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\(\frac{1}{2}\left(\frac{4}{9}-x\right)-\frac{3}{2}\left(16-x\right)+\frac{1}{2}\left(5x+10\right)=0\)
\(\Leftrightarrow\frac{2}{9}-\frac{1}{2}x-24+\frac{3}{2}x+\frac{5}{2}x+5=0\)
\(\Leftrightarrow-\frac{169}{9}=\frac{7}{2}x\Leftrightarrow x=-\frac{338}{63}\)
Sai thì thông cảm cho mk nha

\(\left[\frac{4}{7}-\frac{1}{2}.x\right]^3=2^3\)
\(\Rightarrow\frac{4}{7}-\frac{1}{2}.x=2\)
\(\frac{1}{2}.x=-\frac{10}{7}\)
\(x=-\frac{20}{7}\)

1,ta có:h(x) = ( x - 3 ).( 16 - 4x )=0
*)x-3=0
=>x=3
*)16-4x=0
=>4x=16
=>x=4
2,ta có:4x^2 - 6x=0
<=>2x(2x-3)=0
*)2x=0
=>x=0
*)2x-3=0
=>2x=3
=>x=\(\frac{3}{2}\)
3,ta có:x^2 + 7x - 8=0
denta:72-(-4(1.8))=81
x1:(-7+9):2=1
x2:(-7-81):2=-8



\(\frac{1}{2}x-\frac{1}{3}x=\frac{4}{7}+\left(-\frac{5}{8}\right)-\frac{3}{28}\)
\(\frac{1}{2}x-\frac{1}{3}x=\frac{4}{7}-\frac{5}{8}-\frac{3}{28}\)
\(\frac{1}{2}x-\frac{1}{3}x=\frac{32}{56}-\frac{35}{56}-\frac{6}{56}\)
\(\frac{1}{2}x-\frac{1}{3}x=\frac{32-35-6}{56}\)
\(\frac{1}{2}x-\frac{1}{3}x=\frac{-9}{56}\)
\(\frac{1}{2}x-\frac{1}{3}x=-\frac{9}{56}.168\)
\(\frac{1}{2}x-\frac{1}{3}x=-27\)
\(84x-56x=-27\)
\(28x=-27\)
\(x=\frac{-27}{28}\)
\(\Rightarrow x=\frac{-27}{28}\)

Đặt \(\frac{x}{2}=\frac{y}{3}=k\Rightarrow\hept{\begin{cases}x=2k\\y=3k\end{cases}}\)
Khi đó \(\frac{x-y}{x+3y}=\frac{2k-3k}{2k+9k}=\frac{-k}{11k}=-\frac{1}{11}\)
\(\left(x+2\right)^2-\left(x+3\right)\left(x-3\right)+10=8\)
\(\Leftrightarrow x^2+4x+4-\left(x^2-9\right)+10=8\)
\(\Leftrightarrow x^2+4x+4-x^2+9+10-8=0\)
\(\Leftrightarrow4x+15=0\)
\(\Leftrightarrow x=-\frac{15}{4}\)
\(\left(x+2\right)^2-\left(x+3\right)\left(x-3\right)+10=8\)
\(\Leftrightarrow x^2+4x+4-x^2+9+10=8\)
\(\Leftrightarrow4x+23=8\Leftrightarrow4x=-15\Leftrightarrow x=-\frac{15}{4}\)