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1. \(x-8+32=68\)
\(x-8=68-32\)
\(x-8=36\)
\(x=36+8\)
\(x=44\)
_____
2. \(x+8+32=68\)
\(x+8=68-32\)
\(x+8=36\)
\(x=36-8\)
\(x=28\)
_____
3. \(98-x+34=43\)
\(98-x=43-34\)
\(98-x=9\)
\(x=98-9\)
\(x=89\)
_____
4. \(98+x-34=43\)
\(98+x=43+34\)
\(98+x=77\)
\(x=77-98\)
\(x=-21\)
_____
5. \(x:5:4=800\)
\(x:5=800.4\)
\(x:5=3200\)
\(x=3200.5\)
\(x=16000\)
_____
6. \(18+x=384:8\)
\(18+x=48\)
\(x=48-18\)
\(x=30\)
_____
7. \(\left(84,6-2\times x\right):3,02=5,1\)
\(84,6-2.x=5,1.3,02\)
\(84,6-2.x=15,402\)
\(2.x=84,6-15,402\)
\(2.x=69,198\)
\(x=69,198:2\)
\(x=34,599\)
_____
8. \(x\times5=120:6\)
\(x.5=20\)
\(x=20:5\)
\(x=4\)
_____
9. \(\left(15\times24-x\right):0,25=100:0,25\)
\(\left(15.24-x\right):0,25=400\)
\(15.24-x=400.0,25\)
\(15.24-x=100\)
\(360-x=100\)
\(x=360-100\)
\(x=260\)
1,x-8+32=68
=>x-8=68-32=36
=>x=36+8=42
2,x+8+32=68
=>x+8=68-32=36
=>x=36-8=28
3,98-x+34=43
=>98-x=43-34=9
=>x=98-9=89
4,98+x-34=43
=>98+x=43+34=77
=>x=77-98=-21
5,x:5:4=800
=>x:20=800
=>x=800x20=16000
6,18+x=384:8=48
=>x=48-18=30
7,(84,6-2x):3,02=5,1
=>84,6-2x=5,1x3,02=15,402
=>2x=84,6-15,402=69,198
=>x=69,198:2=34,599
8,5x=120:6=20
=>x=20:5=4
9,(15x24-x):0,25=100:0,25=400
=>360-x=400x0,25=100
=>x=360-100=260.
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\(A=\frac{34}{7.13}+\frac{51}{13.22}+\frac{85}{22.37}+\frac{68}{37.49}\)
\(=\frac{17.2}{7.13}+\frac{17.3}{13.22}+\frac{17.5}{22.37}+\frac{17.4}{37.49}\)
\(=17\left(\frac{2}{7.13}+\frac{3}{13.22}+\frac{5}{22.37}+\frac{4}{37.49}\right)\)
\(=\frac{17}{3}\left(\frac{6}{7.13}+\frac{9}{13.22}+\frac{15}{22.37}+\frac{12}{37.49}\right)\)
\(=\frac{17}{3}\left(\frac{1}{7}-\frac{1}{13}+\frac{1}{13}-\frac{1}{22}+...+\frac{1}{37}-\frac{1}{49}\right)\)
\(=\frac{17}{3}\left(\frac{1}{7}-\frac{1}{49}\right)\)\(=\frac{17}{3}.\frac{6}{49}=\frac{17.2}{49}=\frac{34}{49}\)
Có : \(\frac{17}{24}=\frac{34}{48}\)
Vì 48 < 49 => \(\frac{34}{48}>\frac{34}{49}\). Hay \(\frac{17}{24}>A\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(30-34\right)+x.\left(68-78\right)=78\)
\(-4+x.\left(-10\right)=78\)
\(-4-10x=78\)
\(10x=-4-78\)
\(10x=-82\)
\(x=-8,2\)
Vậy \(x=-8,2\)
Anh Nam rảnh ko dạy em môn Tiếng Anh với có 1 câu khó
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34 - (x + 68) = 23 . 30
34 - (x + 68) = 8 . 1
34 - (x + 68) = 8
x + 68 = 34 - 8
x + 68 = 26
x = 26 - 68
x = -42
2x - 1 + 3 = 4
2x - 1 =4 - 3
2x - 1 = 1
2x = 1 + 1
2x = 2
2x = 21
Vậy x = 1
mik nhah nhất nha
a) 34 - ( x + 68 ) = 2 ^ 3 x 3 ^ 0
34 - ( x + 68 ) = 8 x 1
34 - ( x + 68 ) = 8
x +68 = 34 - 8
x + 68 = 26
x = 26 - 68
x = -42
Vậy x =-42
2 ^ x - 1 + 3 = 4
2 ^ x - 1 + 3 = 2 ^ 2
=> x - 1 + 3 = 2
x - 1 = 2 - 3
x - 1 = - 1
x = - 1 + 1
x = 0
Vậy x = 0
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=-(23.3.4.7)=-1932
=2.8.14.3=672
=-(34+26+91+99)=-250
=82+(-120)=-(120-82)=-38
=20.(-4)+31.(-20)=20.(-4-31)=20.(-35)=-700
=125+/-25/=125+25=150
=26+34=60
=(-275) +115=-160
=(-34)+34=0
=-18.31-28.(-24)=-555+672=114
![](https://rs.olm.vn/images/avt/0.png?1311)
a) ( - 127 ) . 57 + ( - 127 ) . 43
= ( - 127 ) . ( 57 + 43 )
= ( - 127 ) . 100
= - 12 700
b) - 13 . 34 - 8 . 34
= ( - 13 - 8 ) . 34
= - 21 . 34 = - 714
c) ( - 25 ) . 68 + ( - 34 ) . ( - 250 )
= ( - 25 ) . 68 + ( - 340 ) . ( - 25 )
= ( - 25 ) . [ 68 + ( - 340 ) ]
= ( - 25 ) . - 272
= 6800
d) Mk ko bt
\(a,\left(-127\right).57+\left(-127\right).43\)
\(=\left(-127\right).\left(57+43\right)\)
\(=\left(-127\right).100\)
\(=-12700\)
\(b,-13.34-87.34\)
\(=34.\left(-13-87\right)\)
\(=34.\left(-100\right)\)
\(=-3400\)
\(c,\left(-25\right).68+\left(-34\right).\left(-250\right)\)
\(=\left(-25\right).68+\left(-34\right).10.\left(-25\right)\)
\(=\left(-25\right).68+\left(-340\right).\left(-25\right)\)
\(=\left(-25\right).\left(68-340\right)\)
\(=\left(-25\right).\left(-272\right)\)
\(=6800\)
![](https://rs.olm.vn/images/avt/0.png?1311)
12.68+34.18-34-142
12.2.34+34.18-34.1-142
=24.34+34.18-34.1-142
=34.(24+18-1)-142
=34.41-142
=1394-142
=1252
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x + 7 = 68 : 34
x + 7 = 2
x = 2 - 7
x = -5
---> x + 7 = 68 : 34
---> x + 7 = 2
---> x = - 5
xin tiick