![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(3\left(2-x\right)+5\left(x-6\right)=-98\)
\(\Rightarrow6-3x+5x-30=-98\)
\(\Rightarrow2x-24=-98\)
\(\Rightarrow2x=-74\)
\(\Rightarrow x=-37\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(\frac{x+1}{2014}+\frac{x+2}{2013}+\frac{x+3}{2012}=\frac{x+4}{2011}+\frac{x+5}{2010}+\frac{x+6}{2009}\)
\(\Rightarrow\frac{x+1}{2014}+1+\frac{x+2}{2013}+1+\frac{x+3}{2012}+1=\frac{x+4}{2011}+1+\frac{x+5}{2010}+1+\frac{x+6}{2009}+1\)
\(\Rightarrow\frac{2015+x}{2014}+\frac{2015+x}{2013}+\frac{2015+x}{2012}=\frac{2015+x}{2011}+\frac{2015+x}{2010}+\frac{2015+x}{2009}\)
\(\Rightarrow\left(2015+x\right)\left(\frac{1}{2014}+\frac{1}{2013}+\frac{1}{2012}-\frac{1}{2011}-\frac{1}{2010}-\frac{1}{2009}\right)=0\)
=> 2015 + x = 0
=> x = -2015
![](https://rs.olm.vn/images/avt/0.png?1311)
3x=4y-21
=> x=\(\frac{4y-21}{3}=\frac{4y}{3}-7\)
x < 10 => \(\frac{4y-21}{3}< 10\)=> 4y-21 < 30 => 4y < 51 => y<51/4=12,75
Mà 4y phải chia hết cho 3 => y=3; 6; 9; 12
+/ y=3 => x=-3
+/ y=6 => x=1
+/ y=9 => x=5
+/ y=12 => x=9
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\frac{7}{x}=\frac{3}{12}\)
→ 7 . 12 = 3x
84 = 3x
x = 84 : 3
x = 28
Ta có / x-2013/ + /x -2020/ = /x -2013/ + / 2020 -x/ >/ / x -2013 + 2020 -x / = 7
Dấu ' =' xảy ra khi 2013</ x </ 2020
Nếu x là số tự nhiên
=> x thuộc { 2013; 2014;2015;....2020}