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\(\left(x+1\right)^2+\left(x^2+1\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}\left(x+1\right)^2=0\\\left(x^2+1\right)=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x+1=0\\x^2+1=0\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=-1\\x^2=-1\end{cases}\Leftrightarrow}x=-1}\)
Vậy x=-1
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1) (X-6)x(2x - 6)=0
=> X - 6 = 0 => x = 0 + 6 = 6
=> 2x - 6 = 0 => 2x = 6 => X = 6 : 2 = 3
Vẫy x{6; 3}
2) 100:(x-7)=1
x-7 = 100:1
x-7 = 100
x = 100 + 7
x = 107
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tinh tong cua 11,10,9,8,7,6,5,..........,-37,-38
-675 nha ban
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3+2x-1=24-[16-(4-1)]
3+2x+1=24-(16-3)
3+2x+1=24-13
3+2x+1=11
2x+1=11-3
2x+1=8
2x+1=23
=> x+1=3
x=2
3+2\(^{x-1}\)=24-[16-3]
3+2\(^{x-1}\)=24-13=11
2\(^{x-1}\)=11-3=8=2\(^3\)
=>x-1=3
=>x=4
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Ta có : x(x - 1) - (x - 1)2 = 0
=> x2 - x - (x2 - 1) = 0
=> x2 - x - x2 +1 = 0
=> -x +1 = 0
=> -x = -1
=> x =1
( x - 1 )2 = 1 (x - 1)² =1 =) x - 1 = 1 x = 1 + 1 = 2