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a, x-7= -5
x = (-5)+7
x = 2
Vậy x = 2
b, 128-3.(x+4)=23
3.(x+4)=128-23
3.(x+4)= 105
x+4 = 105 : 3
x+4 = 35
x = 35-4
x = 31
Vậy x =31
c, [(6x-39) :7].4=12
[(6x-39):7] = 12:4
[(6x-39):7] = 3
6x-39 = 3.7
6x - 39 = 21
6x = 21+39
6x = 60
x = 60:6
x = 10
Vậy x = 10
d, (x:3-4).5=15
x:3-4 = 15 : 5
x:3-4 = 3
x: 3 = 7
x = 21
Vậy x= 21
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a) (x : 3 - 4) . 5 = 15
x : 3 - 4 = 15 : 5
x : 3 - 4 = 3
x : 3 = 3 + 4
x : 3 = 7
x = 7 . 3
x = 21.
b) 128 - 3 . (x + 4) = 23
3 . (x + 4) = 128 - 23
3 . (x + 4) = 105
x + 4 = 105 : 3
x + 4 = 35
x = 35 - 4
x = 31.
c) (3x - 24) . 73 = 2 . 74
3x - 24 = 2 . 74 : 73
3x - 24 = 2 . 7
3x - 16 = 14
3x = 14 + 16
3x = 30
x = 30 : 3
x = 10.
d) 5x + x = 39 - 311 : 39
5x + x = 39 - 32
5x + x = 39 - 9
6x = 30
x = 30 : 6
x = 5.
a) \(\left(\dfrac{x}{3}-4\right).5=15\)
\(\Leftrightarrow\dfrac{x}{3}-4=\dfrac{15}{5}\)
\(\Leftrightarrow\dfrac{x}{3}-4=3\)
\(\Leftrightarrow\dfrac{x}{3}=3+4\)
\(\Leftrightarrow\dfrac{x}{3}=7\)
\(\Leftrightarrow x=7.3\)
\(\Leftrightarrow x=21\)
Vậy \(x=21\)
b) \(128-3\left(x+4\right)=23\)
\(\Leftrightarrow3\left(x+4\right)=128-23\)
\(\Leftrightarrow3\left(x+4\right)=105\)
\(\Leftrightarrow x+4=\dfrac{105}{3}\)
\(\Leftrightarrow x+4=35\)
\(\Leftrightarrow x=35-4\)
\(\Leftrightarrow x=31\)
Vậy \(x=31\)
c) \(\left(3x-2^4\right).7^3=2.7^4\)
\(\Leftrightarrow3x-2^4=\dfrac{2.7^4}{7^3}\)
\(\Leftrightarrow3x-2^4=2.7\)
\(\Leftrightarrow3x-2^4=14\)
\(\Leftrightarrow3x-16=14\)
\(\Leftrightarrow3x=14+16\)
\(\Leftrightarrow3x=30\)
\(\Leftrightarrow x=\dfrac{30}{3}\)
\(\Leftrightarrow x=10\)
Vậy \(x=10\)
d) \(5x+x=39-3^{11}:3^9\)
\(\Leftrightarrow6x=39-3^{11-9}\)
\(\Leftrightarrow6x=39-3^2\)
\(\Leftrightarrow6x=39-9\)
\(\Leftrightarrow6x=30\)
\(\Leftrightarrow x=\dfrac{30}{6}\)
\(\Leftrightarrow x=5\)
Vậy \(x=5\)
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\(\frac{x}{2}+x+\frac{x}{3}+x+x+\frac{x}{4}=\frac{23}{12}\)
\(\left(\frac{x}{2}+\frac{x}{3}+\frac{x}{4}\right)+\left(x+x+x\right)=\frac{23}{12}\)
\(\frac{3x}{12}+\frac{36x}{12}=\frac{23}{12}\)
\(\frac{49x}{12}=\frac{23}{12}\)
\(\frac{49}{12}.x=\frac{23}{12}\)
\(x=\frac{23}{12}:\frac{49}{12}=\frac{23}{49}\)
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a, 128 - 3.( x + 4 ) = 23 b, [( 6x - 39 ) : 7 ] . 4 = 12 c, ( x : 3 - 4 ) . 5 = 15
3. ( x + 4 ) = 128 - 23 [(6x - 39 ) : 7 ] = 3 ( x : 3 - 4 ) = 3
3. ( x + 4 ) = 105 ( 6x - 39 ) = 21 x : 3 = 7
x + 4 = 35 6x = 21 + 39 x = 7 . 3
x = 35 - 4 6x = 60 x = 21
x = 31 x = 10 Vậy x = 21
Vậy x = 31 Vậy x = 10
