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1/ \(=3^n.3^2+3^n=3^n\left(3^2+1\right)=10.3^n⋮10\)
2/ \(100.x+\left(1+2+3+...+100\right)=7450\)
Đến đây bạn tự làm nốt nhé
1. Ta có: \(3^{n+2}+3^n=3^n.\left(3^2+1\right)=3^n.\left(9+1\right)=3^n.10⋮10\)( đpcm )
2. \(\left(x+1\right)+\left(x+2\right)+.......+\left(x+100\right)=7450\)
\(\Leftrightarrow x+1+x+2+........+x+100=7450\)
\(\Leftrightarrow100x+\frac{100.101}{2}=7450\)
\(\Leftrightarrow100x+5050=7450\)
\(\Leftrightarrow100x=2400\)\(\Leftrightarrow x=24\)
Vậy \(x=24\)
\(\left|X-15\right|=2\)
\(\orbr{\begin{cases}X-15=-2\\X-15=2\end{cases}\Leftrightarrow\orbr{\begin{cases}X=-2+15=-13\\X=2+15=17\end{cases}}}\)
VẬY X=-13 HOẶC X=17
/x-15/=2
\(\Rightarrow\)/x/=2+15
\(\Rightarrow\)/x/=17
suy ra hoặc x=17
hoặc x=-17
Ai trả lời cho mình sẽ tik cho nhé
(x+1)+(x+2)+(x+3)+...+(x+100)=7450
2x -2^3×3^2=138
(6x-3^4)×7^3=3×74
(x+1)+(x+2)+(x+3)+...+(x+100)=7450
(100x+1+2+3+4+...+100)=7450
100x+5050=7450
100x=7450-5050
100x=2400
x=2400:100
x=24
\(\left(x+1\right)+\left(x+2\right)+........+\left(x+100\right)=7450\)
\(x+1+x+2+..............+x+100=7450\)
\(100x+\left(1+2+3+..........+100\right)=7450\)
\(100x+5050=7450\)
\(100x=7450-5050=2400\)
\(x=24\)
Ta có :
1025 = (5 + x) * SLSH : 2
2050 = ( 5 + x ) * SLSH
SLSH = (x - 5) +1
Suy ra:
2050 = ( 5 + x ) * [ ( x - 5 ) + 1 ]
2050 = 5x + x^2 - 5x + 5x + 5 + x
2050 = 6x + x.x
2050= (6x)^2
Từ đây bạn tự mò nhé.
Good luck
\(\Rightarrow\)(x+x+x+...+x)+(1+2+..+100)=7450
\(\Rightarrow\)101x+(100+1)*100/2=7450
\(\Rightarrow\)101x+101*50=7450
\(\Rightarrow\)101x+5050=7450
\(\Rightarrow\)101x=7450-5050
\(\Rightarrow\)101x=2400
\(\Rightarrow\)x=2400/101
mik ra k chia hết
nhưng kb vs mik nha ,mik là A.R.M.Y
=> x+x+1+x+2+......+x+100 = 7450
=> 100x + 5050 = 7450
=> 100x = 7450 - 5050 = 2400
=> x = 2400 : 100 = 24
Vậy x = 24
Tk mk nha
\(\left(x+1\right)+\left(x+2\right)+...+\left(x+100\right)=7450\)
\(100x+\left(1+2+3+...+100\right)=7450\)
\(100x+\frac{100.101}{2}=7450\)
\(100x+5050=7450\)
\(100x=2400\)
\(\Rightarrow x=24\)
\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+......+\left(x+100\right)=7450\)
\(=>100x+\left(1+2+3+4+5+.....+100\right)=7450\)
\(=>100x+\frac{100.101}{2}=7450\)
\(=>100x=2400\)
\(=>x=24\)
Ủng hộ nha
Thanks
(x+1)+(x+2)+....+(x+100)=7450
100x + (1+2+...+100)=7450
100x + 5050 = 7450
100x = 7450 - 5050
100x = 2400
x = 2400 : 100
x = 24
(x+1)+(x+2)+...+(x+100)=7450
100x+(1+2+...+100)=7450
100x+5050=7450
100x =7450-5050
100x. =2400
x=24