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a) \(x-2=-6\)
\(x=-6+2\)
\(x=-4\)
b) \(15-\left(x-7\right)=-21\)
\(x-7=36\)
\(x=43\)
c) \(4.\left(3x-4\right)-2=18\)
\(4\left(3x-4\right)=20\)
\(3x-4=5\)
\(3x=9\)
\(x=3\)
d) \(\left(3x-6\right)+3=32\)
\(3x-6=29\)
\(3x=29+6\)
\(3x=35\)
\(x=\frac{35}{3}\)
e) \(\left(3x-6\right).3=32\)
\(3x-6=\frac{32}{3}\)
\(3x=\frac{32}{3}+6\)
\(3x=\frac{50}{3}\)
\(x=\frac{50}{9}\)
f) \(\left(3x-6\right):3=32\)
\(3x-6=96\)
\(3x=102\)
\(x=34\)
g) \(\left(3x-6\right)-3=32\)
\(3x-6=35\)
\(3x=41\)
\(x=\frac{41}{3}\)
h) \(\left(3x-2^4\right).7^3=2.7^4\)
\(\left(3x-2^4\right)=2.7=14\)
\(\left(3x-16\right)=14\)
\(3x=14+16=30\)
\(x=10\)
i) \(\left|x\right|=\left|-7\right|\)
\(\left|x\right|=7\)
\(\Rightarrow\orbr{\begin{cases}x=7\\x=-7\end{cases}}\)
k) \(\left|x+1\right|=2\)
\(\Rightarrow\orbr{\begin{cases}x+1=2\\x+1=-2\end{cases}\Rightarrow\orbr{\begin{cases}x=1\\x=-3\end{cases}}}\)
l) \(\left|x-2\right|=3\)
\(\Rightarrow\orbr{\begin{cases}x-2=3\\x-2=-3\end{cases}\Rightarrow\orbr{\begin{cases}x=5\\x=-1\end{cases}}}\)
m) \(x+\left|-2\right|=0\)
\(x+2=0\)
\(x=-2\)
o) \(72-3\left|x+1\right|=9\)
\(3\left|x-1\right|=63\)
\(\left|x-1\right|=21\)
\(\Rightarrow\orbr{\begin{cases}x-1=21\\x-1=-21\end{cases}\Rightarrow\orbr{\begin{cases}x=22\\x=-20\end{cases}}}\)
p) Ta có: \(\left|x-1\right|=3\)
\(\Rightarrow\orbr{\begin{cases}x-1=3\\x-1=-3\end{cases}}\)
mà \(x+1< 0\)
\(\Rightarrow x-1=-3\)
\(\Rightarrow x=-2\)
q) \(\left(x-2\right)\left(x+4\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-2=0\\x+4=0\end{cases}\Rightarrow\orbr{\begin{cases}x=2\\x=-4\end{cases}}}\)
hok tốt!!
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có : [(x-2)^2-49] . [(x+1).5-32]=0
=> (x-2)^2-49 =0 hoặc (x+1).5-32=0
+) Nếu (x-2)^2-49 =0
=> (x-2)^2 =0+49=49
=> (x-2) ^2=7^2
=>x-2=7
x=7+2=9
Vậy x=9
+) Nếu (x+1).5-32=0
=> (x+1).5=32+0=32
=>(x+1) =32:5
x+1=32/5
x=32/5 -1=27/5
Vậy x=37/5
(bn nhớ chú ý đề bài nhé, nếu đề bài y/c tìm x nguyên dương thì loại TH2 nhé :)
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\(16\cdot\frac{x-1}{4}=0\)
\(\Rightarrow\frac{x-1}{4}=0\)
\(\Rightarrow x-1=0\)
\(\Rightarrow x=1\)
vậy_
32(x - 8) = 32
=> x - 8 = 32 : 32
=> x - 8 = 1
=> x = 9
vậy_
112 - (x - 34) = 97
=> x - 34 = 112 - 97
=> x - 34 = 15
=> x = 49
vậy_
181 - (210 - x) = 119
=> 210 - x = 181 - 119
=> 210 - x = 62
=> x = 148
vậy_
\(\left(3x-1\right)\left(x-6\right)=0\)
\(\Rightarrow\orbr{\begin{cases}3x-1=0\\x-6=0\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{1}{3}\\x=6\end{cases}}}\)
vậy_
2x = 4
=> 2x = 22
=> x = 2
vậy_
43x = 64
=> 43x = 43
=> 3x = 3
=> x = 1
vậy_
![](https://rs.olm.vn/images/avt/0.png?1311)
a,\(\left(x^2+1\right)\left(81-x^2\right)=0\)
\(< =>\orbr{\begin{cases}x^2+1=0\\81-x^2=0\end{cases}}\)
\(< =>81=x^2< =>x=\pm9\)
b,\(\left(x-5\right)^5=32=2^5\)
\(< =>x-5=2< =>x=7\)
\(\left(x^2+1\right).\left(81-x^2\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x^2+1=0\\81-x^2=0\end{cases}\Leftrightarrow}\orbr{\begin{cases}x^2=-1\left(VL\right)\\x^2=81=\left(\pm9\right)^2\end{cases}}\)
\(\Leftrightarrow x=\pm9\)
Vậy \(x=\pm9\)
\(\left(x-5\right)^5=32=2^5\)
\(\Leftrightarrow x-5=2\)
\(\Leftrightarrow x=7\)
Vậy \(x=7\)
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(x+2).(x-1)=0
=>x+2=0 hoặc x-1=0
x+2=0 =>x=-2
x-1=0 =>x=1
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1 a x=4
b x=-4
c x=-7
d x=3
e x=10
g x=60
h x=36
i x=16
2a 1,2,3,4,5,6,7,8,9
b 1,2,3,4,5,6,7,8,9.........
c rỗng
3a 0
b 0
c10
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\(\dfrac{x-1}{2}-\dfrac{32}{x-1}=0\)
\(ĐKXĐ:x-1\ne0\Leftrightarrow x\ne1\)
\(\dfrac{x-1}{2}-\dfrac{32}{x-1}=0\)
\(\Leftrightarrow\dfrac{\left(x-1\right)\left(x-1\right)}{2\left(x-1\right)}-\dfrac{2.32}{\left(x-1\right)2}=0\)
\(\Rightarrow\left(x-1\right)\left(x-1\right)-64=0\)
\(\Leftrightarrow\left(x-1\right)^2-8^2=0\)
\(\Leftrightarrow\left(x-1-8\right)\left(x-1+8\right)=0\)
\(\Leftrightarrow\left(x-9\right)\left(x+7\right)=0\)
\(\Leftrightarrow x-9=0\) \(hoặc\) \(x+7=0\)
\(\Leftrightarrow x=9\) hoặc \(x=-7\)
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31x72 - 31x70 - 31 x 2 - 31
=31x(72 -70 -2 -1)
=31 x (-1)
= -31
những câu sau thì lam tương tự nha bạn ^_^