Trl:
a. 128 - 3 . ( x + 4 ) = 23
=> 3 . ( x + 4 ) = 128 - 23
=> 3 . ( x + 4 ) = 105
=> x + 4 = 105 : 3
=> x + 4 = 35
=> x = 35 - 4
=> x = 31
Vậy x = 31
b. [( 6x - 39 ) : 7 ] . 4 = 12
=> [( 6x - 39 ) : 7 ] = 12 : 4
=> [( 6x - 39 ) : 7 ] = 3
=> ( 6x - 39 ) = 3 . 7
=> ( 6x - 39 ) = 21
=> 6x = 21 + 39
=> 6x = 60
=> x = 60 : 6
=> x = 10
Vậy x = 10
c. ( x : 3 - 4 ) . 5 = 15
=> ( x : 3 - 4 ) = 15 : 5
=> ( x :3 - 4 ) = 3
=> x : 3 = 3 + 4
=> x : 3 = 7
=> x = 7 . 3
=> x = 21
Vậy x = 21
d. | x + 2 | = 0
=> x + 2 = 0
=> x = 0 - 2
=> x = -2
Vậy x = -2
e. | x - 5 | = |-7|
=> | x - 5 | = 7
=> x - 5 = 7 hoặc x - 5 = -7
=> x = 7 + 5 hoặc x = -7 + 5
=> x = 12 hoặc x = -2
Vậy \(x\in\left\{12;-2\right\}\)
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a) 128-3(x+4)=23
3(x+4)=128-23
3(x+4)=105
x+4=105:3
x+4=35
x=35-4
x=31
b) [(4x+28).3+55]:5=35
(4x+28).3+55=35.5
(4x+28).3+55=175
(4x+28).3=175-55
(4x+28).3=120
4x+28=120:3
4x+28=40
4x=40+28
4x=68
x=68:4
x=17
c) ( 12x - 43 ) . 83 = 4 . 84
12x-64=4.(84:83)
12x-64=4.8
12x-64=32
12x=32+64
12x=96
x=96:12
x=8
d) 720 : [ 4 - ( 2x - 5 ) ] = 23 . 5
720:[4-(2x-5)] = 8.5
720:[4-(2x-5)]=40
4-(2x-5)=720:40
4-(2x-5)=18
2x-5=4-18
2x-5=-14
2x=-14+5
2x=-9
x=-9:2
x=\(\frac{-9}{2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1/(-37) +14+26+37
=[(-37)+37] +(14+26)
= 0 + 40
= 40
2/(-24) +6 +10+24
=[(-24)+24] +(10+6)
= 0 +16
=16
3/15+23+9+(-25) +9+(-23)
=[(-23)+23] +[(-25)+15] +(9+9)
= 0 + (-10) +18
= 0 + 8
= 8
4/60 +33 +(-50) +(-33)
=[(-33)+33]+[60 +(-50)]
= 0 + 10
= 10
5/(-16)+ (-209) + (-14) +209
=[(-209)+209] +[(-16)+(-14)]
= 0 +(-30)
= -30
6/(-12) +(-13)+36 +(-11)
=[(-12) +(-11)] +[ 36+(-13)]
= (-23) + 23
= 0
Chúc bn hok tốt !!!
1, (-37)+14+26+37=[(-37)+37]+14+26=0+40=40
2, (-24)+6+10+24=[(-24)+24]+6+10=0+16=16
3 , 15+23+(-25)+(-23)=[15+(-25)]+[23+(-23)]=-10
4, 60+33+(-50)+(-33)= [60+(-50)]+[33+(-33)]=10
5, (-16)+(-209)+(-14)+209=[(-16)+(-14)]+[(-209)+209]=-30
6, (-12)+(-13)+36+(-11)=[(-12)+(-11)]+[(-13)+36]=(-23)+23=0
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left|x+2\right|=0\)
\(\Rightarrow x+2=0\)
\(\Rightarrow x=0-2\)
\(\Rightarrow x=-2\)
\(\left|x-5\right|=\left|-7\right|\)
\(\Rightarrow\left|x-5\right|=7\)
\(\Rightarrow\hept{\begin{cases}x-5=-7\\x-5=7\end{cases}}\Leftrightarrow\hept{\begin{cases}x=-7+5\\x=7+5\end{cases}}\Leftrightarrow\hept{\begin{cases}x=-2\\x=12\end{cases}}\)
\(\Rightarrow x\in\left\{-2;12\right\}\)
(x:3-4).5=15
=> x:3-4 = 3
=> x : 3 = 7
=> x = 7 x 3 = 21
128 - 3(x+4) = 23
=> 3(x+4) = 128 - 23 = 105
=> x + 4 = 105 : 3 = 35
=> x = 35 - 4
=> x = 31
x=21 x=31