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1) 5(x - 2) + 27 = 4x - 8
=> 5x - 10 + 27 = 4x - 8
=> 5x + 17 = 4x - 8
=> 5x - 4x = -8 - 17
=> x = -25
2) 3(x + 1) + 2(x + 2) = -13
=> 3x + 3 + 2x + 4 = -13
=> 5x + 7 = -13
=> 5x = -13 - 7
=> 5x = -20
=> x = -20 : 5
=> x = -4
3) (2x + 4)(5 - x) = 0
=> \(\orbr{\begin{cases}2x+4=0\\5-x=0\end{cases}}\)
=> \(\orbr{\begin{cases}2x=-4\\x=5\end{cases}}\)
=> \(\orbr{\begin{cases}x=-2\\x=5\end{cases}}\)
Vậy ...
4) x2 - 3x = 0
=> x(x - 3) = 0
=> \(\orbr{\begin{cases}x=0\\x-3=0\end{cases}}\)
=> \(\orbr{\begin{cases}x=0\\x=3\end{cases}}\)
Vậy ...
5) x2 - 3x + 2 = 0
=> x(x - 3) = -2
=> x(x - 3) = 1 . (1 - 3)
=> x = 1
a. \(\frac{-3}{2}-2x+\frac{3}{4}=-22\)2
=> \(-2x=-22+\frac{3}{2}-\frac{3}{4}\)
=> \(-2x=\frac{-85}{4}\)
=> \(x=\frac{-85}{4}:\left(-2\right)\)
=> \(x=\frac{85}{8}\)
b. \(\left(\frac{-2}{3}x-\frac{3}{5}\right).\left(\frac{3}{-2}-\frac{10}{3}\right)=\frac{2}{5}\)
=> \(\left(\frac{-2}{3}x-\frac{3}{5}\right).\frac{-29}{6}=\frac{2}{5}\)
=> \(\frac{-2}{3}x-\frac{3}{5}=\frac{2}{5}:\left(\frac{-29}{6}\right)\)
=> \(\frac{-2}{3}x-\frac{3}{5}=\frac{-12}{145}\)
=> \(\frac{-2}{3}x=\frac{-12}{145}+\frac{3}{5}\)
=> \(\frac{-2}{3}x=\frac{15}{29}\)
=> x = \(\frac{15}{29}:\frac{-2}{3}\)
=> x = \(\frac{-45}{58}\)
a) 4 × (5 - x) = x
20 - 4x = x
x + 4x = 20
5x = 20
x = 20 : 5
x = 4
b) 1/2 (x - 14) = 2
x - 14 = 2 : 1/2
x - 14 = 4
x = 4 +14
x = 18
c) 18/13 + 3 × x = 3
3x = 3 - 18/13
3x = 21/13
x = 21/13 : 3
x = 7/13
d) đề khó hiểu
a ) 10 x X - 1 - 3 - 5 - 7 - ... - 19 = 2 + 4 + 6 + ... + 20
10 x X - 1 - 3 - 5 - 7 - ... - 19 = 110
10 x X - ( 1 + 3 + 5 + 7 + ... + 19 ) = 110
10 x X - 100 = 110
10 x X = 110 + 100
10 x X = 210
X = 210 : 10
X = 21
a) 2.(5 +3 .x) + x =31
10 + 6.x + x = 31
6x + x = 31-10
7x = 21
x = 21:7
x=3
Vậy x=3
b) ( 3x -7 ) +2 . (5-2x) + 5x = 19
3x - 7 + 10 - 4x + 5x = 19
3x - 4x + 5x = 19 + 7 - 10
4x = 16
x = 16:4
x = 4
Vậy x=4
\(a,2\left(5+3x\right)+x=31\)
\(10+6x+x=31\)
\(10+7x=31\)
\(7x=21\)
\(x=3\)
\(b,\left(3x-7\right)+2\left(5-2x\right)+5x=19\)
\(3x-7+10-4x+5x=19\)
\(4x+3=19\)
\(4x=16\)
\(x=4\)
\(\frac{3x}{2}-\frac{1}{3}=\frac{2}{5}+x\)
\(\frac{3x}{2}-x=\frac{2}{5}+\frac{1}{3}\)
\(x.\left(\frac{3}{2}-1\right)=\frac{11}{15}\)
\(x.\frac{1}{2}=\frac{11}{15}\)
x = \(\frac{11}{15}:\frac{1}{2}\)
x =\(\frac{22}{15}\)
3x/2-1/3=2/5+x
3x/2-x=2/5+1/3
1/2x=11/15
x=11/15:1/2
x=22/15
đúng-**** cho mk nha!!!
a) x= \(\frac{-5}{12}\)
b) x = \(\frac{2}{5}\)
c) x =\(\frac{-87}{140}\)
d) x = \(\frac{109}{140}\)
e) x = \(\frac{13}{63}\)
\(\frac{3x}{2}-\frac{1}{3}=\frac{2}{5}-x\)
\(< =>\frac{9x-2}{6}=\frac{2-5x}{5}\)
\(< =>\left(9x-2\right)5=\left(2-5x\right)6\)
\(< =>45x-10=12-30\)
\(< =>45x+30x=12+10=22\)
\(< =>x=\frac{22}{75}\)
x-5=5/3:2/3
x-5=2,5
x=2,5+5
x=7,5
2/3 x ( x -5 ) = 5/3
x - 5 = 5/3 : 2/3
x - 5 = 5/2
x = 5/2 + 5
x = 15/2
Vay x = 15/2