
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.


a) \(2.\left(x+\frac{2}{5}\right)+1\frac{1}{4}=\frac{11}{20}\)
\(2.\left(x+\frac{2}{5}\right)+\frac{5}{4}=\frac{11}{20}\)
\(2.\left(x+\frac{2}{5}\right)=\frac{-7}{10}\)
\(x+\frac{2}{5}=\frac{-7}{20}\)
\(x=\frac{-13}{20}\)
Vậy \(x=\frac{-13}{20}\)
b)\(x-1\frac{1}{8}-\frac{2}{3}x-\frac{5}{6}x=75\%\)
\(\left(x-\frac{2}{3}x-\frac{5}{6}x\right)-\frac{9}{8}=\frac{3}{4}\)
\(\frac{-1}{2}x-\frac{9}{8}=\frac{3}{4}\)
\(\frac{-1}{2}x=\frac{15}{8}\)
\(x=\frac{-15}{4}\)
Vậy \(x=\frac{-15}{4}\)


3x 2x+1 - 5 = 19
3.2x+1 = 19 + 5
3x2x+1 = 24
2x+1 = 24 :3
2x+1 = 8
2x+1 = 23
=>x+1 = 3
=> x=2

#)Giải :
\(\left(\frac{1}{2}\right)^{15}\div\left(\frac{1}{4}\right)^{20}=\left(\frac{1}{2}\right)^{15}\div\left(\frac{1}{2}\right)^{40}=\left(\frac{1}{2}\right)^{-25}\)

a, x-1:4/3+9/16=-5^(^laf mũ)2/4^2
x-1:4/3+9/16=25/16
x-1:4/3=25/16-9/16
x-1:4/3=1
x-1=1.4/3
x-1=4/3
x=4/3+1
x=7/3
kl:...................(hì tự viết nha mik lười viết)
b, 5/2x+2-31/2=1/6
5/2x+2=1/6+31/2
5/2x+2=16
5/2x=16-2
5/2x=14
x=14:5/2
x=28/5(vì 28 ko chia hết cho 5 nên mik viết như vậy)
*chúc bn học tốt nha* ^-^ *_*

\(x^4\cdot x^7\cdot...\cdot x^{100}\)
\(=x^{4+7+...+100}\)
\(=x^{52\cdot33}=x^{1716}\)
\(x^1\cdot x^2\cdot x^3\cdot...\cdot x^{2006}\)
Ta có : \(x^1\cdot x^2=x^{1+2}=x^3\)
Tương tự : \(x^1\cdot x^2\cdot x^3=x^{1+2+3}=x^6\)
Áp dụng vào bài toán :
\(x^1\cdot x^2\cdot x^3\cdot...\cdot x^{2006}=x^{1+2+3+...+2006}\)
\(\Rightarrow x^{1+2+3+...+2006}=x^{2013021}\)
\(\left(x-1\right)^4=2^4\Leftrightarrow\left[{}\begin{matrix}x-1=2\\x-1=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)
x4=16x4=16
⇔ [16=2416=(−2)4[16=2416=(−2)4
⇒x4=⇒x4= [24(−2)4[24(−2)4
⇒⇒ [x=2x=−2