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2. 20-(x+14)=15
x+14=5
x=-11 ( vì x thuộc n , loại )
x thuộc rỗng
3.24+3(5-x)=27
3(5-x)=3
5-x=1
x=4 (chọn )
có 1+2+3+*\(⋮\)9
6+*\(⋮\)9
=>*=3
thay vào ta có
***.9=1233
***=137
Ta có: \(\overline{abc}.9=123\overline{d}\left(d< 9\right)\)
\(\Rightarrow123\overline{d}⋮9\)
\(\Rightarrow1+2+3+d⋮9\)
\(\Rightarrow6+d⋮9\)
\(\Rightarrow d=3\)
Với d=3, ta được: \(\overline{abc}.9=1233\)
\(\Rightarrow\overline{abc}=1233:9=137\)
~~Học tốt nha~~
a) 3571 - ( 1265 + x ) = 728 : 14
3571 - ( 1265 + x ) = 52
1265 + x = 3571 - 52
1265 + x = 3519
x = 3519 - 1265
x = 2254
b) ( 15 + 4x ) : 29 + 32 = 47
( 15 + 4x ) : 29 = 47 - 32
( 15 + 4x ) : 29 = 15
15 + 4x = 15 . 49
15 + 4x = 735
4x = 735 - 15
4x = 720
x = 180
\(2.3^x=10.3^{12}+8.27^4\)
\(2.3^x=10.3^{12}+8.\left(3^3\right)^4\)
\(2.3^x=10.3^{12}+8.3^{12}\)
\(2.3^x=3^{12}.18\)
\(2.3^x=3^{12}.3^2.2\)
\(2.3^x=2.3^{14}\)
\(\Rightarrow x=14\)
\(2.3^x=10.3^{12}+8.27^4\)
\(\Rightarrow 2.3^x=2.3^{12}.5+2.3^{12}.2^2\)
\(\Rightarrow 2.3^x=2.3^{12}.(5+2^2)\Rightarrow 2.3^x=2.3^{12}.9\)
\(\Rightarrow 2.3^x=2.3^{12}.3^2\Rightarrow 2.3^x=2.3^{14}\Rightarrow 3^x=3^{14}\Rightarrow x=14\)
k mk nha bạn!
1.1!+2.2!+3.3!+4.4!+5.5!
=(2-1).1!+(3-1).2!+(4-1).3!+
(5-1).4!+(6-1).5!
=2!-1!+3!-2!+4!-3!+5!-4!+6!-5!
=6!-1!=720-1=719
đặt A= 1+2+2^2+2^3+...+2^99+2^100
=>2A=2+2^2+2^3+...+2^100+2^101
=>2A‐A=2+2^+2^3+...+2^100+2^101 ‐﴾1+2+2 2+2 3+...+2 99+2 100 ﴿
=> A=2+2^2+2^3+...+2^100+2^101 ‐1‐2‐2^2 ‐2^3 ‐...‐2^99 ‐2^100
=2^101 ‐1
vậy 1+2+2^2+2^3+...+2^99+2^100
=2^101 ‐1
k nha
= -3 + (-3) + ..... + (-3) + 3001 [ có 500 số -3 ]
= 500. (-3) + 3001
= -1500 + 3001
= 1501
Tk mk nha
4-\(\dfrac{x}{5}\)=-3+\(\dfrac{-2x}{7}\)
x=\(\dfrac{-245}{3}\)
a) \(\dfrac{5^3.2.5.3^2.2^6}{5^4.3^2.2^{13}}=\dfrac{5^4.2^7.3^2}{5^4.3^2.2^{13}}=\dfrac{2^7}{2^{13}}=\dfrac{1}{64}\)
b) \(\dfrac{15^5.16^7}{12^5.20^5}=\dfrac{5^5.3^5.2^{28}}{2^{10}.3^5.2^{10}.5^5}=\dfrac{5^5.3^5.2^{28}}{2^{20}.3^5.5^5}=\dfrac{2^{28}}{2^{20}}=256\)
\(\dfrac{5^3.90.4^3}{25^2.3^2.2^{13}}=\dfrac{5^3.2.5.3^2.2^6}{5^4.3^2.2^{13}}=\dfrac{5^4.3^2.2^7}{5^4.3^2.2^{13}}=\dfrac{1}{2^6}=\dfrac{1}{64}\)
\(\dfrac{15^2.16^4.15^3.16^3}{12^2.20^3.20^2.12^3}=\dfrac{\left(3.5\right)^2.\left(2^4\right)^4.\left(3.5\right)^3.\left(2^4\right)^3}{\left(3.2^2\right)^2.\left(2^2.5\right)^3.\left(2^2.5\right)^2.\left(2^2.3\right)^3}=\dfrac{3^2.5^2.2^{16}.3^3.5^3.2^{12}}{3^2.2^4.2^6.5^3.2^4.5^2.2^6.3^3}=\dfrac{3^5.5^5.2^{28}}{3^5.5^5.2^{20}}=2^8=256\)
Mình đang cần gấp nên đánh nhầm chữ " HELP ME" . Rất xin lỗi các bn.
= 20+15
=35
Ê dễ màa :))