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Đặt là a, b nhá
\(a)\) \(7^{x-1}-2.7^{100}=5.7^{100}\)
\(\Leftrightarrow\)\(7^{x-1}=5.7^{100}+2.7^{100}\)
\(\Leftrightarrow\)\(7^{x-1}=7^{100}\left(5+2\right)\)
\(\Leftrightarrow\)\(7^{x-1}=7^{100}.7\)
\(\Leftrightarrow\)\(7^{x-1}=7^{101}\)
\(\Leftrightarrow\)\(x-1=101\)
\(\Leftrightarrow\)\(x=101+1\)
\(\Leftrightarrow\)\(x=102\)
Vậy \(x=102\)
\(b)\) \(5^{x-4}=25\)
\(\Leftrightarrow\)\(5^{x-4}=5^2\)
\(\Leftrightarrow\)\(x-4=2\)
\(\Leftrightarrow\)\(x=2+4\)
\(\Leftrightarrow\)\(x=6\)
Vậy \(x=6\)
Chúc bạn học tốt ~
\(7^{x-1}-2.7^{100}=5.7^{100}\)
\(\Rightarrow7^{x-1}=5.7^{100}+2.7^{100}\)
\(\Rightarrow7^{x-1}=7.7^{100}\)
\(\Rightarrow7^{x-1}=49^{100}\)
\(\Rightarrow7^{x-1}=7^{2^{100}}\)
\(\Rightarrow7^{x-1}=7^{200}\)
\(\Rightarrow x=201\)
Vậy x = 201
\(5^{x-4}=25\)
\(\Rightarrow5^{x-4}=5^2\)
\(\Rightarrow x=6\)
Vậy x = 6
\(\left(2^{100}.5+2^{100}.3\right):2^{101}\)
\(=2^{100}.8:2^{101}\)
\(=2^{100}.2^3:2^{101}\)
\(=2^{103}:2^{101}\)
\(=2^2\)
\(=4\)
\(3^5:3^3+2^2.2^3-14\)
\(=3^2+2^6-14\)
\(=9+64-14\)
\(=59\)
a, \(\frac{\left(2^3.5.7\right)\left(5^2.7^3\right)}{\left(2.5.7^2\right)^2}\)\(=\frac{2^3.5.7.5^2.7^3}{2^2.5^2.7^4}=\frac{2^3.5^3.7^4}{2^2.5^2.7^4}=10\)
b, \(\frac{4}{77}+\frac{4}{165}+\frac{4}{285}\)
\(=\frac{4}{7.11}+\frac{4}{11.15}+\frac{4}{15.19}\)
\(=\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{15}+\frac{1}{15}-\frac{1}{19}\)
\(=\frac{1}{7}-\frac{1}{19}\)
\(=\frac{19}{133}-\frac{7}{133}=\frac{12}{133}\)
Bài 2:
\(a,\left(x+\frac{2}{3}\right).\frac{-3}{5}+\frac{4}{7}=1\frac{4}{7}.x\)
\(\Rightarrow\frac{-3}{5}x+\frac{-2}{5}+\frac{4}{7}=\frac{11}{7}.y\)
\(\Rightarrow\frac{-3}{5}x+\frac{6}{35}=\frac{11}{7}.y\)
Từ đây làm nốt
b, \(\left|5x-2\right|\le0\)
\(\Rightarrow\left|5x\right|\le2\)( x \(\ge0\))
Mà không có số x nào nhân với 5 bé hơn hoặc bằng 2
\(\Rightarrow\)x không có giá trị thỏa mãn
c đề bài sai, chỉ tìm x chứ làm gì có y
d, \(\left(x-3\right).\left(2y+1\right)=7\)
TH1:
x - 3 = 1
x = 1 + 3
x = 4
2y + 1 = 7
2y = 7 - 1 = 6
y = 6 : 2 = 3
TH2:
x - 3 = 7
x = 7 + 3 = 10
2y + 1 = 1
2y = 1 - 1 = 0
y = 0 : 2 = 0
TH3:
x - 3 = -1
x = -1 + 3
x = 2
2y+ 1 = -7
2y = -7 - 1 = -8
y = (-8) : 2 = -4
TH4:
x - 3 = -7
x = -7 + 3
x = -4
2y + 1 = -1
2y = (-1) - 1
2y = -2
y = (-2) : 2 = -1
Vậy ......
