\text{×}3+18\text{×}4+12\text{×}2+168\)
\(=72+72+72+72+24+168\)
\(=\left(72\text{×}4\right)+24+168=288+24+168=480\)

a) 23*45 -23*35+23*90
= 23* (45-35+90)
= 23*100
= 2300
b) 636/ 6 - 36/ 6
= 600/ 6
= 100
c) 11*607 -607
= 11*607 -607*1
= 607* (11 -1)
= 607*10
= 6070

TL:
8/15 x 5/6 = 40/90 = 4/9
41/20 x 3/4 = 123/80
(11/23 + 9/23) + (18/23 + 2/23) = 20/23 + 20/23 = 40/43
HT
\(\left(\frac{2}{3}\times\frac{4}{5}\right)\times\frac{5}{6}\) = \(\frac{2}{3}\times\frac{4}{5}\times\frac{5}{6}\)=\(\frac{2\times4\times5}{3\times5\times6}\)=\(\frac{2\times4\times5}{3\times5\times2\times3}\)=\(\frac{4}{9}\)
\(\frac{11}{23}+\frac{2}{23}+\frac{9}{23}+\frac{18}{23}\)=\(\frac{\left(11+9\right)+\left(18+2\right)}{23}\)=\(\frac{20+20}{23}\)=\(\frac{40}{23}\)
\(\frac{27}{12}+\frac{17}{6}-\frac{25}{36}-\frac{15}{6}\)=\(\left(\frac{27}{12}-\frac{25}{36}\right)+\left(\frac{17}{6}-\frac{15}{6}\right)\)=\(\frac{14}{9}+\frac{2}{6}\)=\(\frac{17}{9}\)
/HT\

1. 36 x 25 x 4
= 36 x 100
= 3600
2. 18 x 24 : 9
= 18 : 9 x 24
= 2 x 24
= 48
3. 41 x 2 x 8 x 5
= 41 x 8 x 10
= 328 x 10
= 3280
4. 108 x (23+7)
= 108 x 30
= 3240
5. 215 x 86 + 215 x 14
= 215 x (86+14)
= 215 x 100
= 21500
6. 53 x 128 - 43 x 128
= (53-43) x 128
= 10 x 128
= 1280
\(\frac{36\cdot50+24\cdot100}{23\cdot36+114\cdot18}=\frac{50\cdot12\cdot\left(3+2\cdot2\right)}{18\left(23\cdot2+114\right)}=\frac{50\cdot12}{18}\cdot\frac{7}{150}\)
\(=\frac{50}{150}\cdot\frac{12}{18}\cdot7=\frac13\cdot\frac23\cdot7=\frac{14}{9}\)
\(\frac{36\times50+24\times100}{23\times36+114\times18}\)
\(=\frac{36\times50+24\times2\times50}{23\times2\times18+114\times18}\)
\(=\frac{36\times50+48\times50}{46\times18+114\times18}\)
\(=\frac{50\times\left(36+48\right)}{18\times\left(46+114\right)}\)
\(=\frac{50\times84}{18\times160}\)
\(=\frac{5\times10\times6\times14}{6\times3\times10\times16}\)
\(=\frac{5\times14}{3\times16}\)
\(=\frac{5\times2\times7}{3\times2\times8}\)
\(=\frac{5\times7}{3\times8}\)
\(=\frac{35}{24}\)