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VC
Vũ Cao Minh
CTV
VIP
26 tháng 8 2021
a) \(3x-10=2x+13\Leftrightarrow x=13+10=23\)
b) \(x+12=-5-x\Leftrightarrow2x=-17\Leftrightarrow x=-\frac{17}{2}\)
c) \(x+5=10-x\Leftrightarrow2x=5\Leftrightarrow x=\frac{5}{2}\)
d) \(6x+23=2x-12\Leftrightarrow4x=-35\Leftrightarrow x=-\frac{35}{4}\)
e) \(12-x=x+1\Leftrightarrow2x=11\Leftrightarrow x=\frac{11}{2}\)
f) \(14+4x=3x+20\Leftrightarrow x=20-14=6\)
VC
Vũ Cao Minh
CTV
VIP
26 tháng 8 2021
g) \(2\left(x-1\right)+3\left(x-2\right)=x-4\Leftrightarrow2x-2+3x-6=x-4\)
\(\Leftrightarrow5x-8=x-4\Leftrightarrow4x=4\Leftrightarrow x=1\)
h ) \(3\left(4-x\right)-2\left(x-1\right)=x+20\Leftrightarrow12-3x-2x+2=x+20\)
\(\Leftrightarrow14-5x=x+20\Leftrightarrow6x=-6\Leftrightarrow x=-1\)
i ) \(4\left(2x+7\right)-3\left(3x-2\right)=24\Leftrightarrow8x+28-9x+6=24\)
\(\Leftrightarrow34-x=24\Leftrightarrow x=34-24=10\)
k) \(3\left(x-2\right)+2x=10\Leftrightarrow3x-6+2x=5x-6=10\)
\(\Leftrightarrow5x=10+6=16\Leftrightarrow x=\frac{16}{5}\)
Tự KL cho các phần
2 tháng 6 2017
a) \(\dfrac{x}{5}+\dfrac{1}{2}=\dfrac{6}{10}\\ \dfrac{x}{5}+\dfrac{1}{2}=\dfrac{3}{5}\\ \dfrac{x}{5}=\dfrac{3}{5}-\dfrac{1}{2}\\ \dfrac{x}{5}=\dfrac{6}{10}-\dfrac{5}{10}\\ \dfrac{x}{5}=\dfrac{1}{10}\\ \dfrac{2x}{10}=\dfrac{1}{10}\\ \Rightarrow2x=1\\ x=1:2\\ x=0,5=\dfrac{1}{2}\)
b) \(x+\dfrac{3}{15}=\dfrac{1}{3}\\ x=\dfrac{1}{3}-\dfrac{3}{15}\\ x=\dfrac{5}{15}-\dfrac{3}{15}\\ x=\dfrac{2}{15}\)
c) \(x-\dfrac{12}{4}=\dfrac{1}{2}\\ x-3=\dfrac{1}{2}\\ x=\dfrac{1}{2}+3\\ x=\dfrac{1}{2}+\dfrac{6}{2}\\ x=\dfrac{7}{2}\)
d) \(\dfrac{1}{2}x+\dfrac{1}{2}=\dfrac{5}{2}\\ \dfrac{1}{2}x=\dfrac{5}{2}-\dfrac{1}{2}\\ \dfrac{1}{2}x=2\\ x=2:\dfrac{1}{2}\\ x=4\)
NC
2 tháng 6 2017
a. \(\dfrac{2x+5}{10}=\dfrac{6}{10}\Leftrightarrow2x=1\Leftrightarrow x=\dfrac{1}{2}\)
b. \(\dfrac{15x+3}{15}=\dfrac{5}{15}\Leftrightarrow15x=2\Leftrightarrow x=\dfrac{2}{15}\)
c. \(\dfrac{4x-12}{4}=\dfrac{2}{4}\Leftrightarrow4x=14\Leftrightarrow x=\dfrac{7}{2}\)
d. \(\dfrac{1+x}{2x}=\dfrac{5x}{2x}\Leftrightarrow-4x=-1\Leftrightarrow x=\dfrac{1}{4}\)
e. \(\dfrac{-4\left(2x-5\right)}{6\left(2x-5\right)}-\dfrac{2}{6\left(2x-5\right)}=\dfrac{9\left(2x-5\right)}{6\left(2x-5\right)}\)
\(\Leftrightarrow-8x+20-2=18x-45\)
\(\Leftrightarrow-26x=-63\Leftrightarrow x=\dfrac{63}{26}\)
A
28 tháng 3 2020
a) \(3x-10=2x+13\)
\(\Leftrightarrow3x-2x=13+10\)
\(\Leftrightarrow x=23\)
b) \(x+12=-5-x\)
\(\Leftrightarrow x+x=-5-12\)
\(\Leftrightarrow2x=-17\)
\(\Leftrightarrow x=-\frac{17}{2}\)
c) \(x+5=10-x\)
\(\Leftrightarrow x+x=10-5\)
\(\Leftrightarrow2x=5\)
\(\Leftrightarrow x=\frac{5}{2}\)
d) \(6x+2^3=2x-12\)
\(\Leftrightarrow6x+8=2x-12\)
\(\Leftrightarrow6x-2x=-12-8\)
\(\Leftrightarrow4x=-20\)
\(\Leftrightarrow x=-5\)
e) \(12-x=x+1\)
\(\Leftrightarrow-x-x=1-12\)
\(\Leftrightarrow-2x=-11\)
\(\Leftrightarrow x=\frac{11}{2}\)
g) \(2\left(x-1\right)+3\left(x-2\right)=x-4\)
\(\Leftrightarrow2x-2+3x-6=x-4\)
\(\Leftrightarrow2x+3x-x=-4+6+2\)
\(\Leftrightarrow4x=4\)
