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\(A=\left[\frac{1\frac{11}{31}\cdot4\frac{3}{7}-\left(15-6\frac{1}{3}\cdot\frac{2}{19}\right)}{4\frac{5}{6}+\frac{1}{6}\left(12-5\frac{1}{3}\right)}\cdot\left(-1\frac{14}{93}\right)\right]\cdot\frac{31}{50}\)
\(A=\left[\frac{\frac{42}{31}\cdot\frac{31}{7}-\left(15-\frac{19}{3}\cdot\frac{2}{19}\right)}{4\frac{5}{6}+\frac{1}{6}\left(12-\frac{16}{3}\right)}\cdot\left(-\frac{107}{93}\right)\right]\cdot\frac{31}{50}\)
\(A=\left[\frac{6-\left(15-\frac{2}{3}\right)}{\frac{29}{6}+\frac{10}{9}}\cdot\left(-\frac{107}{93}\right)\right]\cdot\frac{31}{50}\)
\(A=\left[\frac{6-\frac{43}{3}}{\frac{107}{18}}\cdot\left(-\frac{107}{93}\right)\right]\cdot\frac{31}{50}\)
\(A=\left[\frac{-\frac{25}{3}}{\frac{107}{18}}\cdot\left(-\frac{107}{93}\right)\right]\cdot\frac{31}{50}\)
\(A=\frac{50}{31}\cdot\frac{31}{50}=1\)
a) \(25^3:5^2=5^6:5^2=5^4=625\)
b) \(\left(\frac{3}{7}\right)^{21}:\left(\frac{9}{49}\right)^6=\left(\frac{3}{7}\right)^{21}:\left(\frac{3}{7}\right)^{12}=\left(\frac{3}{7}\right)^9\)
c) \(3-\left(-\frac{6}{7}\right)^0+\left(\frac{1}{2}\right)^2:2=3-1+\frac{1}{8}=\frac{17}{8}\)
\(\left[\frac{\frac{25}{3}}{\frac{49}{6}}\cdot\left(-\frac{14}{93}\right)\right]\cdot\frac{31}{50}\)
\(=\left[\frac{25}{3}:\frac{49}{6}\cdot\left(-\frac{14}{93}\right)\right]\cdot\frac{31}{50}\)
\(=\frac{25}{3}\cdot\frac{6}{49}\cdot\frac{-14}{93}\cdot\frac{31}{50}\)
\(=\frac{25\cdot6\cdot-14\cdot31}{3\cdot49\cdot93\cdot50}\)
\(=\frac{5\cdot5\cdot2\cdot3\cdot-2\cdot7\cdot31}{3\cdot7\cdot7\cdot31\cdot3\cdot5\cdot5\cdot2}\)
\(=\frac{-2}{3\cdot7}=\frac{-2}{21}\)
Mình tính lại bằng máy tính rùi. Không sai đâu. Hứa đấy.