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\(\dfrac{\left(2^3.5.7\right).\left(5^2.7^3\right)}{2.5.\left(7^2\right)}=\dfrac{2^3.\left(5.5^2\right).\left(7.7^3\right)}{2.5.7^2}\)
\(=\dfrac{2^3.5^3.7^4}{2.5.7^2}=\left(2^3:2\right).\left(5^3:5\right).\left(7^4:7^2\right)=2^2.5^2.7^2\)
=\(\left(2.5.7\right)^2=4900\)
(23 . 5 . 7) . (52 . 73) / 2 . 5 (72)
= (8 . 5 . 7) . (25 . 343) / 2 . 5 . 49
= 280 . 8575 / 490
= 2401000 / 490
= 4900
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{2^3.5.7.5^2.7^3}{2^2.5^2.7^4}=\frac{2^3.5^3.7^4}{2^2.5^2.7^4}=2.5=10\)
đối với lớp 6 thì trình bày thế này dễ hiểu hơn
\(\frac{\left(2^3.5.7\right)\left(5^2.7^3\right)}{\left(2.5.7^2\right)^2}=\frac{2^3.5.5^2.7.7^3}{2.5.7^2.2.5.7^2}=\frac{2^3.5^3.7^4}{2^2.5^2.7^4}=\frac{2.5}{1}=10\)
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Bài 2: Mỗi xe ô tô có 4 bánh xe . Hỏi 5 xe ô tô như thế có bao nhiêu bánh xe ?
Bài giải
5 xe ô tô như thế có số bánh xe là :
4 x 5= 20 (bánh xe )
Đáp số : 20 bánh xe
![](https://rs.olm.vn/images/avt/0.png?1311)
Đặt là a, b nhá
\(a)\) \(7^{x-1}-2.7^{100}=5.7^{100}\)
\(\Leftrightarrow\)\(7^{x-1}=5.7^{100}+2.7^{100}\)
\(\Leftrightarrow\)\(7^{x-1}=7^{100}\left(5+2\right)\)
\(\Leftrightarrow\)\(7^{x-1}=7^{100}.7\)
\(\Leftrightarrow\)\(7^{x-1}=7^{101}\)
\(\Leftrightarrow\)\(x-1=101\)
\(\Leftrightarrow\)\(x=101+1\)
\(\Leftrightarrow\)\(x=102\)
Vậy \(x=102\)
\(b)\) \(5^{x-4}=25\)
\(\Leftrightarrow\)\(5^{x-4}=5^2\)
\(\Leftrightarrow\)\(x-4=2\)
\(\Leftrightarrow\)\(x=2+4\)
\(\Leftrightarrow\)\(x=6\)
Vậy \(x=6\)
Chúc bạn học tốt ~
\(7^{x-1}-2.7^{100}=5.7^{100}\)
\(\Rightarrow7^{x-1}=5.7^{100}+2.7^{100}\)
\(\Rightarrow7^{x-1}=7.7^{100}\)
\(\Rightarrow7^{x-1}=49^{100}\)
\(\Rightarrow7^{x-1}=7^{2^{100}}\)
\(\Rightarrow7^{x-1}=7^{200}\)
\(\Rightarrow x=201\)
Vậy x = 201
\(5^{x-4}=25\)
\(\Rightarrow5^{x-4}=5^2\)
\(\Rightarrow x=6\)
Vậy x = 6
\(\left(2^{100}.5+2^{100}.3\right):2^{101}\)
\(=2^{100}.8:2^{101}\)
\(=2^{100}.2^3:2^{101}\)
\(=2^{103}:2^{101}\)
\(=2^2\)
\(=4\)
\(3^5:3^3+2^2.2^3-14\)
\(=3^2+2^6-14\)
\(=9+64-14\)
\(=59\)
![](https://rs.olm.vn/images/avt/0.png?1311)
= \(\frac{3^2.5^4.7^9}{3^3.5^2.7^5.3^3.5^2.7^5}\)
=\(\frac{3^2.5^4.7^9}{3^6.5^4.7^{10}}\)
= \(\frac{1.1.1}{3^4.1.7}\)
= \(\frac{1}{567}\)
\(\frac{\left(3^2.5.7^9\right).\left(3^5.5^3\right)}{\left(3^3.5^2.7^5\right)^2}=\frac{\left(3^2.3^5\right).\left(5.5^3\right).7^9}{3^6.5^4.7^{10}}=\frac{3^7.5^4.7^9}{3^6.5^4.7^{10}}=\frac{3}{7}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{1}{2}\cdot2^x+2^x\cdot2^2=2^8+2^5\)
\(2^x\left(\frac{1}{2}+4\right)=2^8+2^5\)
\(2^x\cdot\frac{9}{2}=288\)
\(2^x=64\)
\(2^x=2^6\)
\(x=6\)
\(9^x:3^x=3^7\)
\(3^{2x}:3^x=3^7\)
\(3^x=3^7\)
\(x=7\)
\(7^{x+2}+2\cdot7^{x-1}=345\)
\(7^x\cdot7^2+2\cdot7^x:7=345\)
\(7^x\left(7^2+\frac{2}{7}\right)=345\)
\(7^x\cdot\frac{345}{7}=345\)
\(7^x=7\)
\(x=1\)
a) 1/2.2^x + 2^x+2 = 256 + 32
1/2.2^x + 2^2.2^x=288
2^x(1/2+4)= 288
2^x.4,5=288
2^x= 288:4,5
2^x=64=2^6
x=6
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492.75
=(72)2.75
=74.75
=79
42x-3=64
=> 42x-3=43
=> 2x-3=3
=> 2x=6
=> x=6:2
=> x=3
a)492.75=(72)2.75=74.75=79
b)42x-3=64
42x-3=43
=>2x-3=3
2x = 3 + 3
2x = 6
x = 3
Vậy x = 3
( 3 + 5 + 7 + ... + 57 )^2
tính riêng 3 + 5 + 7 + ... + 57
số số hạng là:
( 57 - 3 ) : 2 + 1 = 28 (số)
tổng là:
( 57 + 3 ) x 28 : 2 = 840
vậy:
( 3 + 5 + 7 + ... + 57 )^2
= 840^2
= 705 600