\(\Leftrightarrow x=1\)
h) \(14+4x=3x+20\)
\(\Leftrightarrow4x-3x=20-14\)
\(\Leftrightarrow x=6\)
i) \(4\left(2x+7\right)-3\left(3x-2\right)=24\)
\(\Leftrightarrow8x+28-9x+6=24\)
\(\Leftrightarrow8x-9x=24-6-28\)
\(\Leftrightarrow-x=-10\)
\(\Leftrightarrow x=10\)
k) \(3\left(4-x\right)-2\left(x-1\right)=x+20\)
\(\Leftrightarrow12-3x-2x+2=x+20\)
\(\Leftrightarrow-3x-2x-x=20-2-12\)
\(\Leftrightarrow-6x=6\)
\(x=-1\)
l) \(3\left(x-2\right)+2x=10\)
\(\Leftrightarrow3x-6+2x=10\)
\(\Leftrightarrow3x+2x=10+6\)
\(\Leftrightarrow5x=16\)
\(\Leftrightarrow x=\frac{16}{5}\)
Lần sau bạn chỉ nên đăng ít câu hỏi một thôi nhé, đăng nnay các bạn làm không xuể đâu
9 tháng 10 2017
a, 2^6x = 1024 <=> x=1024:2^6 <=>x=1024:64 <=>x=16
b,2.3^x=10.3^12+8.3^12
<=>2.3^x=3^12.(10+8)
<=>2.3^x=3^12.18
<=>3^x=9
<=>3^x=3^2
<=>x=2
6,(2x-4)^5:(2x-4)^3=0
<=>(2x-4)^2=0
<=>2x-4=0
<=>2x=4
<=>x=2
hai câu kia hơi dài mà mình mỏi tay quá , sorry bạn ! bạn hãy cố gắng đưa chúng về cùng cơ số nhé ! sẽ giải ra nhé ! goodluck !
9 tháng 10 2017
a) \(2^{2x}.2^4=1024\)
\(2^{2x}=1024:2^4\)
\(2^{2x}=1024:16\)
\(2^{2x}=64\)
\(2^{2x}=2^6\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
vay \(x=3\)
b) \(2.3^x=10.3^{12}+8.27^4\)
\(2.3^x=2.5.3^{12}+2^3.\left(3^3\right)^4\)
\(2.3^x=2.5.3^{12}+2^3.3^{12}\)
\(2.3^x=2.3^{12}.\left(5+2^2\right)\)
\(2.3^x=2.3^{12}.9\)
\(2.3^x=2.3^{12}.3^2\)
\(2.3^x=2.3^{14}\)
\(\Rightarrow x=14\)
vay \(x=14\)
c) \(5^8.25^x+1=5^{17}\)
\(5^8.\left(5^2\right)^x+1=5^{17}\)
\(5^8.5^{2x}+1=5^{17}\)
\(5^{8+2x}=5^{17}-1\)
e) \(\left(2x-4\right)^5=\left(2x-4\right)^3\)
\(\left(2x-4\right)^5-\left(2x-4\right)^3=0\)
\(\left(2x-4\right)\left[\left(2x-4\right)^2-1\right]=0\)
\(\left(2x-4\right)\left(2x-4-1\right)\left(2x-4+1\right)=0\)
\(\left(2x-4\right)\left(2x-5\right)\left(2x-3\right)=0\)
\(\Rightarrow2x-4=0\)hoac \(\orbr{\begin{cases}2x-5=0\\2x-3=0\end{cases}}\)
\(\Rightarrow2x=4\)hoac \(\orbr{\begin{cases}2x=5\\2x=3\end{cases}}\)
\(\Rightarrow x=2\)hoac \(\orbr{\begin{cases}x=\frac{5}{2}\\x=\frac{3}{2}\end{cases}}\)
vay \(x=2\)hoac \(\orbr{\begin{cases}x=\frac{5}{2}\\x=\frac{3}{2}\end{cases}}\)
NH
2
28 tháng 6 2018
a) 3x - 4 (2x-7) = 3x - 3
3x - 8x + 28 = 3x - 3
=> 3x - 8x - 3x = -3 -28
-8x = -31
x = 31/8
b) 3(2x-7) - (4-2x) = 2x -1
6x - 7 - 4 + 2x = 2x -1
=> 6x + 2x - 2x = -1 + 7+4
6x = 10
x = 5/3
c) (x-2).(2x+12)=0
=> x -2 = 0 => x = 2
2x + 12 = 0 => 2x = -12 => x = -6
KL: x = 2 hoặc x = -6
Ta có :
\(x\left(2x-1\right)-4\left(x+1\right)=12+2x\left(x-3\right)\)
\(\Rightarrow2x^2-x-\left[4x+4\right]=12+\left(2x^2-6x\right)\)
\(\Rightarrow2x^2-x-4x-4=12+2x^2-6x\)
\(\Rightarrow2x^2-5x-4=12+2x^2-6x\)
\(\Rightarrow\left(2x^2-5x-4\right)-\left(2x^2-6x\right)=12\)
\(\Rightarrow2x^2-5x-4-2x^2+6x=12\)
\(\Rightarrow x-4=12\)
\(\Rightarrow x=12+4\)
\(\Rightarrow x=16\)
Vậy \(x=16\)
~ Ủng hộ nhé
x(2x - 1) - 4(x +1) = 12+ 2x( x - 3)
➡️ 2x2 - x - 4x - 3 = 12 + 2x2 - 6x
➡️ 2x2 - x - 4x - 2x2 + 6x = 12 +3
➡️ 2x2 - x - 4x - 2x2 + 6x = 15
➡️- 5x + 6x = 15
➡️ x = 15
Hok tốt!!!