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\(77^{33}=\left(11.7\right)^{33}=11^{33}.7^{33}=11^{33}.\left(7^3\right)^{11}=11^{33}.343\left(1\right)\)
\(33^{77}=\left(3.11\right)^{77}=3^{77}.11^{77}=\left(3^7\right)^{11}.11^{77}=2187^{11}.11^{77}\left(2\right)\)
Từ \(\left(1\right)+\left(2\right)\Leftrightarrow33^{77}>77^{33}\)
Ta có:\(33^{77}=3^{77}.11^{77}=\left(3^7\right)^{11}.11^{77}=2187^{11}.11^{77}\)
\(77^{33}=7^{33}.11^{33}=\left(7^3\right)^{11}.11^{33}=343^{11}.11^{33}\)
Do \(2188>343\Rightarrow2187^{11}>343^{11}\Rightarrow3^{77}>7^{33}\)
Lại có\(11^{77}>11^{33}\)
\(\Rightarrow33^{77}>77^{33}\)
Vậy\(33^{77}>77^{33}\)
77 . 25 + 5 . 77 + 77 . 14 + 33 . 77
= 77. ( 25 + 5 + 14 + 33 )
= 77 . 77
= 772
= 5929
~ Hok tốt ~
77 . 25 + 5 . 77 + 77 . 14 + 33 . 77
=77 . (25 + 5 + 14 + 33)
=77 . 77
=5929
Chúc bn học tốt! Kick cho mik nha!
77.(-7)-33.7-10.(-7)
=77.(-7)-(-33).(-7)-10.(-7)
=(-7).[77-(-33)-10]
=(-7).(77+33-10)=(-7).100=-700
77 . ( - 7 ) - 33 . 7 - 10 . ( - 7 )
=-539- 33 . 7 - 10 . ( - 7 )
=-539-231 - 10 . ( - 7 )
=-539-231 - (-70)
=-539-231 +70
=-770+70
=-700
\(=\left(-67\right).\left(-33\right)-67.77+\left(-67\right).33-77.33\)
\(=\left[\left(-67\right).\left(-33\right)+\left(-67\right).33\right]-66.77-77.33\)
\(=-77\left(66+33\right)=-77.99=-7623\)
a/ 3 + 2387 : 77 - 33
= 3 + 31 - 33
= 31 + ( 3 - 33)
= 31 + (-30)
= 1
b/ 8 x 33 x 25 x 125 x 4
= (8 x 125) x (4 x 25) x 33
= 1000 x 100 x 33
= 100000x 33
= 3300000
c/ 20, 16 : 0,01
= 2016 : 1
= 2016
Thêm :
D, 8,6 - 2,75
E, 4\(\frac{3}{8}\)+ 5\(\frac{2}{3}\)
F, 3\(\frac{1}{5}\)- 1\(\frac{1}{5}\)+ \(\frac{2}{5}\)
G, \(\frac{2}{5}\)+ \(\frac{3}{5}\): \(\frac{4}{5}\)
H, \(\frac{5}{2}\)x \(\frac{1}{3}\)+ \(\frac{1}{4}\)
3366+7755-2=(332)33+7754.77-2=A933+(772)27.77-2=A933+B927.77-2
=(...9)+[(...9).77]-2=(..9)+(...3)-2=(...2)-2=(...0).
Tận cùng 0 hoặc 5 thì chia hết cho 5.
Vậy 3366+7755-2 chia hết cho 5.
110
77 33 + 110