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[X+2]+[X+4]+...+[X+10]=200
[X+X+X+....+X]+[2+4+...+10]
5X+[[10+2]*[[10-2]:2+1]]:2
5X+30=200
5X=170
X=170:5
X=34
\(\Leftrightarrow5x+\frac{\left[\left(10-2\right):2+1\right]\left(10+2\right)}{2}=200\)
\(\Leftrightarrow5x+30=200\)
\(\Leftrightarrow5x=270\)
\(\Leftrightarrow x=54\)
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198-(x+4)=120
\(\Leftrightarrow\)198-x-4=120
\(\Leftrightarrow\)-x-4=-78
\(\Leftrightarrow\)-x=-74
\(\Leftrightarrow\)x=74
x+4= 198 - 120
x+4= 78
x= 78-4
x=74
Vậy x= 74
2x(x-51) = 2 x 2^3 + 20
2x( x-51) = 2 x 8+ 20
2x(x-51) = 16+20
2x- (x-51) = 36
2x-x+51= 36
x+ 51= 36
x= 51-36
=15
Vậy x=15
phần cuối làm giống phần đầu tiên, bn tự giải nha, nhớ k cho mk nhé!!!!^_^~~~~~~~~~~~~~~~~~~~
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\(\left(5x+2\right)+\left(5x+4\right)+\left(5x+6\right)+...+\left(5x+200\right)=90100.\)
\(\Leftrightarrow5x+2+5x+4+5x+6+...+5x+200=90100\)
\(\Leftrightarrow\left(5x+5x+...+5x\right)+\left(2+4+6+...+200\right)=90100\)
\(\text{Số các số hạng là: }\frac{\left(200-2\right)}{2}+1=100\left(\text{số}\right)\text{ *Chú ý chỗ nãy nếu lớp 7-8 rồi thì ko cần }\)
\(\Leftrightarrow5x.100+\frac{\left(200+2\right).100}{2}=90100\)
\(\Leftrightarrow500x+10100=90100\)
\(\Leftrightarrow x=\frac{90100-10100}{500}\)
\(\text{Vậy }x=160\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 460 + 85.4 = ( x + 200 ) : 4
=> x = 3000
b) => x = 2595
c) => x = 50
d) => x = 40
a)460 +85 . 4 = (x+200) :4 b)x:15+42=15+25.8
suy ra : 460+340=(x+200):4 suy ra: x:15+42=15+200
suy ra: 800= (x+200):4 suy ra : x:15+42=215
suy ra : 800.4=x+200 suy ra: x:15=215-42
suy ra : 3200=x+200 suy ra : x:15=173
suy ra: x= 3200-200 suy ra : x=173.15
suy ra : x=3000 vậy x =3000 suy ra: x=2595 vậy x = 2595
c) x-32:16=48 d)x-6:2-(48-24.2:6-3)=0
suy ra :x-2=48 suy ra : x-6:2-(48-48:6-3)=0
suy ra :x=48+2 suy ra : x-6:2-(48-8-3)=0
suy ra : x=50 suy ra : x-6:2-(40-3)=0
vậy x=50 suy ra : x-6:2 - 37=0
suy ra : x-3-37=0
suy ra : x-3=0+37
suy ra : x-3=37
suy ra : x=37+3
suy ra :x=40 vậy x= 40
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\(C=\frac{1}{2}\times\frac{3}{4}\times\frac{5}{6}\times...\times\frac{199}{200}\)
\(C^2=\left(\frac{1}{2}\right)^2\times\left(\frac{3}{4}\right)^2\times\left(\frac{5}{6}\right)^2\times...\times\left(\frac{199}{200}\right)^2\)
\(< \frac{1}{2}\times\frac{2}{3}\times\frac{3}{4}\times\frac{4}{5}\times\frac{5}{6}\times\frac{6}{7}\times...\times\frac{199}{200}\times\frac{200}{201}\)
\(=\frac{1}{201}< \frac{1}{196}\)
\(\Rightarrow C< \sqrt{\frac{1}{196}}=\frac{1}{14}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, 460 + 85 . 4 = ( x + 200 ) : 4
460 + 340 = ( x + 200 ) : 4
( x + 200 ) : 4 = 800
x + 200 = 800 . 4 = 3200
x = 3200 - 200
x = 3000
Lời giải:
$(x+2)+(x+4)+(x+6)+...+(x+200)=80400$
$(x+x+...+x)+(2+4+6+...+200)=80400$
$100\times x+(200+2)\times 100:2=80400$
$100\times x+10100=80400$
$100\times x=80400-10100=70300$
$x=70300:100=703$