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a) \(2\left(2x-7\right)^2=18\)
\(\Leftrightarrow\left(2x-7\right)^2=9\)
\(\Leftrightarrow\left(2x-7\right)^2=3^2\)
\(\Leftrightarrow2x-7=3\)
\(\Leftrightarrow2x=10\)
\(\Leftrightarrow x=5\)
2.(2X-7)^2= 18
(2X-7)^2=18:2
(2x-7)^2= 9
(2x-7)^2 = 3^2 = (-3)^2
=> (2x-7)^2 = 3^2 và (2x-7)^2 = (-3)^2

a)Ta có:
\(^{2^x+128=18}\)\(\Rightarrow\)\(2^x=18-128=-110\)
mà 2\(2^x>0\Rightarrow-110>0\Rightarrow vl\Rightarrow x\in\varnothing\)
b)
ta có :\(2^x>2^y\Rightarrow x>y\left(1\right)\)
vì 7 lẻ \(\Rightarrow2^x-2^ylẻ\)
trong \(2^xva2^y\)chắc chắn có 1 số lẻ:
xét \(2^xlẻ\Rightarrow x=0\)
\(\Rightarrow2^ychan\Rightarrow y>2\Rightarrow y>x\Rightarrow vl\)vì trái với điều kiện (1)
xét \(2^ylẻ\Rightarrow y=0\)
\(2^x-1=7\Leftrightarrow2^x=8\Leftrightarrow2^x=2^3\Rightarrow x=3\)
\(\Rightarrow\left(x,y\right)=\left(3,0\right)\)

\(18⋮x\)và \(7\le x< 18\)
Vì \(18⋮x\)
\(\Rightarrow\)\(x\inƯ\left(18\right)=\left\{1;2;3;6;9;18\right\}\)
Mà \(7\le x< 18\)
\(\Rightarrow\)\(x\in\left\{9\right\}\)
Vậy chọn đáp án \(D.9\)

a, 2x + 2x+1 + 2x+2 + 2x+3 = 480
=> 2x + 2x.2 + 2x.22 + 2x.23 = 480
=> 2x.(1 + 2 + 22 + 23) = 480
=> 2x.15 = 480
=> 2x = 480 : 15
=> 2x = 32 = 25
=> x = 5
b, |7 - x| = -13 - 5.(-8)
|7 - x| = 27
\(\Rightarrow\hept{\begin{cases}7-x=27\\-7+x=27\end{cases}}\Rightarrow\hept{\begin{cases}x=-20\\x=34\end{cases}}\)

a, \(x-\frac{2}{5}=\frac{5}{7}\)
\(x=\frac{5}{7}+\frac{2}{5}\)
\(x=\frac{39}{35}\)
b, \(\frac{5}{12}-x=\frac{7}{18}\)
\(x=\frac{5}{12}-\frac{7}{18}\)
\(x=\frac{1}{36}\)
x-2/5=-5/2
x=-5/2+2/5
x=-21/10
vậy x=21/10
5/12-x=7/18
x=5/12-7/18
x=1/36
vậy x=1/35

a/ \(\frac{6}{7}x=\frac{18}{23}\)
\(x=\frac{18}{23}:\frac{6}{7}=\frac{21}{23}\)
b/ \(2\frac{1}{2}x=\frac{5}{6}\)
\(=>\frac{5}{2}x=\frac{5}{6}\)
\(x=\frac{5}{6}:\frac{5}{2}=\frac{1}{3}\)
c/\(x:2\frac{3}{4}=9\frac{5}{8}\)
\(x:\frac{11}{4}=\frac{77}{8}\)
\(x=\frac{77}{8}\cdot\frac{11}{4}=\frac{847}{32}\)
d/\(7\frac{1}{7}\cdot\frac{1}{7}\cdot x=22\frac{1}{8}\)
\(\frac{50}{49}x=\frac{177}{8}\)
\(x=\frac{177}{8}:\frac{50}{49}=\frac{8673}{400}\)
\(a,\frac{6}{7}.x=\frac{18}{23}\) \(\Rightarrow x=\frac{18}{23}:\frac{6}{7}=\frac{18}{23}.\frac{7}{6}=\frac{21}{23}\)
\(b,2\frac{1}{2}.x=\frac{5}{6}\Rightarrow\frac{5}{2}.x=\frac{5}{6}\Rightarrow x=\frac{5}{6}:\frac{5}{2}=\frac{5}{6}.\frac{2}{5}=\frac{1}{3}\)
\(c,x:2\frac{3}{4}=9\frac{5}{8}\Rightarrow x:\frac{11}{4}=\frac{77}{8}\Rightarrow x=\frac{77}{8}.\frac{11}{4}=\frac{847}{32}\)
\(d,7\frac{1}{7}.\frac{1}{7}.x=22\frac{1}{8}\Rightarrow\frac{50}{49}.x=\frac{177}{8}\Rightarrow x=\frac{177}{8}:\frac{50}{49}=\frac{177}{8}.\frac{49}{50}=\frac{8673}{400}\)

