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Trả lời
x:(1/2+1/3+1/6)=2019
x:6/6 =2019
x:1 =2019
=>x =2019.1
=>x =2019
Học tốt !
x : (\(\frac{1}{2}\)+ \(\frac{1}{3}\)+ \(\frac{1}{6}\)) = 2019
x : 1 = 2019
x = 2019
C=(1x3+3x5+...+99x101)+(2x4+4x6+...+98x100)
đặt S=1x3+3x5+...+99x101
=>6S=6x(1x3+3x5+...+99x101)
=1x3x(5+1)+3x5x(7-1)+...+97x99x(101-95)+99x101x(103-97)
=1x3x5+1x3x1+3x5x7-1x3x5+....+97x99x101-95x97x99+99x101x103-97x99x101
=1x3x1+99x101x103
=>S=(3+99x101x103):6=171650
=>C=171650+(2x4+4x6+...+98x100)
đặt A=2x4+4x6+...+98x100
=>6A=6x(2x4+4x6+...+98x100)
=>6A=2x4x6+4x6x(8-2)+...+96x98x(100-94)+98x100x(102-96)
=2x4x6+4x6x8-2x4x6+...+96x98x100-94x96x98+98x100x102-96x98x100
=98x100x102
=>A=98x100x102:6=166600
=>C=166600+171650
=>C=338250
B=2x2+4x4+6x6+...+100x100
=2x(4-2)+4x(6-2)+6x(8-2)+...+100x(102-2)
=2x4-4+4x6-8+6x8-12+...+100x102-200
=(2x4+4x6+6x8+...+100x102)-(4+8+12+...+200)
đặt A=2x4+4x6+...+98x100+100x102
=>6A=6x(2x4+4x6+...+98x100+100x102)
=>6A=2x4x6+4x6x(8-2)+...+96x98x(100-94)+98x100x(102-96)+100x102x(104-98)
=2x4x6+4x6x8-2x4x6+...+96x98x100-94x96x98+98x100x102-96x98x100+100x102x104-98x100x102
=100x102x104
=>A=100x102x104:6=176800
=>B=176800-(4+8+12+...+200)
đặt S=4+8+12+..+200
Số số hạng của S là:
(200-4):4+1=50 số
S=(200+4)x50:2=5100
=>B=176800-5100
=>B=171700
1)\(25x+3\left(4-6x\right)=50\)
\(25x+12-18x=50\)
\(7x+12=50\)
\(7x=38\)
\(x=\frac{38}{7}\)
2)\(4\left(2x+3\right)+2\left(3x+1\right)=120\)
\(8x+12+6x+2=120\)
\(14x+14=120\)
\(14x=106\)
\(x=\frac{53}{7}\)
\(\frac{\left|x-1\right|}{-8}=-\frac{3}{4}\)
=> |x - 1|.4 = (-8) . (-3)
=> |x - 1| . 4 = 24
=> |x - 1| = 24 : 4
=> |x - 1| = 6
=> \(\orbr{\begin{cases}x-1=6\\x-1=-6\end{cases}}\)
=> \(\orbr{\begin{cases}x=7\\x=-5\end{cases}}\)
Vậy ...
|2 - x| - 7 = 6/-2
=> |2 - x| = -3 + 7
=> |2 - x| = 4
=> \(\orbr{\begin{cases}2-x=4\\2-x=-4\end{cases}}\)
=> \(\orbr{\begin{cases}x=-2\\x=6\end{cases}}\)
vậy ...
\(\frac{-2}{1-x}=\frac{1-x}{-8}\)
=> (-2).(-8) = (1 - x).(1 - x)
=> (1 - x)2 = 16
=> (1 - x)2 = 42
=> \(\orbr{\begin{cases}1-x=4\\1-x=-4\end{cases}}\)
=> \(\orbr{\begin{cases}x=-3\\x=5\end{cases}}\)
Vậy ...
còn lại tự lm tương tự
\(\frac{x}{6}=\frac{1}{2}+\frac{1}{3}.\frac{3}{4}\)
<=> \(\frac{x}{6}=\frac{1}{2}+\frac{3}{12}\)
<=>\(\frac{x}{6}=\frac{1}{2}+\frac{1}{4}\)
<=>\(\frac{x}{6}=\frac{2}{4}+\frac{1}{4}\)
<=>\(\frac{x}{6}=\frac{3}{4}\)
<=>\(x=\frac{3}{4}.6\)
<=>\(x=\frac{9}{2}\)
kl:
k minh di mink giai cho de lam