Question

[Lưu Tuấn Tú]

(x - 2)² - (x-3).(x+3) = 6

Answer 1

[Phước Lộc]

\(\left(x-2\right)^2-\left(x-3\right)\left(x+3\right)=6\)

\(\left(x-2\right)^2-\left(x^2-9\right)=6\)

\(x^2-4x+4-x^2+9=6\)

\(-4x+13=6\)

\(-4x=-7\)

\(x=\frac{7}{4}\)

Answer 2

[Nguyễn Huy Tú]

\(\left(x-2\right)^2-\left(x-3\right)\left(x+3\right)=6\)

\(\Leftrightarrow x^2-4x+4-x^2+9=6\)

\(\Leftrightarrow-4x+7=0\Leftrightarrow x=\frac{7}{4}\)