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9 tháng 7 2016

\(a^6-a^4+2a^3+2a^2\)

\(=\left[\left(a^3\right)^2-\left(a^2\right)^2\right]+2\left(a^2+a^3\right)\)

\(=\left(a^3-a^2\right)\left(a^3+a^2\right)+2\left(a^3+a^2\right)\)

\(=\left(a^3-a^2+2\right)\left(a^3+a^2\right)\)

\(=a^2.\left(a^3-a^2+2\right)\left(a+1\right)\)

9 tháng 7 2016

\(a^6-a^4+2a^3+2a^2=a^2\left(a^4-a^2+2a+2\right)=a^2\left[a^2\left(a^2-1\right)+2\left(a+1\right)\right]\)

\(=a^2\left[a^2\left(a-1\right)\left(a+1\right)+2\left(a+1\right)\right]=a^2\left(a+1\right)\left(a^3-a^2+2\right)=a^2\left(a+1\right)^2\left(a^2-2a+2\right)\)

13 tháng 10 2016

a) = (xyz+xy) +(z+1) +(yz+zx)+(x+y)

 = xy(z+1) +(z+1)+z(x+y)+(x+y)

= (z+1)(xy+1)+(x+y)(Z+1)

=(z+1)(xy+1+x+y)

20 tháng 8 2017

dễ mà bn

mk bk lm mà lm biếng gõ qá

9 tháng 8 2015

a)27x3+27x2+9x+1+x+1/3

=(3x+1)3+1/3(3x+1)

=(3x+1)[(3x+1)2+1/3]

=(3x+1)(9x2+6x+4/3)

b)8xy3-5xyz-24y2+15z

=(8xy3-24y2)-(5xyz-15z)

=8y2(xy-3)-5z(xy-3)

=(xy-3)(8y2-5z)

c)x4+x3+x+1

=x3(x+1)+(x+1)

=(x+1)(x3+1)

=(x+1)(x+1)(x2-x+1)

=(x+1)2(x2-x+1)

d)a6-a4-2a3+2a2

=a4(a-1)(a+1)-2a2(a-1)

=(a-1)(a5+a4-2a2)

=(a-1)(a5-a4+2a4-2a2)

=(a-1)[a4(a-1)+2a2(a-1)(a+1)]

=(a-1)(a-1)(a4+2a3+2a2)

=(a-1)2(a4+2a3+2a2)

3 tháng 9 2018

\(x^4+x^3+x+1\)

\(=x^3\left(x+1\right)+\left(x+1\right)\)

\(=\left(x+1\right)\left(x^3+1\right)\)

\(=\left(x+1\right)^2\left(x^2-x+1\right)\)

10 tháng 8 2016

a)\(\left(a^3-b^3\right)+\left(a-b\right)^2\)

\(=\left(a-b\right)\left(a^2+ab+b^2\right)+\left(a-b\right)^2\)

\(\left(a-b\right)\left(a^2+ab+b^2+a-b\right)\)

b) \(\left(8a^3-27b^3\right)-2a\left(4a^2-9b^2\right)\)

\(=\left(2a-3b\right)\left(4a^2+6ab+9b^2\right)-2a\left(2a-3b\right)\left(2a+3b\right)\)

\(=\left(2a-3b\right)\left(4a^2+6ab+9b^2-4a^2-6ab\right)\)

\(=\left(2a-3b\right)\cdot9b^2\)

 

 

10 tháng 8 2016

\(=\left(a-b\right)\left(a^2+ab+b^2\right)+a^2-2ab+b^2\)

= ...........

24 tháng 8 2016

2a2b2+2a2c2+2b2c2-a4-b4-c4

=4a2b2-(a4+2a2b2+b4)+(2b2c2+2a2c2)-c4

=2(ab)2-(a+b)2+2c2(a2+b2)+c4

=2(ab)2-[(a+b)2-2c2(a2+b2)+c4]

=2(ab)2-(b2+a2-c2)2

=[(a+b)2-c2][-(a-b)2+c2]

=(a+b-c)(a+b+c)(c-a+b)(a+c-b)

 

25 tháng 8 2016

\(2a^2b^2+2a^2c^2+2b^2c^2-a^4-b^4-c^4\)

\(=4a^2b^2-\left(a^4+2a^2b^2+b^4\right)+\left(2b^2c^2+2a^2c^2\right)-c^4\)

\(=2\left(ab\right)^2-\left(a+b\right)^2+2c^2\left(a^2+b^2\right)+c^4\)

\(=2\left(ab\right)^2-\left[\left(a+b\right)^2-2c^2\left(a^2+b^2\right)+c^4\right]\\ =2\left(ab\right)^2-\left(b^2+a^2-c^2\right)^2\)

=\(\left[\left(a+b\right)^2-c^2\right]\left[-\left(a-b\right)^2+c^2\right]\\ =\left(a+b+c\right)\left(a+b+c\right)\left(c-a+b\right)\left(a+c-b\right)\)

24 tháng 8 2021

Sửa ý đầu: \(\left(2a+3\right)x-\left(2a+3\right)y+2a+3\)

\(=\left(2a=3\right)\left(x-y+1\right)\)

\(\left(a-b\right)c+\left(b-a\right)y-a+b\)

\(=\left(a-b\right)c-\left(a-b\right)y-\left(a-b\right)\)

\(=\left(a-b\right)\left(c-y-1\right)\)

\(81a^2+18a+1\)

\(=\left(9a+1\right)^2\)

\(a^3-1\)

\(=\left(a-1\right)\left(a^2+a+1\right)\)

\(a^5-b^5\)

Áp dụng công thức: \(a^{2n+1}-b^{2n+1}=\left(a-b\right)\left(a^{2n}+a^{2n-1}.b+...+b^{2n-1}.a+b^{2n}\right)\)

\(=\left(a-b\right)\left(a^4+a^3b+a^2b^2+ab^3+b^{\text{4}}\right)\)

2 tháng 7 2017

a(a+2b)3 -b(2a+b)3

\(=a\left(a^3+6a^2b+12ab^2+8b^3\right)-b\left(8a^3+12a^2b+6ab^2+b^3\right)\)

\(=a^4+6a^3b+12a^2b^2+8ab^3-8a^3b-12a^2b^2-6ab^3-b^4\)

\(=a^4-2a^3b+2ab^3-b^4\)

\(=\left[\left(a^2\right)^2+ \left(b^2\right)^2\right]-2ab\left(a^2-b^2\right)\)

\(=\left(a^2+b^2\right)\left(a^2-b^2\right)-2ab\left(a^2-b^2\right)\)

\(=\left(a^2-b^2\right)\left(a^2-2ab+b^2\right)\)

\(=\left(a-b\right)\left(a+b\right)\left(a-b\right)^2\)

\(=\left(a-b\right)^3\left(a+b\right)\)

13 tháng 9 2019

\(2\left(x-3\right)^3-4\left(3-x\right)^2-x+3\)

\(=2\left(x-3\right)^3-4\left(x-3\right)^2-\left(x-3\right)\)

\(=\left(x-3\right)\left[2\left(x-3\right)^2-4\left(x-3\right)-1\right]\)

\(=\left(x-3\right)\left[2\left(x^2-6x+9\right)-4x+12-1\right]\)

\(=\left(x-3\right)\left[2x^2-12x+18-4x+11\right]\)

\(=\left(x-3\right)\left[2x^2-16x+29\right]\)

\(ab\left(a-b\right)-2a+2b\)

\(=ab\left(a-b\right)-2\left(a-b\right)\)

\(=\left(ab-2\right)\left(a-b\right)\)