Tìm số tự nhiên \(x\) , biết :
a) \(123-5\left(x+4\right)=38\)
b) \(\left(3.x-2^4\right).7^3=2.7^4\)
a) \(123-5\left(x+4\right)=38\)
\(5\left(x+4\right)=123-38\)
\(5\left(x+4\right)=85\)
\(x+4=85:5\)
\(x+4=17\)
\(x=17-4\)
\(x=13\)
Vậy \(x=13\).
b) \(\left(3x-2^4\right)\cdot7^3=2\cdot7^4\)
\(3x-16=2\cdot7^4:7^3\)
\(3x-16=2\cdot7\)
\(3x-16=14\)
\(3x=14+16\)
\(3x=30\)
\(x=30:3\)
\(x=10\)
Vậy \(x=10\).
a/ BSCNN (12, 25, 30) = 22.52.3 = 4.25.3 = 300
=> X=300
b/ (3x-24).73=2.73 <=> 3x-16=2.74:73
<=> 3x-16=2.7 => 3x-16=14 => 3x=30 => x=10
c/ /x-5/=16+2.(-3) <=> /x-5/=16-6 <=> /x-5/=10 => x-5=\(\pm\)10
=> x=15 và x=-5
a)\(\frac{3}{4}+\frac{1}{4}:x=-3\)
\(\frac{1}{4}:x=-3-\frac{3}{4}\)
\(\frac{1}{4}:x=\frac{-15}{4}\)
\(x=\frac{1}{4}:\frac{-15}{4}\)
\(x=\frac{-1}{15}\)
b) \(\frac{-5}{x}=\frac{20}{28}\)
\(\Rightarrow\)\(-5:x=\frac{20}{28}\)
\(x=-5:\frac{20}{28}\)
\(x=-7\)
c)\(\frac{2}{3}x-\frac{1}{2}=\frac{1}{10}\)
\(\frac{2}{3}x\) \(=\frac{1}{10}+\frac{1}{2}\)
\(\frac{2}{3}x\) \(=\frac{6}{10}\)
\(x\) \(=\frac{6}{10}:\frac{2}{3}\)
\(x\) \(=\frac{9}{10}\)
d)\(1\frac{2}{9}x+\frac{8}{3}=\frac{-2}{3}\)
\(1\frac{2}{9}x\) \(=\frac{-2}{3}-\frac{8}{3}\)
\(1\frac{2}{9}x\) \(=\frac{-10}{3}\)
\(x\) \(=\frac{-10}{3}:1\frac{2}{9}\)
\(x\) \(=\frac{-30}{11}\)
Câu Cuối)\(\frac{x}{2}-\frac{11}{5}=\frac{7}{8}.\frac{64}{49}\)
\(\Rightarrow\) \(x:2-\frac{11}{5}=\frac{7}{8}.\frac{64}{49}\)
\(x:2-\frac{11}{5}=\frac{448}{392}\)
\(x:2\) \(=\frac{448}{392}+\frac{11}{5}\)
\(x:2\) \(=\frac{117}{35}\)
\(x\) \(=\frac{117}{35}.2\)
\(x\) \(=\frac{234}{35}\)
Bạn cho mình 1 .
Chúc bạn học tốt .
đếch giúp!ai bảo câu hỏi của ngọc trả lời ko tử tế cơ!thằng nào ngu như mày thì thằng đó chết nhe răng giống mày!
