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99 + 1 = 100
9999 + 1 = 10000
999......9 + 1 = 1000.....0 ( dưới 1000....0 là " m chữ số 0 "
a, \(\left(4.2\right)^5:\left(2^3.\dfrac{1}{16}\right)=8^5:\left(2^3.\dfrac{1^4}{2^4}\right)=\left(2^3\right)^5:\dfrac{2^3.1^4}{2^4}=2^{15}:\dfrac{1}{2}=2^{15}.2=2^{16}\)
\(b,\dfrac{2^2.4.32}{2^2.2^5}=\dfrac{2^2.2^4.2^5}{2^2.2^5}=2^4=16\)
\(a,\dfrac{\left(4.2\right)^5}{2^3.\dfrac{1}{16}}=\dfrac{\left(2^3\right)^5}{2^3.2^{-4}}=\dfrac{2^{15}}{2^{-1}}=2^{16}\)
b,\(\dfrac{2^2.4.32}{2^2.2^5}=\dfrac{2^2.2^2.2^5}{2^2.2^5}=2^2=4\)
a) = (5:2)1234567 = (2,5)1234567
b) = (9:3)766676555 = 3766676555
Bài 3:
a) \(\left(x-\frac{1}{2}\right)^2=0\)
\(\Rightarrow x-\frac{1}{2}=0\)
\(\Rightarrow x=\frac{1}{2}\)
Vậy \(x=\frac{1}{2}\)
b) \(\left(x-2\right)^2=1\)
\(\Rightarrow x-2=\pm1\)
+) \(x-2=1\Rightarrow x=3\)
+) \(x-2=-1\Rightarrow x=1\)
Vậy \(x=3\) hoặc \(x=1\)
c) \(\left(2x-1\right)^3=-8\)
\(\Rightarrow\left(2x-1\right)^3=\left(-2\right)^3\)
\(\Rightarrow2x-1=-2\)
\(\Rightarrow2x=-1\)
\(\Rightarrow x=\frac{-1}{2}\)
Vạy \(x=\frac{-1}{2}\)
d) \(\left(x+\frac{1}{2}\right)^2=\frac{1}{16}\)
\(\Rightarrow\left(x+\frac{1}{2}\right)^2=\left(\frac{1}{4}\right)^2\)
\(\Rightarrow x+\frac{1}{2}=\frac{1}{4}\)
\(\Rightarrow x=\frac{-1}{4}\)
Vậy \(x=\frac{-1}{4}\)
Bài 6:
a: \(2^{27}=8^9\)
\(3^{18}=9^9\)
b: Vì \(8^9< 9^9\)
nên \(2^{27}< 3^{18}\)
99 +1 = 100 =102
tương tự
9999+1= 10000 = 104
999....9+1= 10....0 = 10x
Tks bạn