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7,1 + (-5,25)-(-2,25+7,1)
= 7,1 + ( -5,25 ) + 2,25 + 7,1
= 7,1 + (-3) + 7,1
= 11,2

Ta có \(B=\left(5,25.12\frac{7}{10}+\frac{21}{4}.17\frac{3}{10}\right):\left(-6\frac{9}{16}\right)\)
\(=\left(\frac{21}{4}.12\frac{7}{10}+\frac{21}{4}.17\frac{3}{10}\right):\left(-\frac{105}{16}\right)\)
\(=\frac{21}{4}.\left(12\frac{7}{10}+17\frac{3}{10}\right):\left(-\frac{105}{16}\right)\)
\(=\frac{21}{4}.30:\frac{-105}{16}\)
\(=\frac{315}{2}.\left(\frac{-16}{105}\right)\)
\(=\frac{3.-8}{1}\)
\(=-24\)

\(-4\dfrac{1}{5}-x=2,25\)
\(\dfrac{-21}{5}-x=2,25\)
-4.2-x=2,25
x=-4,2-2,25
x=-6,45

a) 2,25 : \(\frac{-6}{25}=\frac{9}{4}\cdot\frac{-25}{6}=\frac{9\cdot\left(-25\right)}{4\cdot6}=\frac{3\cdot3\cdot\left(-25\right)}{4\cdot3\cdot2}=\frac{-75}{8}\)
b) \(\frac{2^3\cdot5^2\cdot7^2\cdot3^7}{49\cdot5^3\cdot3^6\cdot11}=\frac{2^3\cdot5^2\cdot7^2\cdot3^6\cdot3}{7^2\cdot5^2\cdot5\cdot3^6\cdot11}=\frac{2^3\cdot3}{5\cdot11}=\frac{24}{55}\)

a: Đề sai rồi bạn
b: \(\dfrac{\left(1.16-x\right)\cdot5.25}{\left(10+\dfrac{5}{9}-7-\dfrac{1}{4}\right)\cdot\dfrac{36}{17}}=\dfrac{3}{4}\)
\(\Leftrightarrow21\left(1.16-x\right)=3\cdot\dfrac{36}{17}\cdot\left(3+\dfrac{5}{9}-\dfrac{1}{4}\right)\)
\(\Leftrightarrow21\left(1.16-x\right)=\dfrac{108}{17}\cdot\dfrac{108+20-9}{36}\)
\(\Leftrightarrow21\cdot\left(1.16-x\right)=21\)
=>1,16-x=1
hay x=0,16

\(\frac{\left(1,16-x\right).5,25}{\left(10\frac{5}{9}-7\frac{1}{4}\right).2\frac{2}{17}}=75\%\) <=> \(\frac{6,09-5,25x}{\left(\frac{95}{9}-\frac{29}{4}\right).\frac{36}{17}}=\frac{3}{4}\)<=> \(\frac{6,09-5,25x}{\frac{119}{36}.\frac{36}{17}}=\frac{3}{4}\)
<=> \(\frac{6,09-5,25x}{7}=\frac{3}{4}\)<=> 4(6,09-5,25x)=21 <=> 24,36-21x=21
=> 21x=3,36 => x=3,36:21 => x=0,16
Đáp số: x=0,16

\(\frac{28,8:13\frac{5}{7}+6,6:\frac{2}{3}}{1\frac{11}{16}:}2,25\)=\(\frac{\frac{21}{10}+\frac{99}{10}}{\frac{3}{4}}=\frac{12}{\frac{3}{4}}=16\)
\(\left(-3,48+5,25\right)-\left(-6,48+2,25\right)\)
\(=-3,48+5,25+6,48-2,25\)
\(=\left(-3,48+6,48\right)+\left(5,25-2,25\right)\)
\(=3+3=6\)
Hết nghỉ lễ là thị đấy