\(\frac{1}{2}\cdot2^x+2^x\cdot2^2=2^8+2^5\)
\(2^x\left(\frac{1}{2}+4\right)=2^8+2^5\)
\(2^x\cdot\frac{9}{2}=288\)
\(2^x=64\)
\(2^x=2^6\)
\(x=6\)
\(9^x:3^x=3^7\)
\(3^{2x}:3^x=3^7\)
\(3^x=3^7\)
\(x=7\)
\(7^{x+2}+2\cdot7^{x-1}=345\)
\(7^x\cdot7^2+2\cdot7^x:7=345\)
\(7^x\left(7^2+\frac{2}{7}\right)=345\)
\(7^x\cdot\frac{345}{7}=345\)
\(7^x=7\)
\(x=1\)
a) 1/2.2^x + 2^x+2 = 256 + 32
1/2.2^x + 2^2.2^x=288
2^x(1/2+4)= 288
2^x.4,5=288
2^x= 288:4,5
2^x=64=2^6
x=6
1) \(x:\dfrac{2}{3}=150\)
\(\Leftrightarrow x=150.\dfrac{2}{3}\)
\(\Leftrightarrow x=100\).
2) \(\dfrac{35}{9}:x=\dfrac{35}{6}\)
\(\Leftrightarrow x=\dfrac{35}{9}:\dfrac{35}{6}\)
\(\Leftrightarrow x=\dfrac{2}{3}\).
3) \(\dfrac{49}{7}:x=\dfrac{49}{5}\)
\(\Leftrightarrow x=\dfrac{49}{7}:\dfrac{49}{5}\)
\(\Leftrightarrow x=\dfrac{5}{7}\).
4) \(1-\left\{5\dfrac{4}{9}+x-7\dfrac{7}{18}\right\}:15\dfrac{3}{5}=0\)
\(\Leftrightarrow1-\left\{\dfrac{49}{9}+x-\dfrac{133}{18}\right\}:\dfrac{78}{5}=0\)
\(\Leftrightarrow\left\{\dfrac{-35}{18}+x\right\}:\dfrac{78}{5}=1-0\)
\(\Rightarrow\dfrac{-35}{18}+x=1.\dfrac{78}{5}\)
\(\Leftrightarrow\dfrac{-35}{18}+x=\dfrac{78}{5}\)
\(\Rightarrow x=\dfrac{1579}{90}\).
Gọi a,b,c.. cho dễ nhé.Thớt vui tính quá, dấu phẩy cũng không viết hộ con dân =)))
a, \(x:\dfrac{2}{3}=150\)
\(\Leftrightarrow x=150.\dfrac{2}{3}\)
\(\Leftrightarrow x=100\)
Vậy...
b, \(\dfrac{35}{9}:x=\dfrac{35}{6}\)
\(\Leftrightarrow x=\dfrac{35}{9}:\dfrac{35}{6}\)
\(\Leftrightarrow x=\dfrac{2}{3}\)
Vậy...
c, \(\dfrac{49}{7}:x=\dfrac{49}{5}\)
\(\Leftrightarrow x=\dfrac{49}{7}:\dfrac{49}{5}\)
\(\Leftrightarrow x=\dfrac{5}{7}\) Vậy...
d, \(1-\left\{5\dfrac{4}{9}+x-7\dfrac{7}{18}\right\}:15\dfrac{3}{4}=0\)
\(\Leftrightarrow1-\left\{\dfrac{49}{9}+x-\dfrac{133}{18}\right\}:\dfrac{63}{4}=0\)
\(\Leftrightarrow1-\left\{x-\dfrac{35}{18}\right\}:\dfrac{63}{4}=0\)
\(\Leftrightarrow1-\left(\dfrac{\left(18x-35\right).4}{18.63}\right)=0\)
\(\Leftrightarrow1-\left(\dfrac{72x-140}{1134}\right)=0\)
\(\Leftrightarrow1-\dfrac{72x-140}{1134}=0\)
\(\Leftrightarrow\dfrac{1134-72x+140}{1134}=0\)
\(\Leftrightarrow1274-72x=0\)
\(\Leftrightarrow72x=1274\)
\(\Leftrightarrow x=\dfrac{637}{36}\)
Vậy...
492.75
=(72)2.75
=74.75
=79
42x-3=64
=> 42x-3=43
=> 2x-3=3
=> 2x=6
=> x=6:2
=> x=3
a)492.75=(72)2.75=74.75=79
b)42x-3=64
42x-3=43
=>2x-3=3
2x = 3 + 3
2x = 6
x = 3
Vậy x = 3