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Tìm x:
a,3(x-5)-x+5=0
=>3(x-5)-(x-5)=0
=>(x-5)(3-1)=0
=>(x-5).2=0
=>x-5=0
=>x=5
Vậy x=5.
a) \(\left(x^2-9\right) \left(x-7\right)=\left(x+3\right)\left(x^2+6\right)\)
\(\Leftrightarrow\)\(\left(x+3\right)\left(x-3\right)\left(x-7\right)-\left(x+3\right)\left(x^2+6\right)=0\)
\(\Leftrightarrow\)\(\left(x+3\right)\left(x^2-10x+21-x^2-6\right)=0\)
\(\Leftrightarrow\)\(\left(x+3\right)\left(-10x+15\right)=0\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x+3=0\\-10x+15=0\end{cases}}\)\(\Leftrightarrow\)\(\orbr{\begin{cases}x=-3\\x=1,5\end{cases}}\)
Vậy...
1
a) \(\left(3x+1\right)\left(3x-1\right)=9x^2-1\)
\(\left(x+5y\right)\left(x-5y\right)=x^2-25y\)
b) \(\left(x-3\right)\left(x^2+3x+9\right)=x^3-27\)
\(\left(x-5\right)\left(x^2+5x+25\right)=x^3-125\)
Bài 3:
a: \(\Leftrightarrow x^2+8x+16-x^2+1=16\)
=>8x+1=0
=>x=-1/8
b: \(\Leftrightarrow4x^2-4x+1+x^2+6x+9-5x^2+245=0\)
=>2x+255=0
=>x=-255/2
c: \(\Leftrightarrow x^3-6x^2+12x-8-x^3+64+6x^2+12x+6=49\)
=>24x+62=49
=>24x=-13
=>x=-13/24
d: =>x^3+8-x^3-2x=15
=>-2x=15-8=7
=>x=-7/2
a) \(\left(x-2\right)^2-\left(x-3\right)\left(x+3\right)=6\)
\(\Leftrightarrow x^2-4x+4-x^2+9-6=0\)
\(\Leftrightarrow-4x+7=0\Leftrightarrow x=\dfrac{7}{4}\)
b) \(4\left(x-3\right)^2-\left(2x-1\right)\left(2x+1\right)=10\)
\(\Leftrightarrow4\left(x^2-6x+9\right)-\left(4x^2-1\right)=10\)
\(\Leftrightarrow4x^2-24x+36-4x^2+1-10=0\)
\(\Leftrightarrow-24x+27=0\Leftrightarrow x=\dfrac{9}{8}\)
c) đề có sai ko vậy bạn :
\(\left(x-4\right)^2-\left(x+2\right)\left(x-2\right)=6\)
\(\Leftrightarrow\left(x^2-8x+16\right)-\left(x^2-4\right)=6\)
\(\Leftrightarrow x^2-8x+16-x^2+4-6=0\)
\(\Leftrightarrow-8x+14=0\Leftrightarrow x=\dfrac{7}{4}\)
d) \(9\left(x+1\right)^2-\left(3x-2\right)\left(3x+2\right)=10\)
\(\Leftrightarrow9\left(x^2+2x+1\right)-\left(9x^2-4\right)=10\)
\(\Leftrightarrow9x^2+18x+9-9x^2+4-10=0\)
\(\Leftrightarrow18x+3=0\Leftrightarrow x=\dfrac{1}{6}\)
a) ( x - 2 )2 - ( x - 3 )( x+ 3) = 6
( x2 - 4x + 4 ) - ( x2 - 9 ) = 6
x2 - 4x + 4 - x2 + 9 = 6
-4x + 13 = 6
-4x = -7
x = 7/4
X x 4 + 1 + 3 + 4 + 6 + 9 =
Ko bit x = ?