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TA
1
5 tháng 1 2018
\(128^4=\left(2^7\right)^4=2^{28}=\left(2^5\right)^{5,6}=32^{5,6}\)
theo đề ta có
\(32^x< 128^4=32^{5,6}\Rightarrow x\in\left\{1;2;3;4;5\right\}\)
TH
3
AK
9 tháng 4 2018
Ta có :
\(1-80\%\le\frac{x}{100}< 2\%+\frac{1}{4}\)
\(\Rightarrow1-\frac{80}{100}\le\frac{x}{100}< \frac{2}{100}+\frac{25}{100}\)
\(\Rightarrow\frac{20}{100}\le\frac{x}{100}< \frac{27}{100}\)
\(\Rightarrow20\le x< 27\)
\(\Rightarrow x=\left\{20;21;...;26\right\}\)
Chúc bạn học tốt !!!
LA
24 tháng 1 2018
1) Ta có: x thuộc Z => 3+x thuộc Z => |3+x| thuộc N
Mà -3<|3+x|<3
Tức là : 0<|3+x|<3
- |3+x|=1 => 3+x= \(\pm1\orbr{\begin{cases}\Rightarrow3+x=1\Rightarrow x=-2\\\Rightarrow3+x=-1\Rightarrow x=-4\end{cases}}\)
- |3+x|=2 => 3+x= \(\pm2\orbr{\begin{cases}\Rightarrow3+x=2\Rightarrow-1\\\Rightarrow3+x=-2\Rightarrow-5\end{cases}}\)
Vậy x thuộc {-2;-4;-2;-5} thì -3<|3+x|<3
27 tháng 10 2018
a.
Ta có: x thuộc B(8) và x \(\le\)30
=> \(x\in\left\{x\inℕ;x⋮8;x\le30\right\}\)
=> \(x\in\left\{0;8;16;24\right\}\)
Vậy: ...........
b.
Ta có: \(4⋮x-1\)
\(\Rightarrow x-1\in B\left(4\right)=\left\{1;2;4\right\}\) ( vì \(x\inℕ\))
\(\Rightarrow x\in\left\{2;3;5\right\}\)
Vậy:...............
14 tháng 10 2018
Bo may la binh day k di hieu ashdbfgbgygygggydfsghuyfhdguuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu3
\(a,4\le2^x< 32\\ \Rightarrow2^2\le2^x< 2^5\\ \Rightarrow x\in\left\{2;3;4\right\}\)