Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Gọi tổng trên là A
Ta có : \(A=\frac{1}{5}+\frac{1}{10}+\frac{1}{20}+...+\frac{1}{2560}\)
\(2A=2\left(\frac{1}{5}+\frac{1}{10}+...+\frac{1}{2560}\right)\)
\(2A=\frac{2}{5}+\frac{1}{5}+\frac{1}{10}+...+\frac{1}{1280}\)
\(2A-A=\left(\frac{2}{5}+\frac{1}{5}+...+\frac{1}{1280}\right)-\left(\frac{1}{5}+\frac{1}{10}+...+\frac{1}{2560}\right)\)
\(A\left(2-1\right)=\frac{2}{5}-\frac{1}{2560}\)
\(A.1=\frac{1024}{2560}-\frac{1}{2560}\)
\(A=\frac{1023}{2560}\)
Ta có : A = 1/5 + 1/10 + 1/20 + ... + 1/2560
2A = 2 ( 1/5 + 1/10 + ... + 1/2560 )
2A = 2/5 + 1/5 + 1/10 + .. + 1/2560
2A - A = ( 2/5 + 1/5 + ... + 1/1280 ) - ( 1/5 + 1/10 + ... + 1/2560 )
A = 2 - 1 = 2/5 - 1/2560
A.1 = 1024/2560 - 1/2560
A = 1023 = 2560
\(\frac{2}{5}\)x m + 25% x m + m = 16,5
m x ( \(\frac{2}{5}\) + 25% + 1 ) = 16,5
m x \(\frac{33}{20}\)= 16,5
m = 16,5 : \(\frac{33}{20}\)
m = 10
\(\frac{24}{400}+50\%+\frac{3}{100}+25\%\)
\(=0,24\%+50\%+0,03\%+25\%\)
\(=50,52\%\)
\(\frac{2012+2013x2014}{2014x2015-2016}\)\(=\frac{2012+2013x2014}{2014x\left(2013+2\right)-2016}\)
\(=\frac{2012+2013x2014}{2014x2013+4028-2016}\)
\(=\frac{2012+2013x2014}{2014x2013+2012}\)
\(=1\)
\(\frac{2012+2013x2014}{2014x2015-2016}\)
= \(\frac{2012+2013x2014}{2014x\left(2013+2\right)-2016}\)
= \(\frac{2012+2013x2014}{2014x2013+4028-2016}\)
= \(\frac{2012+2013x2014}{2014x2013+2012}\)
= 1
\(2\frac{1}{3}:3\frac{1}{4}\)
\(=\frac{7}{3}:\frac{13}{4}\)
\(=\frac{28}{39}\)
\(x+3\frac{1}{2}+x=24\frac{1}{4}\)
\(2x=24+\frac{1}{4}-3-\frac{1}{2}\)
\(2x=20+1+\frac{1}{4}-\frac{2}{4}\)
\(2x=20+\frac{3}{4}\)
\(2x=\frac{83}{4}\)
\(x=\frac{83}{4}:2\)
\(x=\frac{83}{8}\)
\(x+3\frac{1}{2}+x=24\frac{1}{4}\)
\(\Leftrightarrow x+\frac{7}{2}+x=\frac{97}{4}\)
\(\Leftrightarrow x+x=\frac{97}{4}-\frac{7}{2}\)
\(\Leftrightarrow2x=\frac{83}{4}\)
\(\Leftrightarrow x=\frac{83}{8}\)
X20=x20
Sao bạn hỏi câu hỏi j kì z
Oh, xin lỗi mik mới là người sai