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\(\Rightarrow\left(3x+4\right)^3=-125=\left(-5\right)^3\\ \Rightarrow3x+4=-5\\ \Rightarrow3x=-9\\ \Rightarrow x=-3\)
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Thêm nữa câu a) Tính: M(x) + N(x)+ P(x)
B) Tính M(x) - N (x) - P(x)
ok rồi giúp mình với nha
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\(5^6.20^{-1}.2^2.\left(-3\right)^2:125=15625.\dfrac{1}{20}.4.9:125=225\)
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a) \(\left(\frac{1}{16}\right)^{25}\div\left(\frac{1}{2}\right)^{30}=\left(\frac{1}{2^4}\right)^{25}\div\left(\frac{1}{2}\right)^{30}=\left[\left(\frac{1}{2}\right)^4\right]^{25}\div\left(\frac{1}{2}\right)^{30}=\left(\frac{1}{2}\right)^{4.25}\div\left(\frac{1}{2}\right)^{30}\)
\(=\left(\frac{1}{2}\right)^{100}\div\left(\frac{1}{2}\right)^{30}=\left(\frac{1}{2}\right)^{100-30}=\left(\frac{1}{2}\right)^{70}\)
b) \(584^{100}\div292^{100}=\left(584-292\right)^{100}=292^{100}\)
c) \(125^4\cdot16^3=\left(5^3\right)^4\cdot\left(2^4\right)^3=5^{3\cdot4}\cdot2^{4\cdot3}=5^{12}\cdot2^{12}=\left(5+2\right)^{12}=7^{12}\)
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Bài làm :
\(\frac{125^6.3^{61}.8^{10}}{4^{15}.25^9.9^{30}}\)
\(=\frac{\left(5^3\right)^6.3^{61}.\left(2^3\right)^{10}}{\left(2^2\right)^{15}.\left(5^2\right)^9.\left(3^2\right)^{30}}\)
\(=\frac{5^{18}.3^{61}.2^{30}}{2^{30}.5^{18}.3^{60}}\)
\(=3\)
Học tốt nhé
Bài làm :
Ta có :
\(\frac{125^6.3^{61}.8^{10}}{4^{15}.25^9.9^{30}}\)
\(=\frac{\left(5^3\right)^6.3^{61}.\left(2^3\right)^{10}}{\left(2^2\right)^{15}.\left(5^2\right)^9.\left(3^2\right)^{30}}\)
\(=\frac{5^{18}.3^{61}.2^{30}}{2^{30}.5^{18}.3^{60}}\)
\(=\frac{3^{61}}{3^{60}}\)
\(=3\)
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\(b;2^6\times125^2=2^6\times5^6=\left(2\times5\right)^6=10^6=1000000\)
\(\left(3x-1\right)^3=125\\ \Rightarrow\left(3x-1\right)^3=5^3\\ \Rightarrow3x-1=5\\ \Rightarrow3x=5+1\\ \Rightarrow3x=6\\ \Rightarrow x=6:3\\ \Rightarrow x=2\)
Vậy \(x=2\)