a) x + 15 = 36 - 2x
x + 15 = 36 - (x + x )
15 =36 - ( x + x) - x
15 = 36 - x - x - x
15 = 36 - 3x
3x = 36 - 15
3x = 21
x = 21 : 3
=> x = 7
b) (x - 7) - (2x +5) = -14
x - 7 -( 2x + 5) = -14
x - (2x + 5) = -14 + 7 = -7
x - 2x - 5 = -7
x - 2x = -7 + 5 = -2
x - x + x = 2
x = 2 (-x + x cũng bằng chính nó)
=> x = 2
c) (x - 12) - 15 = (-7 + 20) - (18+x)
(x - 12) - 15 = 13 - (18 + x)
(x - 12) - 15 = 13 - 18 - x
(x - 12) - 15 = -5 - x
15 = (x - 12 ) - (-5 - x)
15 = x - 12 + 5 + x
15 = x + (-12) + 5 + x
15 = 2x + [(-12) + 5]
15 = 2x + -7
2x = -7 + 15
2x = 8
x = 8 : 2
=> x = 4
..................

a) \(x-\frac{5}{7}=\frac{1}{9}\Rightarrow x=\frac{1}{9}+\frac{5}{7}\Rightarrow x=\frac{52}{63}\)
b) \(\frac{-3}{7}-x=\frac{4}{5}+\frac{-2}{3}\Rightarrow\frac{-3}{7}-x=\frac{2}{15}\Rightarrow x=\frac{-3}{7}-\frac{2}{15}\Rightarrow x=\frac{-59}{105}\)
c) \(x-\frac{1}{5}=\frac{2}{7}.\frac{-11}{5}\Rightarrow x-\frac{1}{5}=\frac{-22}{35}\Rightarrow x=\frac{-22}{35}+\frac{1}{5}\Rightarrow x=\frac{-3}{7}\)
d) \(\frac{x}{182}=\frac{-6}{14}.\frac{35}{91}\Rightarrow\frac{x}{182}=\frac{-15}{91}\Rightarrow x=\frac{\left(-15\right).182}{91}\Rightarrow x=-30\)

(8 x 18 -5 x 18 -18 x3) x y + 2 x y =8 x 7 + 2
<=>144 x y -90 x y -54 x y + 2 x y = 58
<=>2 x y = 58
<=> y = 29
vậy y = 29
( mình ko chép lại đề bài đâu nha ,giải lun đó)
[18x(8-5-3)]xy+2xy=56+2
(18x0)xy+2xy=58
0xy+2xy=58
2xy=58
y=58:2=29
tick cho mình nha
giup tui plssssssssssssssss
x−7=x−7−18
Nhân chéo:
\(\left(\right. x - 7 \left.\right) \left(\right. x - 7 \left.\right) = \left(\right. - 2 \left.\right) \left(\right. - 18 \left.\right)\) \(\left(\right. x - 7 \left.\right)^{2} = 36\)
Lấy căn hai vế:
\(x - 7 = \pm 6\) \(x = 7 + 6 = 13 \text{ho}ặ\text{c} x = 7 - 6 = 1\)
Vậy nghiệm là \(x = 1\) hoặc \(x = 13\). ✅