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a. \(3-\frac{2}{2x-1}=\frac{2}{3}+\frac{2}{6x-3}-\frac{3}{2}\)
\(3+\frac{3}{2}-\frac{2}{3}=\frac{2}{6x-3}+\frac{2}{2x-1}\)
\(\frac{23}{6}=\frac{2}{6x-3}+\frac{6}{6x-3}\)
\(\frac{23}{6}=\frac{8}{6x-3}\)\(\Rightarrow23.\left(6x-3\right)=48\)
\(6x-3=\frac{48}{23}\)
\(6x=\frac{48}{23}+3=\frac{117}{23}\)
\(x=\frac{117}{23}:6=\frac{117}{23}.\frac{1}{6}=\frac{39}{46}\)
b . \(\frac{1}{2x+3}+\frac{-2}{3}.\left(\frac{3}{4}-\frac{6}{5}\right)=\frac{5}{4x+6}\)
\(\frac{1}{2x+3}+\frac{-2}{3}.\frac{-9}{20}=\frac{5}{4x+6}\)
\(\frac{1}{2x+3}+\frac{3}{10}=\frac{5}{4x+6}\)
\(\frac{3}{10}=\frac{5}{4x+6}-\frac{1}{2x+3}\)\(=\frac{5}{4x+6}-\frac{2}{4x+6}\)
\(\frac{3}{10}=\frac{3}{4x+6}\)\(\Rightarrow3.\left(4x+6\right)=30\)
\(4x+6=30:3=10\)
\(4x=10-6=4\)
\(x=4:4=1\)
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a: \(P\left(x\right)+Q\left(x\right)=9x^3-6x^2+x-3\)
\(P\left(x\right)-Q\left(x\right)=-x^3-6x^2+13x-7\)
b: \(P\left(1\right)=4-6+7-5=-2+7-5=0\)
\(P\left(-2\right)=-32-24-14-5=-73\)
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a: \(P\left(x\right)+Q\left(x\right)=-2x^3-7x^2-2x+4\)
\(P\left(x\right)-Q\left(x\right)=10x^3-7x^2+8x-14\)
b: \(P\left(1\right)=4-7+3-5=-5\)
\(P\left(-1\right)=-4-7-3-5=-19\)
|x + 2| - 6x = 1
=> |x + 2| = 1+ 6x (đk : x ≥ -1/6)
=> x + 2 = 1 + 6x hoặc x + 2 = -1 - 6x
=> 5x = 1 hoặc 7x = -3
=> x = 1/5 (thỏa mãn) hoặc x = -3/7 (loại)
vậy x = 1/5
tính |x+2 |-6x=1
x=0,2
HT
:))