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*) 2x-5=-x-17
<=> 2x-5+x+17=0
<=> 3x+12=0
<=> 3x=-12
<=> x=-4
*) Ta có 2x-3=2(x+1)-5
=> 5 chia hết cho x+1
=> x+1 C Ư(5)={-5;-1;1;5}
Ta có bảng
x+1 | -5 | -1 | 1 | 5 |
x | -6 | -2 | 0 | 4 |
B1.
2x - 5 = -x - 17
2x + x = -17 + 5
3x = -12
x = (-12) : 3
x = -4
Vậy x = -4
B2.
x + 1 là ước của 2x - 3
2x - 3 chia hết cho x + 1
( 2x + 2 ) - 5 chia hết cho x + 1
2( x + 1 ) - 5 chia hết cho x + 1
Vì x + 1 chia hết cho x + 1
nên 2(x+1) chia hết cho x + 1
Suy ra: 5 chia hết cho x + 1
Suy ra: x + 1 thuộc { 1; -1; 5; -5 }
Suy ra: x thuộc { 0 ; -2 ; 4; -6 }
Vậy x thuộc { 0 ; -2 ; 4; -6 }
Hok tốt !
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Bài 2:Tìm số nguyên x
a,x-2=-6+17
=> x-2= 11
=> x = 11 + 2
=> x = 13
b,x+2=-9
=> x = -9 - 2
=> x = -11
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ta có \(3x+6=3\left(x+1\right)+3\) chia hết cho x +1 khi 3 chia hết cho x +1
hay ta có \(x+1\in\left\{\pm1,\pm3\right\}\Leftrightarrow x\in\left\{-4,-2,0,2\right\}\)
\(x+2=x-15+17\) chia hết cho x- 15 khi 17 chia hết cho x -15
hay ta có \(x-15\in\left\{\pm1,\pm17\right\}\Leftrightarrow x\in\left\{-2,14,16,32\right\}\)
ta có \(x-7=x-5-2\text{ chia hết cho x-5 khi 2 chia hết cho x-5}\)
hay ta có \(x-5\in\left\{\pm1,\pm2\right\}\Leftrightarrow x\in\left\{3,4,6,7\right\}\)
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