Question

[Vũ Nam Phong]

\(\frac{2^6\cdot18+2^7}{2^6\cdot5^2-2^6\cdot3}\)

Answer 1

[Nguyễn Tuấn Tú]

\(\frac{2^6.18+2^7}{2^6.5^2-2^6.3}=\frac{2^6.18+2^6.2}{2^6.25-2^6.3}=\frac{2^6.\left(18+2\right)}{2^6.\left(25-3\right)}=\frac{18+2}{25-3}=\frac{20}{22}=\frac{10}{11}\)