Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a: =2008(1+347+752)
=2008*1100
=2208800
b: 125*199*25*8*4
=125*8*25*4*199
=199*1000*100
=199000000
c: =36*(28+45)
=36*73=2628
d: 226*374+277*26
=84524+7202
=91726
`a)2008+2008*347+752*2008`
`=2008*(1+347+752)`
`=2008*1100`
`=2208800`
`125*199*25*8*4`
`=(125*8)*(4*25)*199`
`=1000*100*199`
`=19900000`
`c)226*374+277*26`
`=84524 + 7202`
`=91726`
bn tách ra a, b, c cho dễ nhìn nhé .
Số số chẵn từ 2 đến 2008 là:
[2008-2] : 2 +1 = 1004 [số]
(x+2)+(x+4)+......(x+2008)=1012024
=> 1004.x + 2+4+6+...+2008 = 1012024
=> 1004.x + 1004:2 x [2+2008] = 1012024
=> 1004.x + 1009020 = 1012024
=> 1004.x = 3004
=> x= 751/251
\(\frac{2006}{2008}\times\frac{2001}{2004}\times\frac{2008}{2002}\times\frac{2004}{2006}\times\frac{1001}{2001}=\frac{2006.2001.2008.2004.1001}{2008.2004.2002.2006.2001}\)
\(=\frac{\left(2001.2004.2006.2008.\right).1001}{\left(2001.2004.2006.2008\right).2002}=\frac{1001}{2002}=\frac{1001.1}{1001.2}=\frac{1}{2}\)
a)=1/2*2/3......*19/20
=1/20
b)=3/2*4/3......*2008/2007
=3/2007
Tìm x:
\(a.\frac{2}{3}+x=\frac{5}{7}+\frac{7}{17}\div\frac{49}{34}\)
\(\frac{2}{3}+x=1\)
\(x=1-\frac{2}{3}\)
\(x=\frac{1}{3}.\)
\(b.x-\frac{4}{6}+\frac{5}{9}=\frac{28}{45}\)
\(x-\frac{4}{6}=\frac{28}{45}-\frac{5}{9}\)
\(x-\frac{4}{6}=\frac{1}{15}\)
\(x=\frac{1}{15}+\frac{4}{6}\)
\(x=\frac{11}{15}.\)
\(c.x\div\frac{6}{7}+\frac{2}{3}=\frac{7}{3}\)
\(x\div\frac{6}{7}=\frac{7}{3}-\frac{2}{3}\)
\(x\div\frac{6}{7}=\frac{5}{3}\)
\(x=\frac{5}{3}\times\frac{6}{7}\)
\(x=\frac{30}{21}.\)
\(d.\frac{15}{21}\div x=\frac{3}{7}+\frac{2008}{2009}\times\frac{2000}{2008}+\frac{9}{2008}\times\frac{2008}{2009}\)
\(\frac{5}{7}\div x=\frac{10}{7}\)
\(x=\frac{10}{7}\times\frac{5}{7}\)
\(x=\frac{50}{49}.\)
. là x á nha
=\(\frac{2006}{2008}.\frac{2001}{2004}.\frac{2008}{2002}.\frac{2004}{2006}.\frac{1001}{2001}\)
=\(\frac{2006.2001.2008.2004.1001}{2008.2004.2002.2006.2001}\)
=\(\frac{1001}{2002}\)
= \(\frac{2006\cdot2001\cdot2008\cdot2004\cdot1001}{2008\cdot2004\cdot2002\cdot2006\cdot2001}\)
= \(\frac{1\cdot1\cdot1\cdot1\cdot1001}{1\cdot1\cdot2002\cdot1\cdot1}\)
= \(\frac{1}{2}\)
x + x*4 = 2008
x*5 = 2008
x = 2008/5
Đáp án là 251 bạn nhé!
X + X x 4 = 2008
X + X = 2008 : 4
X + X = 502
2X = 502
X = 502 : 2
X = 251