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a) x2 + y2 +2x - 4y + 5 = 0
( x2 + 2x + 1 ) + ( y2 - 4y + 4 ) = 0
( x + 1 )2 + ( y - 2 )2 = 0
\(\Rightarrow\left\{{}\begin{matrix}x+1=0\\y-2=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=-1\\y=2\end{matrix}\right.\)
b) \(x^2+4y^2-x-4y+\dfrac{5}{4}=0\)
\(x^2-x+\dfrac{1}{4}+4y^2-4y+1=0\)
\(\left(x-\dfrac{1}{2}\right)^2+\left(2y-1\right)^2=0\)
\(\Rightarrow\left\{{}\begin{matrix}x-\dfrac{1}{2}=0\\2y-1=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=\dfrac{1}{2}\\y=\dfrac{1}{2}\end{matrix}\right.\)

a)x3-6x2+9x=x(x2-6x+9)=x(x-3)2
b)x2-2x-4y2-4y=(x2-2x+1)-(4y2+4y+1)=(x-1)2-(2y+1)2=(x-1-2y-1)(x-1+2y+1)=(x-2y-2)(x+2y)
c)x2-x+xy-y=x(x-1)+y(x-1)=(x-1)(x+y)
d)3x2-6xy-75+3y2=3[(x2-2xy+y2)-25]=3[(x-y)2-52]=3(x-y-5)(x-y+5)
e)2x2-5x-7=(2x2+2x)-(7x+7)=2x(x+1)-7(x+1)=(x+1)(2x-7)
f)x4+36=x4+12x2+36-12x2=(x2+6)2-12x2=(x2-\(\sqrt{12}x\)+6)(x2+\(\sqrt{12}x\)+6)
h)x4+4y4=x4+4x2y2+4y2-4x2y2=(x2+2y2)-4x2y2=(x2+2y2-2xy)(x2+2y2+2xy)


a) x2- 2x - 4y2 - 4y = (x2 - 2x + 1) - (4y2 + 4y + 1) = (x - 1)2 - (2y + 1)2 = (x - 1 - 2y - 1)(x - 1 + 2y + 1) = (x - 2y - 2)(x + 2y)
b) x3 - 4x2 + 12x - 27 = (x3 - 3x2) - (x2 - 3x) + (9x - 27) = x2(x - 3) - x(x - 3) + 9(x - 3) = (x2 - x + 9)(x - 3)
d) x4 - 2x3 + 2x - 1 = (x4 - 2x3 + x2) - (x2 - 2x + 1) = (x2 - x)2 - (x - 1)2 = (x2 - x - x + 1)(x2 - x + x - 1)
= (x2 - 2x + 1)(x2 - 1) = (x - 1)2(x - 1)(x + 1) = (x - 1)3(x + 1)
e) x4 + 2x3 - 4x - 4 = (x4 + 2x4 + x2) - (x2 + 4x + 4) = (x2 + x)2 - (x + 2)2 = (x2 + x - x - 2)(x2 + x + x + 2) = (x2 - 2)(x2 + 2x + 2)



\(1,\)
\(x^2-2x-4y^2-4y\)
\(=\left(x-2y\right)\left(x+2y\right)-2\left(x+2y\right)\)
\(=\left(x+2y\right)\left(x-2y-2\right)\)
\(2,\)
\(x^4+2x^3-4x-4\)
\(=\left(x^2-2\right)\left(x^2+2\right)+2x\left(x^2-2\right)\)
\(=\left(x^2-2\right)\left(x^2+2x+2\right)\)
\(3,\)
\(3x^2-3y^2-2\left(x-y\right)^2\)
\(=3\left(x^2-y^2\right)-2\left(x-y\right)^2\)
\(=3\left(x-y\right)\left(x+y\right)-2\left(x-y\right)\)
\(=\left(x-y\right)[3\left(x+y\right)-2\left(x-y\right)]\)
\(=\left(x-y\right)\left(3x+3y-2x+2y\right)\)
\(=\left(x-y\right)\left(x+5y\right)\)
\(4,\)
\(x^2-y^2-2x+2y\)
\(=x^2-y^2-2x+2y\)
\(=\left(x-y\right)\left(x+y\right)-2\left(x-y\right)\)
\(=\left(x-y\right)\left(x+y-2\right)\)

đề bảo lm gì thế bn
\(x^4+2x-4y^2-4y\)
\(=\left(x^2-4y\right)-\left(2x-4y\right)\)
\(=x^2-\left(2y^2\right)-\left(2x-4y\right)\)
\(=\left[\left(x+2y\right).\left(x-2y\right)\right]-2\left(x+2y\right)\)
\(=\left(x+2y\right).\left(x-2y-2\right)\)