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9 tháng 11 2016

nguuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

9 tháng 11 2016

mày coi chừng đấy

7 tháng 4 2020

*) 2x-5=-x-17

<=> 2x-5+x+17=0

<=> 3x+12=0

<=> 3x=-12

<=> x=-4

*) Ta có 2x-3=2(x+1)-5

=> 5 chia hết cho x+1

=> x+1 C Ư(5)={-5;-1;1;5}
Ta có bảng

x+1-5-115
x-6-204
7 tháng 4 2020

B1.

2x - 5 = -x - 17

2x + x = -17 + 5

3x       = -12

x         = (-12) : 3

x         = -4

Vậy x = -4

B2.

x + 1 là ước của 2x - 3

2x - 3 chia hết cho x + 1

( 2x + 2 ) - 5 chia hết cho x + 1

2( x + 1 ) - 5 chia hết cho x + 1

Vì x + 1 chia hết cho x + 1

nên 2(x+1) chia hết cho x + 1

Suy ra: 5 chia hết cho x + 1

Suy ra: x + 1 thuộc { 1; -1; 5; -5 }

Suy ra: x thuộc { 0 ; -2 ; 4; -6 }

Vậy x thuộc { 0 ; -2 ; 4; -6 }

Hok tốt !

20 tháng 1 2018

Bài 1

a, =5.(-24)

    =-12

b,=4+25

   =29

Bài 2:Tìm số nguyên x

a,x-2=-6+17

=> x-2= 11

=> x = 11 + 2

=> x = 13

b,x+2=-9

=> x = -9 - 2

=> x = -11

NM
8 tháng 1 2022

ta có \(3x+6=3\left(x+1\right)+3\) chia hết cho x +1 khi 3 chia hết cho x +1 

hay ta có \(x+1\in\left\{\pm1,\pm3\right\}\Leftrightarrow x\in\left\{-4,-2,0,2\right\}\)

\(x+2=x-15+17\) chia hết cho x- 15 khi 17 chia hết cho x -15

hay ta có  \(x-15\in\left\{\pm1,\pm17\right\}\Leftrightarrow x\in\left\{-2,14,16,32\right\}\)

ta có \(x-7=x-5-2\text{ chia hết cho x-5 khi 2 chia hết cho x-5}\)

hay ta có \(x-5\in\left\{\pm1,\pm2\right\}\Leftrightarrow x\in\left\{3,4,6,7\right\}\)

8 tháng 1 2022

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