Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(=10-\left[\left(91-48\right).5+\left(8.10+8\right)\right]:28\)
\(=10-\left[43.5+88\right]:28\)
\(=10-\left[215+88\right]:28\)
\(=10-303:28\)
\(=10-10,821\)
\(=0,179\)
Ko chắc
\(a.\left(5+2\right).x=36-1\)
\(7.x=35\)
\(x=5\)
\(b.\left(5+1\right).x=75+3\)
\(6.x=78\)
\(x=13\)
\(c.\left(6+1\right).x=5^2+3\)
\(7.x=25+3\)
\(7.x=28\)
\(x=4\)
\(d.\left(7-1\right).x=5^2+3.4-1\)
\(6.x=25+12-1\)
\(6.x=36\)
\(x=6\)
a. 7^5 : 7^3 + 3^2 . 2^3 - 2009^0
= 7^2 + 72 - 1
= 49 + 71
= 120
b. 5^3 . 52 + 5^3 . 7^2 - 5^2
= 5^2 . ( 5 . 52 + 5 . 49 - 1 )
= 25 . ( 260 + 245 - 1 )
= 25 . 504
= 12600
c. [ 130 - 3 ( 5 . 2^4 - 5^2 . 2 ) : 2^3 ]
= [ 130 - 3 . 30 : 2^3 ]
= [ 130 - 90 : 8 ]
= [ 130 - 11,25 ]
= -118,75
d. SSH là : ( 150 - 10 ) : 2 + 1 = 71 ( số )
Tổng là : ( 150 + 10 ) . 71 : 2 = 5680
7x - x = 521: 519 + 3.22 - 70
=> 6x = 52 + 3.4 - 1
=> 6x = 25 + 12 - 1
=> 6x = 36
=> x = 36 : 6
=> x = 6
2x : 23 = 16
=> 2x = 16.23
=> 2x = 128
=> 2x = 27
=> x = 7
32x + 3 - 9x + 1 = 2.310
=> 32x + 3 - 32x + 2 = 2.310
=> 32x + 2. 3 - 32x + 2 = 2.310
=> 32x + 2. (3 - 1) = 2.310
=> 32x + 2.2 = 2.310
=> 32x + 2 = 310
=> 2x + 3 = 10
=> 2x = 10 - 3
=> 2x = 7
=> x = 7/2
a) \(7x-x=5^{21}:5^{19}+3.2^2-7^0\)
\(\Rightarrow6x=25+12-1\)
\(\Rightarrow x=6\)
b) \(2^x:2^3=16\)
\(\Rightarrow2^x=2^4.2^3=2^7\)
\(\Rightarrow x=7\)
c) \(3^{2x+3}-9^{x+1}=2.3^{10}\)
\(\Rightarrow9^x.27-9^x.9=2.3^{10}\)
\(\Rightarrow9^x.18=2.3^{10}\)
\(\Rightarrow9^x=3^8=9^4\)
\(\Rightarrow x=4\)
Bài làm
m) (x + 2).(3 - x) = 0;
=> x + 2 = 0 hoặc 3 - x = 0
=> x = -2 hoặc x = 3
Vậy x = -2 hoặc x = 3
d) 511.712 + 511.711
= 511 . ( 712 + 711 )
= 511 . [ 711 . ( 7 + 1 ) ]
= 511 . 711 . 8
= ( 5 . 7 )11 . 8
= 3511 . 8
512.712 + 9.511.711
= 511 ( 5 . 712 + 9 . 1 . 711 )
= 511 [ 711 ( 5 . 7 + 9 . 1 . 1 ) ]
= 511 ( 711 . 44 )
= 511 . 711 . 44
= 3511 . 44
m. \(\left(x+2\right)\left(3-x\right)=0\Leftrightarrow\orbr{\begin{cases}x+2=0\\3-x=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-2\\x=3\end{cases}}\)
d. \(\frac{5^{11}.7^{12}+5^{11}.7^{11}}{5^{12}.7^{12}+9.5^{11}.7^{11}}=\frac{5^{11}.\left(7^{12}+7^{11}\right)}{5^{11}.\left(5.7^{12}+9.7^{11}\right)}=\frac{7^{12}+7^{11}}{5.7^{12}+9.7^{11}}=\frac{1}{5.9}=\frac{1}{45}\)
q. \(\left(x-3\right)+\left(x-2\right)+\left(x-1\right)+...+10+11=11\)
\(\Rightarrow\left(x-3\right)+\left(x-2\right)+\left(x-1\right)+...+10=0\)
\(\Rightarrow\left[\left(x-3\right)+\left(x-2\right)+\left(x-1\right)\right]+(1+2+3+...+10)=0\)
\(\Rightarrow\left(x-3\right)+\left(x-2\right)+\left(x-1\right)+55=0\)
\(\Rightarrow x-3+x-2+x-1=-55\)
\(\Rightarrow3x-6=-55\)
\(\Rightarrow3x=-49\)
\(\Rightarrow x=-\frac{49}{3}\)
a)7^2+9.8-1 b)=5^3(52+7^2)-25 c)rút gọn rồi làm d) số số hạng của tổng lá NHỚ K NHA
=49+71 =..... (150-10):2+1=71
=130 tổng trên là (150+10).71:2=5680
\(\left(x+7\right)^{10}.\left(x+2\right)^2=5^0.7^0\)
\(\Rightarrow\left(x+7\right)^{10}.\left(x+2\right)^2=1.1=1\)
mà \(\left\{{}\begin{matrix}\left(x+7\right)^{10}\ge0,\forall x\\\left(x+2\right)^2\ge0,\forall x\end{matrix}\right.\)
\(\Rightarrow\left(x+7\right)^{10};\left(x+2\right)^2\in\left\{1\right\}\left(x\inℕ\right)\)
\(\Rightarrow\left\{{}\begin{matrix}\left(x+7\right)^{10}=1\\\left(x+2\right)^2=1\end{matrix}\right.\) (Vô lý)
\(\Rightarrow x\in\varnothing\)