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2. =5(x2-2.1/10.x+1/100-y2+2.1/10y-1/100)
=5.((X-1/10)2-(Y-1/10)2)
=5(X-1/10-Y+1/10)(X-1/10+Y-1/10)
=5(X-Y)(X+Y-2/10)
\(4x^2\left(x+y\right)-x-y\)
\(=4x^2\left(x+y\right)-\left(x+y\right)\)
\(=\left(x+y\right)\left(4x^2-1\right)\)
\(=\left(x+y\right)\left(2x-1\right)\left(2x+1\right)\)
\(16ty^2+6xt-9t-tx^2\)
\(=t.\left(16y^2+6x-9-x^2\right)\)
\(=t.\left[\left(4y\right)^2-\left(x^2-2.x.3+3^2\right)\right]\)
\(=t.\left[\left(4y\right)^2-\left(x-3\right)^2\right]\)
\(=t.\left(4y-x+3\right)\left(4y+x-3\right)\)
\(x^2-9xy+20y^2\)
\(=\left(x^2-4xy\right)-\left(5xy-20y^2\right)\)
\(=x.\left(x-4y\right)-5y\left(x-4y\right)\)
\(=\left(x-4y\right)\left(x-5y\right)\)
Ta có
a, x2-x-y2-y
=x2-y2-(x+y)
=(x-y)(x+y) - (x+y)
=(x+y)(x-y-1)
b, x2-2xy+y2-z2
=(x-y)2-z2
=(x-y-z)(x-y+z)
a: \(=x\left[49-x^2\left(2x+1\right)^2\right]\)
\(=x\left[49-\left(2x^2+x\right)^2\right]\)
\(=x\left[\left(7-2x^2-x\right)\left(7+2x^2+x\right)\right]\)
b: \(=5\left[25x^2-\left(y^2-4y+4\right)\right]\)
\(=5\left[\left(5x-y+2\right)\left(5x+y-2\right)\right]\)
c: \(=1-4x^2-x\left(x^2-4\right)\)
\(=1-4x^2-x^3+4x\)
\(=\left(1-x\right)\left(1+x+x^2\right)-4x\left(x-1\right)\)
\(=\left(1-x\right)\left(1+x+x^2+4x\right)\)
\(=\left(1-x\right)\left(x^2+5x+1\right)\)
e: =(x-9)(x+6)
x2-9xy+20y2=x2-4xy-5xy+20y2
nhóm 2 cái đầu, 2 cái cuối.