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\(A=\frac{5}{1.2}+\frac{5}{2.3}+...+\frac{5}{7.8}\)
\(\Rightarrow5A=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{7.8}\)
\(\Rightarrow5A=1.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-...-\frac{1}{8}\right)\)
\(\Rightarrow5A=1-\frac{1}{8}\)
\(\Rightarrow A=\left(1-\frac{1}{8}\right).\frac{1}{5}=\frac{7}{40}\)
\(A=\frac{5}{1.2}+\frac{5}{2.3}+...+\frac{5}{7.8}\)
\(A=5\left(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{5}{7.8}\right)\)
\(A=5\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{7}-\frac{1}{8}\right)\)
\(A=5\left(1-\frac{1}{8}\right)\)
\(A=5.\frac{7}{8}\)
\(A=\frac{38}{8}\)
\(A=9\left(\frac{1}{4x5}+\frac{1}{5x6}+\frac{1}{6x7}+...+\frac{1}{34x35}+\frac{1}{35.36}\right)\)
\(A=9\left(\frac{5-4}{4x5}+\frac{6-5}{5x6}+\frac{7-6}{6x7}+...+\frac{35-34}{34x35}+\frac{36-35}{35x36}\right)\)
\(A=9\left(\frac{1}{4}-\frac{1}{36}\right)=9x\frac{8}{36}=2\)
\(\frac{1}{2\times3}+\frac{1}{3\times4}+\frac{1}{4\times5}+\frac{1}{5\times6}\)
\(=\frac{3-2}{2\times3}+\frac{4-3}{3\times4}+\frac{5-4}{4\times5}+\frac{6-5}{5\times6}\)
\(=\frac{3}{2\times3}-\frac{2}{2\times3}+\frac{4}{3\times4}-\frac{3}{3\times4}+\frac{5}{4\times5}-\frac{4}{4\times5}+\frac{6}{5\times6}-\frac{5}{5\times6}\)
\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\)
\(=\frac{1}{2}-\frac{1}{6}\)
\(=\frac{1}{3}\)
Ta có : 1/2.3+1/3.4+1/4.5+1/5.6
=1/2-1/3+1/3-1/4+….+1/5-1/6
=1/2-1/6
=2/6=1/3
Đây bạn nhé!
1/2x3 + 1/3x4 + 1/4x5 + 1/5x6
=1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 -1/6 (Gạch hết các phân số giống nhau đi)
=1/2 - 1/6
=1/3
Học tốt!
\(\frac{199...9}{999...5}=\frac{20...0-1}{100...00-5}\)(200...0 có 100 cs 0 và 100....0 có 101 chữ số 0)
\(=\frac{200...0-1}{5.\left(200...0-1\right)}=\frac{1}{5}\)( cả tử và mẫu có 100 cs 0)
\(6xy+\left(\frac{1}{2x3}+\frac{1}{3x4}+\frac{1}{4x5}+...+\frac{1}{7x8}\right)=\frac{29}{8}\)
Đăt \(A=\frac{1}{2x3}+\frac{1}{3x4}+\frac{1}{4x5}+...+\frac{1}{7x8}\)
\(\Rightarrow A=\frac{3-2}{2x3}+\frac{4-3}{3x4}+\frac{5-4}{4x5}+...+\frac{8-7}{7x8}\)
\(A=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{7}-\frac{1}{8}=\frac{1}{2}-\frac{1}{8}=\frac{3}{8}\)
\(\Rightarrow6xy+A=6xy+\frac{3}{8}=\frac{29}{8}\Rightarrow6xy=\frac{26}{8}\Rightarrow y=\frac{26}{8x6}\)
\(D=\dfrac{3}{4\times5}+\dfrac{3}{5\times6}+\dfrac{3}{6\times7}+...+\dfrac{3}{93\times94}+\dfrac{3}{94\times95}\)
\(=3\times\left(\dfrac{1}{4\times5}+\dfrac{1}{5\times6}+\dfrac{1}{6\times7}+...+\dfrac{1}{93\times94}+\dfrac{1}{94\times95}\right)\)
\(=3\times\left(\dfrac{5-4}{4\times5}+\dfrac{6-5}{5\times6}+\dfrac{7-6}{6\times7}+...+\dfrac{94-93}{93\times94}+\dfrac{95-94}{94\times95}\right)\)
\(=3\times\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}+...+\dfrac{1}{93}-\dfrac{1}{94}+\dfrac{1}{94}-\dfrac{1}{95}\right)\)
\(=3\times\left(\dfrac{1}{4}-\dfrac{1}{95}\right)\)
\(=3\times\dfrac{91}{380}\)
\(=\dfrac{273}{380}\)
D= \(\frac{3}{4.5}+\frac{3}{5.6}+\frac{3}{6.7}+\cdots+\frac{3}{93.94}+\frac{3}{94.95}\)
\(= 3 \times \left(\right. \frac{1}{4 \times 5} + \frac{1}{5 \times 6} + \frac{1}{6 \times 7} + . . . + \frac{1}{93 \times 94} + \frac{1}{94 \times 95} \left.\right)\)
\(= 3 \times \left(\right. \frac{5 - 4}{4 \times 5} + \frac{6 - 5}{5 \times 6} + \frac{7 - 6}{6 \times 7} + . . . + \frac{94 - 93}{93 \times 94} + \frac{95 - 94}{94 \times 95} \left.\right)\)
\(= 3 \times \left(\right. \frac{1}{4} - \frac{1}{5} + \frac{1}{5} - \frac{1}{6} + \frac{1}{6} - \frac{1}{7} + . . . + \frac{1}{93} - \frac{1}{94} + \frac{1}{94} - \frac{1}{95} \left.\right)\)
\(= 3 \times \left(\right. \frac{1}{4} - \frac{1}{95} \left.\right)\)
\(= 3 \times \frac{91}{380}\)
\(= \frac{273}{380}\)