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Tìm x, biết:
3(x+2)(x+5) +5(x+5)(x+10) +7(x+10)(x+17) =x(x+2)(x+17) (x∉−2;−5;−10;−17)
2(x−1)(x−3) +5(x−3)(x−8) +12(x−8)(x−20) −1x−20 =−34 (x∉1;3;8;20)
x+110 +2+111 x+112 =x+113 +x+114
x−1030 +x−1443 +x−595 +x−1488 =0
\(A=49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
\(A=49\frac{8}{23}-5\frac{7}{32}+14\frac{8}{23}\)
\(A= \left(49\frac{8}{23}-14\frac{8}{23}\right)-5\frac{7}{32}\)
\(A=\left[\left(49-14\right)-\left(\frac{8}{23}-\frac{8}{23}\right)\right]-5\frac{7}{32}\)
\(A=\left[35-0\right]-5\frac{7}{32}\)
\(A=35-5\frac{7}{32}\)
\(A=\frac{953}{32}\)
\(B=71\frac{38}{45}-\left(43\frac{38}{45}-1\frac{17}{57}\right)\)
\(B=71\frac{38}{45}-\frac{36377}{855}\)
\(B=\frac{1670}{57}\)
\(C=\left(19\frac{5}{8}:\frac{7}{12}-13\frac{1}{4}:\frac{7}{12}\right):\frac{4}{5}\)
\(C=\left[\left(19\frac{5}{8}-13\frac{1}{4}\right):\frac{7}{12}\right]:\frac{4}{5}\)
\(C=\left[\frac{51}{8}:\frac{7}{12}\right]:\frac{4}{5}\)
\(C=\frac{153}{14}:\frac{4}{5}\)
\(C=\frac{765}{56}\)
\(D=\left[\left(\frac{10}{15}-\frac{2}{3}\right):\frac{1}{7}\right]\cdot0,15-\frac{1}{4}\)
\(D=\left[0:\frac{1}{7}\right]\cdot\frac{3}{20}-\frac{1}{4}\)
\(D=0\cdot\frac{3}{20}-\frac{1}{4}\)
\(D=0-\frac{1}{4}\)
\(D=-\frac{1}{4}\)
\(E=\frac{13}{30}+\frac{28}{45}\cdot2\frac{1}{2}-\left[\left(\frac{1}{2}+\frac{1}{3}\right):\frac{53}{90}\right]:\frac{50}{53}\)
\(E=\frac{13}{30}+\frac{28}{45}\cdot\frac{5}{2}-\left[\frac{5}{6}:\frac{53}{90}\right]:\frac{50}{53}\)
\(E=\frac{13}{30}+\frac{28}{45}\cdot\frac{5}{2}-\frac{75}{53}:\frac{50}{53}\)
\(E=\frac{13}{30}+\frac{14}{9}-\frac{3}{2}\)
\(\)\(E=\frac{22}{45}\)
CHUC BAN HOC TOT >.<
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a} đây là biểu thức gì\)
a,\(\frac{31}{1000}\)
b,\(\frac{8}{108}\)
c,0
a,\(\frac{49}{97}\)
b,\(\frac{-1}{4751}\)
1) \(\frac{4}{7}-\frac{1}{14}+\left|\frac{-5}{21}\right|\)
\(=\frac{4}{7}-\frac{1}{14}+\frac{5}{21}\)
\(=\frac{24}{42}-\frac{3}{42}+\frac{10}{42}\)
\(=\frac{31}{42}\)
2) \(\left|\frac{-2}{3}\right|-\frac{1}{2}+3\)
\(=\frac{2}{3}-\frac{1}{2}+\frac{3}{1}\)
\(=\frac{4}{6}-\frac{3}{6}+\frac{18}{6}\)
\(=\frac{19}{6}\)
3) \(\left|\frac{7}{-4}\right|-\frac{5}{8}+\frac{-2}{3}\)
\(=\frac{7}{4}-\frac{5}{8}+\frac{-2}{3}\)
\(=\frac{42}{24}-\frac{15}{24}+\frac{-16}{24}\)
\(=\frac{11}{24}\)
4) \(\frac{4}{5}+\left|\frac{-3}{2}\right|+\frac{1}{-4}\)
\(=\frac{4}{5}+\frac{3}{2}+\frac{-1}{4}\)
\(=\frac{16}{20}+\frac{30}{20}+\frac{-5}{20}\)
\(=\frac{41}{20}\)
5) \(\left|\frac{-1}{4}\right|-3+\frac{3}{4}\)
\(=\frac{1}{4}-\frac{3}{1}+\frac{3}{4}\)
\(=\frac{1}{4}-\frac{12}{4}+\frac{3}{4}\)
\(=-2\)
6) \(\left|\frac{-1}{3}\right|-\frac{5}{4}+\frac{1}{5}\)
\(=\frac{1}{3}-\frac{5}{4}+\frac{1}{5}\)
\(=\frac{20}{60}-\frac{75}{60}+\frac{12}{60}\)
\(=\frac{-43}{60}\)
\(=\frac{1}{3}+\frac{1}{7}-\frac{1}{2}+\frac{1}{6}=\left(\frac{1}{3}-\frac{1}{2}\right)+\frac{1}{6}+\frac{1}{7}=\frac{-1}{6}+\frac{1}{6}+\frac{1}{7}=0+\frac{1}{7}=\frac{1}{7}\)